Official Quant thread for CAT 2013

MBA CAT 2024
29426
@vbhvgupta said:
The duration of a railway journey varies as the distance and inversely as the velocity; the velocity varies directly as the square root of the quantity of coal used per km, and inversely as the no of carriages in the train. In a journey of 50 KM in half an hour with 18 carriages, 100 kg of coal is required. how much coal will be consumed in a journey of 42 KM in 28 minutes with 16 carriages.
will it be 64??


duration = k*d/v

v= m*(q^1/2)/ no. of carriages

from data given,, k/m=1/3

also

28=k*42/v

42k/28 = m* (q^1/2)/16

use k/m=1/3 to find q=64
29427
@vbhvgupta said:
Q1
C?
29428
@albiesriram said:
10- 27?
11- sochna padega
12- circle
29429
29430
@heylady said:
C?
a
29431
@vbhvgupta said:
a
both are increasing...in option A
29432
@heylady said:
C?
I would rather go with b actually!

regards
scrabbler
29433
@Marchex said:
The numbers 1, 2,…….. n are written in the natural order. Numbers in odd places are struck off to form a new sequence. This process is continued till only one number is left.If n = 1997, the number left is(1) 1996 (2) 1988 (3) 512 (4) 1024If the number left is 512, the maximum possible value of n is(1) 1025 (2) 1023 (3) 513 (4) 1024
1-
@Marchex said:
The numbers 1, 2,…….. n are written in the natural order. Numbers in odd places are struck off to form a new sequence. This process is continued till only one number is left.If n = 1997, the number left is(1) 1996 (2) 1988 (3) 512 (4) 1024If the number left is 512, the maximum possible value of n is(1) 1025 (2) 1023 (3) 513 (4) 1024
1 - 1024
2 - 1025 as 1025 / 2 should >= 512 and not less..

Nice set..Hope m correct..
29434
Let T be the set of integers {2, 12, 22, 32 ..., 542, 552} and S be a subset of T such that the sum of no two elements of S is divisible by 3. The maximum possible number of elements in S is
29435
N= 1^1 × 2^2 × 3^6 × 4^12 × 5^20 ..... 25 terms. Find the highest power of 75 that can divide N.
29436
@amresh_maverick said:
N= 1^1 × 2^2 × 3^6 × 4^12 × 5^20 ..... 25 terms. Find the highest power of 75 that can divide N.
950??
29437
@albiesriram said:
for 1st
180-x+180-x+360-x+140=360
3x=500
x=500/3

now x=(n-2)180/n
put value of x here it gives n=27

for 3rd
x^2+y^2-2x=0 --------equation of circle so a)

for second kindly tell mewhat do u mean by rectangular cut then will do it surely :)
29438
@abhishek.2011 said:
for second kindly tell mewhat do u mean by rectangular cut then will do it surely
The new face formed by the cut is in the shape of a rectangle...

regards
scrabbler
29439
@amresh_maverick said:
Let T be the set of integers {2, 12, 22, 32 ..., 542, 552} and S be a subset of T such that the sum of no two elements of S is divisible by 3. The maximum possible number of elements in S is
numbers r of the form 3k ,3k+1 and 3k+2
3k terms =19
3k+2 terms =19
3k+1 terms = 18
now as sum of any two numbers shudnt b multiple of 3 so all 3k+2 terms + 1 3k term
so 20 number set
my take 20
29440
@amresh_maverick said:
N= 1^1 × 2^2 × 3^6 × 4^12 × 5^20 ..... 25 terms. Find the highest power of 75 that can divide N.
total power of 5 = 1900 so 1900/2=950??
29441
@@amresh_maverick said:N= 1^1 × 2^2 × 3^6 × 4^12 × 5^20 ..... 25 terms. Find the highest power of 75 that can divide N.is it 950???
29442
@amresh_maverick said:
N= 1^1 × 2^2 × 3^6 × 4^12 × 5^20 ..... 25 terms. Find the highest power of 75 that can divide N.
950????
29443
@KhannaiiM said:
g6 = g1/21 = 5400/21 = 1800/7
29444

Hi,

Need to solve this using allegation

In a zoo their are deers and ducks. 180 heads and 448 legs. How many deers are their ?
29445
@ananyboss 44 deers