@DarkHorse25 - nopes
@saket.soni05 said:Find the remainder when 22012 is divided by 2012.OPTIONS 1)16 2)64 3)1024 4)503pls post the approach...ty in advance
16 ?
2012 = 2^2*503
2^2012 mod 2012
2^2012 mod 4 = 0
E(503) = 502
2^502k mod 503 = 1
2^4 mod 503 = 16 mod 503 = 16
@techgeek2050 said:f(n) is a function for all non-negative integers n, such that f(f(f(n))) + f(n) = 2n + 4 and f(0) = 1.Find f(2013).
well as the rhs is a polynomial with degree 1 so fn must be a polynomial with degree 1
let f(x)=ax+b
f(f(f(x)))= (a^3+a)x + a^2*b + ab + 2b = 2x+4
so a^3+a = 2
a=1
a^2*b + ab + 2b=4
put a=1 b comes as 1
so polynomial is
y=x+1
put x=2013
y=2014
@Tusharrr said:ABC is a right angled triangle with ˆ ABC=90 ˆ˜and side lengths AB=24 and BC=7. A semicircle is inscribed in ABC, such that the diameter is on ACand it is tangent to AB and BC. If the radius of the semicircle is an improper fraction of the form a/b, where a and b are positive, coprime integers, what is the value of a+b?
24-r/24=r/7
r comes as 168/31
sum 199
A 80 kg climber is standing horizontally on a perfectly vertical cliff face as shown in the picture. The climber is 1.8 m tall and is attached by a 2 m long rope fastened around their middle to a point on the cliff above them. What is the normal force the cliff face exerts on the climber in Newtons?
Details and assumptions
The climber is not moving.The acceleration of gravity is ˆ'9.8 m/s2.The center of mass of the climber is at the point where the rope meets their body.
@Tusharrr said:A 80 kg climber is standing horizontally on a perfectly vertical cliff face as shown in the picture. The climber is 1.8 m tall and is attached by a 2 m long rope fastened around their middle to a point on the cliff above them. What is the normal force the cliff face exerts on the climber in Newtons?Details and assumptionsThe climber is not moving.The acceleration of gravity is ˆ'9.8 m/s2.The center of mass of the climber is at the point where the rope meets their body.
396.40 ?
assume Tension T in rope..
find theta @
so Tsin@ = mg
find T
find theta @
so Tsin@ = mg
find T
then Tcos@ = N
find N
