@ScareCrow28 said:But, when x --> 0 then y/x is an increasing function, so we can't say that if we put x=1 that will give y/x as maximum
but u r not considering the eqn. i think the ans will be 2(sqrt6-1)
@ScareCrow28 said:I + II + III + IV= 120 I + 2II + 3III +4IV = 227Minimise (II + III + IV) OR Maximise I Also, II + 2III + 3IV = 107Put, II = 0WE get, III = 1 and IV = 35Hence minimum number of students playing at least 2 games = 0 + 1 + 35 = 36 ?..
i guess there is a small calculation error in 2nd equation.
but nevertheless, i got the concepts cleared. 
@ChirpiBird said:approach??i simply used the formula, area of regular octagon = 2a^2 (1+rt2)the figure will form a regular octagon of side 43/99a =43/99correct me if i am wrong.
but didnt use the octagon formula simply used algebric x-y eqn and the ans will be 73/99
@DarkHorse25 said:but u r not considering the eqn. i think the ans will be 2(sqrt6-1)
It's nowhere mentioned that x is an integer. Put, x= 0.01 and your answer will change.
@samratroy_1990 said:My question
86/99?
x + y + 43/99 = 1
x + y = 56/99
x^2 + y^2 = (43/99)^2
(x + y)^2 = x^2 + y^2 + 2xy
xy = 1287/99^2*2
area of octagon = 1 - 4/2(xy) = 1 - 2(1287/99^2*2) = 86/99...
@dreamz007 said:PROVIDE SOLUTION FOR THE SUM no. "30" !!! :GIVEN IN THE LINK : http://snag.gy/4ryF9.jpg
let them make a chair/day , b ,c
a+b+c = 8
amar works for x days and rest tow for y days
ax + (b+c)y = 80
take a =5 , b+c =3 x =10
take a =6 , b+c =2 x =10
in any case OA x =10
a+b+c = 8
amar works for x days and rest tow for y days
ax + (b+c)y = 80
take a =5 , b+c =3 x =10
take a =6 , b+c =2 x =10
in any case OA x =10
@DarkHorse25 said:but didnt use the octagon formula simply used algebric x-y eqn and the ans will be 73/99
okk.... but whichever way u do... answer should be same na. i'm getting in the range of .89-.91 ... that's why i asked. :mg:
anyway, let others try ... :)
anyway, let others try ... :)
@ChirpiBird said:okk.... but whichever way u do... answer should be same na. i'm getting in the range of .89-.91 ... that's why i asked. anyway, let others try ...
your answer is for the maximum case. max will be .89.. for the solution look at @mailtoankit 's post
@techgeek2050 said:i guess there is a small calculation error in 2nd equation.but nevertheless, i got the concepts cleared.
@ChirpiBird said:approach??i simply used the formula, area of regular octagon = 2a^2 (1+rt2)the figure will form a regular octagon of side 43/99a =43/99correct me if i am wrong.
even if use the formula of regular octagon its coming .9xxx
@
@DarkHorse25 said:but u r not considering the eqn. i think the ans will be 2(sqrt6-1)
Yes , the answer comes out to be 2(sqrt6-1) acc to me
@ScareCrow28 said:It's nowhere mentioned that x is an integer. Put, x= 0.01 and your answer will change.
the question is not about integer its abt x-1=0 bcoz any square can have min value of zero only . if u minimize (x-1)^2 hence maximize (y+2)^2 and maximizing the overall y/x.
@DarkHorse25 said:even if use the formula of regular octagon its coming .9xxx
yea... .91 without approximation.
.89 if you take approx of some values.
.89 if you take approx of some values.
@iLoveTorres said:your answer is for the maximum case. max will be .89.. for the solution look at @mailtoankit 's post
i got his method. :)
but max nhi h wo... area toh area h. there's no question of max-minimum! :mg:
but max nhi h wo... area toh area h. there's no question of max-minimum! :mg:
@DarkHorse25 said:the question is not about integer its abt x-1=0 bcoz any square can have min value of zero only . if u minimize (x-1)^2 hence maximize (y+2)^2 and maximizing the overall y/x.
Why don't you put x=0.01 and check the value of y/x and compare your answer!@ChirpiBird said:yea... .91 without approximation. .87 if you take approx of some values.i got his method. but max nhi h wo... area toh area h. there's no question of max-minimum!
86/99 be the ans
@ScareCrow28 said:Why don't you put x=0.01 and check the value of y/x and compare your answer!
hmm getting bigger ans..
@ChirpiBird said:yea... .91 without approximation. .87 if you take approx of some values.i got his method. but max nhi h wo... area toh area h. there's no question of max-minimum!
look if you consider it a regular octagon toh you can straight away do this 1-4*(1/2)*(13/99)*(43/99)
(99^2-1112)/99^2=9801-1112/9801=9689/9801~.98 how are you getting .91?
The point is since you are considering regular octagon your area will be maximum
(99^2-1112)/99^2=9801-1112/9801=9689/9801~.98 how are you getting .91?
The point is since you are considering regular octagon your area will be maximum
HELP!!!!
If the vowels are given by the symbols !,@,#,$ and % respctvly, then the message 2$%8!5@ will be
1) YOU VASE 2)YOU SAVE 3)YIU SAFE 4)YIU SAVE 5)YIU VASE
@meow14 said:HELP!!!!If the vowels are given by the symbols !,@,#,$ and % respctvly, then the message 2$%8!5@ will be1) YOU VASE 2)YOU SAVE 3)YIU SAFE 4)YIU SAVE 5)YIU VASE
2)YOU SAVE