How many two digit prime numbers are there in base-9? I am getting 20 .Please confirm . I dont have OA
@Asfakul said:How many two digit prime numbers are there in base-9? I am getting 20 .Please confirm . I dont have OA
Smallest 2 digit no in base 9 = 9 ( in base 10 )
Highest 2 digit no in base 9 = 80 ( in base 10 )
Prime nos from 9 to 80 are 18
18 ?
@ScareCrow28 said:Smallest 2 digit no in base 9 = 9 ( in base 10 ) Highest 2 digit no in base 9 = 80 ( in base 10 )Prime nos from 9 to 80 are 1818 ?
yes. right . please explain how did you find the 2 limits
The given diag shows road map of a city. The lines indicate roads but there are no roads through park. All roads are either parallel or perpendiculur to each other. Peter wants to go from X to Y travllng min distance. In hw mny ways cn he make the jrny??
[p.s-- all blocks in diag are actually squares. Sorry fr the distorted fig 
]
]a)55 b)100 c)166 d)220 e)110
@Asfakul said:yes. right . please explain how did you find the 2 limits
Smallest 2 digit no in base 9 = 10 = 9 in base 10
Largest 2 digit no in base 9 = 88 = 80 in base 10
Hope you got it :)
@ScareCrow28 said:Smallest 2 digit no in base 9 = 10 = 9 in base 10 Largest 2 digit no in base 9 = 88 = 80 in base 10Hope you got it
Okay I think I have 
. Largest number is 88 because in base 9 largest digit is 8 . so 88 .
. Largest number is 88 because in base 9 largest digit is 8 . so 88 . @Asfakul said:How many two digit prime numbers are there in base-9? I am getting 20 .Please confirm . I dont have OA
smallest two digit number -> 9
largest -> 9^2 - 1 = 80
so 18 primes i guess
@Asfakul said:Okay I think I have . Largest number is 88 because in base 9 largest digit is 8 . so 88 .
largest k digit number in any base n is always n^k - 1 😃
@meow14 said:The given diag shows road map of a city. The lines indicate roads but there are no roads through park. All roads are either parallel or perpendiculur to each other. Peter wants to go from X to Y travllng min distance. In hw mny ways cn he make the jrny??[p.s-- all blocks in diag are actually squares. Sorry fr the distorted fig ]a)55 b)100 c)166 d)220 e)110
110
210-10*10
total no of ways 10C4 . the no of wrong ways 5C2 * 5C2. 10C4-5C2*5C2=110
In how many ways can 6 identical rings be worn in 4 fingers of one hand if any no. of rings can be worn in one finger??
a.6^4 b.4^6 c.4!*6! d.84 e.196
@DarkHorse25 said:total no of ways 10C4 . the no of wrong ways 5C2 * 5C2. 10C4-5C2*5C2=110
why 10c4??
@meow14 said:In how many ways can 6 identical rings be worn in 4 fingers of one hand if any no. of rings can be worn in one finger??a.6^4 b.4^6 c.4!*6! d.84 e.196
84?
@meow14 said:84??In how many ways can 6 identical rings be worn in 4 fingers of one hand if any no. of rings can be worn in one finger??a.6^4 b.4^6 c.4!*6! d.84 e.196
@meow14 said:In how many ways can 6 identical rings be worn in 4 fingers of one hand if any no. of rings can be worn in one finger??a.6^4 b.4^6 c.4!*6! d.84 e.196
84 ?
9c3 = 84
@meow14 if u consider the park as 2*2 grid. then no of ways 10C4. but all the ways through the middle point of park are wrong . so we are subtracting 5c2 * 5c2.