Official Quant thread for CAT 2013

MBA CAT 2024
29326
@Buck.up 1205 ????
29327
@Marchex said:
Should be 4/5.

Take it as x. If we multiply it by (1-(-1/4)) = 5/4 we will get 5/4 x = 1.

regards
scrabbler
29328
@Buck.up said:
5 letter word to be constructed from MATHEMATICS,in how many words will E occur.
5490??
29329
Rs. 4,500 was distributed among Aman, Baman and Chaman. From the amount that they received Aman, Baman and Chaman spent Rs.110, Rs.120 and Rs.140 respectively. The amounts then left with Aman and Baman were in the ratio 3 : 4 and with Baman and Chaman were in the ratio 5 : 6. What amount (in Rs.) did Baman receive?
(a) 1520 (b) 1400 (c) 1600 (d) 1420
29330
@Buck.up said:
5 letter word to be constructed from MATHEMATICS,in how many words will E occur.
Options? I am getting some huge value...5370 ke aaspaas...heavy lunch having effect :D

regards
scrabbler
29331
@Marchex said:
Rs. 4,500 was distributed among Aman, Baman and Chaman. From the amount that they received Aman, Baman and Chaman spent Rs.110, Rs.120 and Rs.140 respectively. The amounts then left with Aman and Baman were in the ratio 3 : 4 and with Baman and Chaman were in the ratio 5 : 6. What amount (in Rs.) did Baman receive?(a) 1520 (b) 1400 (c) 1600 (d) 1420
1400? Trying orally...

Edit: 1400 + 120 = 1520 hoga.

Taking a break doston, too much lunch. Back later :)

regards
scrabbler
29332
@heylady said:
5490??
@Marchex said:
@Buck.up 1205 ????
@scrabbler said:
Options? I am getting some huge value...5370 ke aaspaas...heavy lunch having effect regardsscrabbler
OA=6990.
M M A A T T
H E I C S

when all are different = E _ _ _ _ = 7C4*5! = 120*35 = 4200
when two of them are identical = E _ _ _ _ = 3C1*6C2*5!/2! = 2700
when four of them are identical = E _ _ _ _ = 3C2*5!/2!*2! = 90
total = 4200+2700+90 = 6990
29333
@Marchex said:
Rs. 4,500 was distributed among Aman, Baman and Chaman. From the amount that they received Aman, Baman and Chaman spent Rs.110, Rs.120 and Rs.140 respectively. The amounts then left with Aman and Baman were in the ratio 3 : 4 and with Baman and Chaman were in the ratio 5 : 6. What amount (in Rs.) did Baman receive?(a) 1520 (b) 1400 (c) 1600 (d) 1420
1400.?
was gettin a decimal ans near this.
29334
@scrabbler said:
1400? Trying orally...regardsscrabbler
@Buck.up said:
1400.?was gettin a decimal ans near this.
a+b+c=4500
a-110,b-120,c-140

ratios are 3:4 and 5:6 means 15:20:24
So a-110 =15x
b-120 =20x
c-140 =24x

15x+110+20x+120+24x+140 =4500
59x+370 =4500
x=4130/59=70

so b=(70*20)+120 =1520
29335

Two points are chosen uniformly at random on the unit circle and joined to make a chord C1. This process is repeated 3 more times to get chords C2,C3,C4. The probability that no pair of chords intersect can be expressed as ab where a and b are coprime positive integers. What is the value of a+b?

29336
@Tusharrr said:
Two points are chosen uniformly at random on the unit circle and joined to make a chord C1. This process is repeated 3 more times to get chords C2,C3,C4. The probability that no pair of chords intersect can be expressed as ab where a and b are coprime positive integers. What is the value of a+b?
29337
@Marchex said:
4/5 imo
29338
@Marchex said:
There are five cities in a state and each of them is to be connected to exactly two other cities using telephone lines. In how many ways can this be done?(a) 12 (b) 24 (c) 36 (d) 9
@scrabbler said:
Double-counting...counted every case twice I suppose Poora cases list karna hi padega I suppose...too much effort :'(regardsscrabbler
We start of from a vertice say A
now to draw two lines from it, we have 4C2 = 6 cases

and for each pair of two lines that we select, we have 2 cases possible for the remaining vertices...
for e.g : AD, AE
now we have possible nest lines as DC/EB/BC or DB/EC/BC, no other combinations exist ( actually as soon as we decide on next 2 lines , the fifth line is automatically decided, the only case remaining)

So total cases = 6*2 = 12 cases....
Since these covers all vertices having two lines, it can be thought of as being begun by fixing any the vertices....


29339
@Buck.up said:
1400.?was gettin a decimal ans near this.
1520
29340
@Marchex said:
Rs. 4,500 was distributed among Aman, Baman and Chaman. From the amount that they received Aman, Baman and Chaman spent Rs.110, Rs.120 and Rs.140 respectively. The amounts then left with Aman and Baman were in the ratio 3 : 4 and with Baman and Chaman were in the ratio 5 : 6. What amount (in Rs.) did Baman receive?(a) 1520 (b) 1400 (c) 1600 (d) 1420
After money spent , the money left be a,b,c

a + b + c = 4130
3b/4 + b + 6b/5 = 4130

b = 1400

so before they spent, b' = b + 120 = 1520


29341
@Marchex said:
Five equi-spaced points labeled 1, 2, 3, 4, 5 are marked in the same order in clockwise direction on the circumference of a circle. An ant is moving on the circumference of this circle in the clockwise direction. If the ant is at an odd numbered point it shifts one point ahead and if it is at an even numbered point it shifts two points ahead. If the ant starts from point 5, then where would it be after 2010 such movements?(a) 1 (b) 3 (c) 5 (d) None of these
none of these . it will be point 2.
29342
@Marchex said:
Solve This
none of these. 2.5 should be the answer.
29343
@zuloo Ans is none of these and will be on point 4
29344
@Marchex said:
@zuloo Ans is none of these and will be on point 4
soluiton batana?. mera toh point 2 aa raha hai.
29345
@albiesriram said:
Here 8th is unsolved . OA for 7 is B solved by@Subhashdec2New set
bhai for question 8when x>3/2
4x=px-6
x=6/p-4
now it will lead to a real solution for all except 4
for x-3/2
2x+3+3-2x=px+6
px=0
now it will lead to a solution for all values except when p=0 because 0/0 is undefines
similarly when x-2x-3+3-2x=px+6
-4x=px+6
x=-6/p+4
it will lead to solutions for all values except -4
so the solution set for p=R-{4,-4,0}