@albiesriram said:
k = n/(100 - n)
n = 100k/(1 + k)
=> (1 + k) must divide 100 => it must be a factor of 100.
100 has 9 +ve factors. taking the corresponding -ve ones, = 9x2 = 18
@albiesriram said:
5) n/100-n to be integer => n>=50
=> first 4 options are only possible
let n = 100-k (=> k
=> 100-k/k = integer say m
=> 100 = (m+1)k
factors of 100 => values of k => 2,4,5,10,20,25
=> 6 values 😃
@Crysis said:5) n/100-n to be integer => n>=50=> first 4 options are only possiblelet n = 100-k (=> k=> 100-k/k = integer say m=> 100 = (m+1)kfactors of 100 => values of k => 2,4,5,10,20,25 => 6 values
99 101
98 102
96 104
95 105
90 110
75 125
80 120
50 150
0
i think only these values are feasible 100 is a factor of 100 but it is possible only for n=0 it doesnot have any other case so m baffled that it should be 17 values but as 17 is not given i marked 18
@albiesriram said:. But why Cant n=0 be also taken ?
0 is included in the 18 values. it's when k+1 = 1, (which is one of the factors of 100
@techgeek2050 said:k = n/(100 - n)n = 100k/(1 + k)=> (1 + k) must divide 100 => it must be a factor of 100.100 has 9 +ve factors. taking the corresponding -ve ones, = 9x2 = 18
Bhai , there will be 18 integers but i think we should also check n/100-n also for integrity 
@albiesriram said:Bhai , there will be 18 integers but i think we should also check n/100-n also for integrity @Subhashdec2 what say?
integrity...? what integrity check?
bhai i did not get u
@albiesriram said:Bhai , there will be 18 integers but i think we should also check n/100-n also for integrity
ur right bhai... but i guess it is already taken care of. what we need is , n must not be equal to 100
if it is equal to 100, then from
n = 100k/(1 + k)
we 'll get => k = k + 1, which is not possible.
@Subhashdec2 said:integrity...? what integrity check?bhai i did not get u
My bad. I mean we should also check if n/100-n is also an integer or not 
.
. @albiesriram said:My bad. I mean we should also check if n/100-n is also an integer or not .
that's what was assumed initially as k. an integer.
a and b are two alloys of argentum and brass prepared by mixing metals in proportion 7:2 and 7:11 respectively. If equal quantities of two alloys are melted to form a third alloy C, the proportion of argentum and brass in C will be?
@vbhvgupta said:a and b are two alloys of argentum and brass prepared by mixing metals in proportion 7:2 and 7:11 respectively. If equal quantities of two alloys are melted to form a third alloy C, the proportion of argentum and brass in C will be?
14+7 / 4+11=21:15=7:5
@vbhvgupta said:a and b are two alloys of argentum and brass prepared by mixing metals in proportion 7:2 and 7:11 respectively. If equal quantities of two alloys are melted to form a third alloy C, the proportion of argentum and brass in C will be?
7/9 + 7/18 : 2/9 +11/18 = 21/18 : 15 /18 => 7:5 ?
@albiesriram said:My bad. I mean we should also check if n/100-n is also an integer or not .
well i think we should have also taken one more constraint into consideration that is
n>=100-n
2n>=100
n>=50
n/100-n
100-n=x
n=100-x
since n>=50
x
100-x/x
100/x -1
factors of 100=9
9*2=18
remove factors >50
which is only n=100
and we are already not taking it into consideration
since n=0 we are taking and n=100 we are not taking(as mentioned in my earlier post)
so still it would be the same ans
@vbhvgupta said:a and b are two alloys of argentum and brass prepared by mixing metals in proportion 7:2 and 7:11 respectively. If equal quantities of two alloys are melted to form a third alloy C, the proportion of argentum and brass in C will be?
7v/9 + 7v/18 = 2mv
m=7:12
a:g= 7/12-7 = 7/5