@scrabbler said:2013/2025 I guess....?x must be something negative...regardsscrabbler
don't have the OA sir. is it only through trial and error?
@techgeek2050
Ramesh bought a total of 6 fruits (apples and oranges) from the market. He found that he required one orange less to extract the same quantity of juice as extracted from apples. If Ramesh had used the same number of apples and oranges to make the blend, then which of the following correctly represents the percentage of apple juice in the blend?
@scrabbler said:I get real distinct...took a couple of examples T&Error;@albiesriram regardsscrabbler
I too have tried the same method and hence according to those values,calculated the Disciminant and as per that I have answered as imaginary but it went wrong.:-(
@psk.becks
i am talking about this part.
Ramesh bought a total of 6 fruits (apples and oranges) from the market. He found that he required one orange less to extract the same quantity of juice as extracted from apples. If Ramesh had used the same number of apples and oranges to make the blend, then which of the following correctly represents the percentage of apple juice in the blend?
you have used (n-1)O = nA
@techgeek2050 said:don't have the OA sir. is it only through trial and error?
No Sir please :(
What I did was, 2013 lies between 44^2 and 45^2. now, if I consider x as a positive number, if is is 44.xx, then the max possible case for x[x] would be 44.9999... x 44 = 1980 while if I increase x to 45 then it jumps to 2025. So 2013 not possible.
After a little thought I realised that for a negative x it could happen as [-44.xx] would be -45. And the product would lie between 1980 and 2025 and would therefore at some value be 2013. Now consider this x as -44.xx and so [x] = -45. So if x[x] = 2013 then we have x = 2013/ (-45) so x/[x] = 2013/(-45)*(-45) = 2013/2025.
regards
scrabbler
What I did was, 2013 lies between 44^2 and 45^2. now, if I consider x as a positive number, if is is 44.xx, then the max possible case for x[x] would be 44.9999... x 44 = 1980 while if I increase x to 45 then it jumps to 2025. So 2013 not possible.
After a little thought I realised that for a negative x it could happen as [-44.xx] would be -45. And the product would lie between 1980 and 2025 and would therefore at some value be 2013. Now consider this x as -44.xx and so [x] = -45. So if x[x] = 2013 then we have x = 2013/ (-45) so x/[x] = 2013/(-45)*(-45) = 2013/2025.
regards
scrabbler
@albiesriram said:
6479?
Seems to be an pattern of n^2 + (n-1)
1 + 0
4+1
9+2
16+3 and so on
regards
scrabbler
@techgeek2050
okkkkkk
@scrabbler said:No Sir please What I did was, 2013 lies between 44^2 and 45^2. now, if I consider x as a positive number, if is is 44.xx, then the max possible case for x[x] would be 44.9999... x 44 = 1980 while if I increase x to 45 then it jumps to 2025. So 2013 not possible.After a little thought I realised that for a negative x it could happen as [-44.xx] would be -45. And the product would lie between 1980 and 2025 and would therefore at some value be 2013. Now consider this x as -44.xx and so [x] = -45. So if x[x] = 2013 then we have x = 2013/ (-45) so x/[x] = 2013/(-45)*(-45) = 2013/2025.regardsscrabbler
@albiesriram said:
N = 2?
f(n) = log(2002)(11)^2 + log(2002)(13)^2 + log(2002)(14)^2
= 2(log(11)/log(2002) + log(13)/log(2002) + log(14)/log(2002))
= 2(log(11*13*14)/log(2002)) = 2(log(2002)/log(2002)) = 2
