as said did it orally cost of 1 apple 5 rscost of 1 orange 4 rs12*5+9*4=96for doing it orally just seek the solutions of 3x+4y=32 in mind
True (and well spotted)....but a much quicker method, not even requiring x and y to be computed, would be to just recognise that what we need (9 oranges and 12 apples) is 3/4th of the first given equation (12 oranges and 16 apples cost rupees 128) and hence the cost is straightaway 3/4 of 128 i.e. 96 without even using the second piece of information given. regards scrabbler
again on ur path scrabbler bhai did it orally too_/3 it will bejoin centre of hexagon with vertices ,now every length will be same as 1,from centre join the side ,half the side will come as _/3/2 as angle subtended is 60so _/3
That is assuming a regular hexagon. Else, 2 tak jaa sakta hai :P
Waise in case of a regular hexagon, if you think of the side-waale triangles as 30-30-120 triangles, straightaway the ratios of the sides turn out to be 1 : 1 : rt3. Or if you have calculated the diagonals of a reg hex before, then the answer is already there :)
At time t=0 s, the radius of a circle is equal to 15 cm. The radius of the circle increases at a rate of 0.5 cm/s. The rate of change of area at t=20 s is equal to mπ cm^2/s, where m is a positive integer. What is the value of m?
At time t=0 s, the radius of a circle is equal to 15 cm. The radius of the circle increases at a rate of 0.5 cm/s. The rate of change of area at t=20 s is equal to mπ cm^2/s, where m is a positive integer. What is the value of m?
2 > c did orally,not sure though... see if cosec^2 and sec^2 are roots then product of roots divided by sum of roots is 1. this is true for c only.
I guess 1 bhi orally ho sakta hai if we consider an equilateral triangle (since no CBD or NOTA must be true for any triangle) Edit: Will be 1/4. For equi, 2rt3 + 2rt3 + 2rt3 = lambda(2rt3)^3 = lambda(24rt3) so lambda = 1/4.
At time t=0 s, the radius of a circle is equal to 15 cm. The radius of the circle increases at a rate of 0.5 cm/s. The rate of change of area at t=20 s is equal to mπ cm^2/s, where m is a positive integer. What is the value of m?
At time t=0 s, the radius of a circle is equal to 15 cm. The radius of the circle increases at a rate of 0.5 cm/s. The rate of change of area at t=20 s is equal to mπ cm^2/s, where m is a positive integer. What is the value of m?
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dekha nhi!
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