Official Quant thread for CAT 2013

MBA CAT 2024
28545
@The_Loser said:
side of the largest triangle that can be inserted in hexagon of side 1 cm.?
rt 3.......

P.S. - Chats must be done in Shoutbox thread plz...keep this thread clean..
28546
@albiesriram said:
OA for Last problem set is C n D . Last one of the day....
OA for this one is A,A,B.
28547
@anantn said:
@scrabbler scrabbler sir, after meeting hearing you out at, i started doing all my questions orally, and discovered that there is absolutely no need for any quant question to be written down, dunno why i didnt do the samw in cat, would have saved tons of time...
Perhaps not all, but certainly 40-50% even in a CAT paper can be done orally (or with a line of writing) if you figure out how (and that comes mostly through practice!). On the actual exam day though, even if you manage to do just 3-4 questions in that way, it will give you a huge advantage over most of the competition... :)

Aur....sir mat bol

regards
scrabbler
28548
@The_Loser said:
side of the largest triangle that can be inserted in hexagon of side 1 cm.?
Just less than 2. i.e. 1.99999

regards
scrabbler
28549
@scrabbler said:
Just less than 2. i.e. 1.99999regardsscrabbler
Cant understand. how?

28550
The perimeter of the base of the cylinder is 6.28 cm. A part of this cylinder has been cut off. What is the volume of the remaining cylinder, as shown in the diagram? ( ห†? = 3.14)
28551
@Tusharrr Let AD=x.
Then, by the cos formula,
x^2+25-2(5)xcos 30 = x^2 + 625 - 2(25)xcos30
which on solving gives
x=10์ฐฝห†ลก3
hence AD^2=(x)^2=300
28552
@amresh_maverick said:
The perimeter of the base of the cylinder is 6.28 cm. A part of this cylinder has been cut off. What is the volume of the remaining cylinder, as shown in the diagram? ( ห†? = 3.14)
66 ? remaining is basically 7/8th of the original cylinder.
28553
@albiesriram said:
Cant understand. how?
It doesn't say regular hexagon. If we judiciously choose our hexagon with all sides 1 we can fit in a triangle of almost 2...

regards
scrabbler
28554

Fine.

Also it doesn't mention which side, the largest or smallest like wise.. so i thought they are expecting a equilateral triangle's sides as an answer .
28555
@albiesriram said:
66 ? remaining is basically 7/8th of the original cylinder.
if the cylinder is not cut , the whole volume would be 18.84 ??
28556
@amresh_maverick said:
The perimeter of the base of the cylinder is 6.28 cm. A part of this cylinder has been cut off. What is the volume of the remaining cylinder, as shown in the diagram? (โˆ = 3.14)

15.7?
r=1cm
the volume of the region above the height of 4cm= 1/2*(โˆr^2*2)=3.14
the volume of the region of height of 4cm= โˆr^2*4=12.56
total volume=15.7
OA ?
28557
@amresh_maverick said:
if the cylinder is not cut , the whole volume would be 18.84 ??
oh ,yes.. r =1, h= 6 hence total volume would be 22/7 *1*1*6

7/8th of it would be 22 *6/8 =16.5 ?
28558
@amresh_maverick said:
The perimeter of the base of the cylinder is 6.28 cm. A part of this cylinder has been cut off. What is the volume of the remaining cylinder, as shown in the diagram? ( ห†? 15.70 cm^3...
28559
@amresh_maverick said:
The perimeter of the base of the cylinder is 6.28 cm. A part of this cylinder has been cut off. What is the volume of the remaining cylinder, as shown in the diagram? (โˆ = 3.14)
@Zedai said:
15.7?r=1cmthe volume of the region above the height of 4cm= 1/2*(โˆr^2*2)=3.14the volume of the region of height of 4cm= โˆr^2*4=12.56total volume=15.7OA ?
OA: 15.7

The corner of a cube has been cut by the plane passing through the mid-point of the three edges meeting at that corner. If the edge of the cube is of 2 cm length, then the volume of the pyramid thus cut off is
28560
@scrabbler
mere liye to aap sir hi hue na( if you remember we have met in the real world)
28561
@albiesriram said:
Fine.Also it doesn't mention which side, the largest or smallest like wise.. so i thought they are expecting a equilateral triangle's sides as an answer .
No I am talking of an equilateral triangle only....the hexagon is flexible. Since it says "side" in each case we have to assume that the hexagon has all sides equal and the triangle too has all sides equal.

Edit: Attaching figure

regards
scrabbler
28562
@anantn said:
@scrabblermere liye to aap sir hi hue na( if you remember we have met in the real world)
That makes no difference bhai....here I am scrabbler and nothing more (nor less!)

regards
scrabbler
28563
@amresh_maverick said:
OA: 15.7The corner of a cube has been cut by the plane passing through the mid-point of the three edges meeting at that corner. If the edge of the cube is of 2 cm length, then the volume of the pyramid thus cut off is
1/6 I suppose...I seem to remember that such a figure becomes 1/6th of the volume of the cuboid but don't remember why :(

regards
scrabbler
28564
@scrabbler said:
1/6 I suppose...I seem to remember that such a figure becomes 1/6th of the volume of the cuboid but don't remember why regardsscrabbler
correct , do not possess such "powers"

after visualizing, the pyramid would have a triangular base which would be an equilateral triangle with side =_/2 , calculated height and used the formula for vol of pyramid to get 1/6