@amresh_maverick said:A hemispherical roof is on a circular room, inner diameter of the roof is equal to the height of the room. If 48,510 cm3 air is inside the room, find the height of the room.
Don't know how to make the figure sir! Don't know how to make the figure sir!@amresh_maverick said:Two line segments AB and CD bisect each other. If their ends are joined to form a quadrilateral ADBC, then which of the following is(are) true? I. ˆ ADB = 90 ° II. AD = AC III. AD = BC
OA: III. AD = BC
@amresh_maverick said:A hemispherical roof is on a circular room, inner diameter of the roof is equal to the height of the room. If 48,510 cm3 air is inside the room, find the height of the room.
OA: 42
@amresh_maverick said:Two line segments AB and CD bisect each other. If their ends are joined to form a quadrilateral ADBC, then which of the following is(are) true? I. ˆ ADB = 90 ° II. AD = AC III. AD = BC
AD = BC ?
@ScareCrow28 said:Don't know how to make the figure sir!
srimaan mahoday , I am no sir
I was also unable due to the same issue . I took the fig as hemisphere on a circle. But this is not possible as the circle is a room with some height ?
what is a circle with some height ?
I was also unable due to the same issue . I took the fig as hemisphere on a circle. But this is not possible as the circle is a room with some height ?
what is a circle with some height ?
@amresh_maverick said:srimaan mahoday , I am no sirI was also unable due to the same issue . I took the fig as hemisphere on a circle. But this is not possible as the circle is a room with some height ?
But sir, circle to 2D hogaya..Question galat ho sakta hai?? 
Room to cubical ya spherical b maanlo chalo..
Room to cubical ya spherical b maanlo chalo..@ScareCrow28 said:But sir, circle to 2D hogaya..Question galat ho sakta hai?? Room to cubical ya spherical b maanlo chalo..
yep , the ans is given as a hemisphere mounted on a cylinder
PFA
PFA
@ravi6389 said:Q. 4 dice are thrown.In how many ways can a sum of 20 be obtained? for this question
the required number is the coefficient of x^20 in (x + x^2 + x^3 + ....+ x^6)^4
coeff of x^16 in (1 + x + x^2 + x^3 + ....+ x^5)^4
coefficeint of x^16 in
[(1 - x^6)^4][(1 - x)^(-4)]
= (1 - 4C1(x^6) + 4C2(x^12) - ....)(1 + 4C1x + 5C2x^2 + 6C3x^3 + ......)
19C16 - (4C1)(13C10) + (4C2)(7C4)
= 35 ways
Thirty six numbers are filled in the cells of a matrix as shown in the figure given below. Six numbers are chosen from the matrix such that no two numbers belong to the same row or the same column. In how many ways can the numbers be chosen?
Q 34
Q 35 36
@wovfactorAPS
@ravi6389 said:Q. 4 dice are thrown.In how many ways can a sum of 20 be obtained? for this question
this can also be thought in a different way.
max.sum=24
so taking complementary values for each dice i mean 6-a for a dice if a is the value on the dice
(6-a)+(6-b)+(6-c)+(6-d)=4
take 6-a=A and so on..
A+B+C+D=4
each of A B C D can take all values from 0-5
so total solutions are 7c3=35
this can also be thought in a different way.
max.sum=24
so taking complementary values for each dice i mean 6-a for a dice if a is the value on the dice
(6-a)+(6-b)+(6-c)+(6-d)=4
take 6-a=A and so on..
A+B+C+D=4
each of A B C D can take all values from 0-5
so total solutions are 7c3=35
Correct answer dude.thanks:)
@Subhashdec2 @pavimai said:A boat is to be rowed by 10 men; 5 on the left side and 5 on the right side. Of the 10 men, available two cannot row on the right side and three cannot row on the left side. In how many ways can the 10 men be arranged?
5c3 *5!*5!
5c3 *5!*5!
plz expliain dis 5c3....
@simplydevesh said:@Subhashdec2@pavimai said:A boat is to be rowed by 10 men; 5 on the left side and 5 on the right side. Of the 10 men, available two cannot row on the right side and three cannot row on the left side. In how many ways can the 10 men be arranged?5c3 *5!*5!plz expliain dis 5c3....
two cannot row on the right side >>>> they sit on left side
three cannot row on the left side >>>>> they sit on right side
total people selected till now = 5
rem people =5
if we select 2 people from rem people = 5c2 for arrangement on right side or 5c3 people on left side
hope u got it
three cannot row on the left side >>>>> they sit on right side
total people selected till now = 5
rem people =5
if we select 2 people from rem people = 5c2 for arrangement on right side or 5c3 people on left side
hope u got it
Q42 43