@Dexian said:pehle sabko 1 de diya....... 3x+y+z=35....ab x=1.... y+z=33.......... 33x=2......... y+z=30...... 30and so on...sum from 3 to 33.......
aur agar aisa kuch hota
3x+2y+z+a=120?...
i hope aise aate ni honge...:D
@amresh_maverick said:1> 3x +y +z=40 where x ,y,z are +ve integers , no of sol ?2> no distinct rectangles having integral sides such that perimeter is an integer less than 100 cm
1- 700?
@amresh_maverick said:1> 3x +y +z=40 where x ,y,z are +ve integers , no of sol ?2> no distinct rectangles having integral sides such that perimeter is an integer less than 100 cm
OA :
1> 234
2> 600
koi madad karo in question 2
1> 234
2> 600
koi madad karo in question 2
@amresh_maverick said:1> 3x +y +z=40 where x ,y,z are +ve integers , no of sol ?
3x + y + z = 40
x = 1.....y + z = 37.....so 36 solutions
x = 2....y + z = 34...so 33 solutions
so 36 + 33 + 30 + 27 + 24 + 21 + 18 + 15 + 12 + 9 + 6 + 3 = 234 ?
@Subhashdec2 said:aur agar aisa kuch hota3x+2y+z+a=120?...i hope aise aate ni honge...
no idea.........
@amresh_maverick said:OA :1> 2342> 600koi madad karo in question 2
for the first one i m getting 198 which is 234-36....
ek sol kam hai.... aisa kyun...
kuchh prakash daliye plzzz
ek sol kam hai.... aisa kyun...
kuchh prakash daliye plzzz
@Dexian said:for the first one i m getting 198 which is 234-36....ek sol kam hai.... aisa kyun...kuchh prakash daliye plzzz
36 waale kyon nahi liye ?
@mailtoankit said:36 waale kyon nahi liye ?
pehle sabko 1 de diya.......
3x+y+z=35....
ab x=1.... y+z=33.......... 33
x=2......... y+z=30...... 30
and so on...
sum from 3 to 33.......
3x+y+z=35....
ab x=1.... y+z=33.......... 33
x=2......... y+z=30...... 30
and so on...
sum from 3 to 33.......
@Dexian said:pehle sabko 1 de diya....... 3x+y+z=35....ab x=1.... y+z=33.......... 33x=2......... y+z=30...... 30and so on...sum from 3 to 33.......
second time to bhai x=0 se shuru kar skte ho
x ko 1 to de chuke ho pehle
@ChirpiBird said:please post the approach.
recalculated..its 66..
15 O - 1
10M 5A - 1
14O 1M ,13O 2M ,..............., 5O 10M = 10
14O 1A,13O 1A,...................,10O 5A = 5
we can visualize and count for rest as the possibilities will keep on increasing for o =13,12..9 and then decrease after some values as O =4,3,2,1
what can be a shorter approach frnds???
15 O - 1
10M 5A - 1
14O 1M ,13O 2M ,..............., 5O 10M = 10
14O 1A,13O 1A,...................,10O 5A = 5
we can visualize and count for rest as the possibilities will keep on increasing for o =13,12..9 and then decrease after some values as O =4,3,2,1
what can be a shorter approach frnds???
@Subhashdec2 said:second time to bhai x=0 se shuru kar skte hox ko 1 to de chuke ho pehle
arey correct ..........thanks..
no distinct rectangles having integral sides such that perimeter is an integer less than 100 cm
I stuck here Plz help
Let us take perimeter to be 98
L + B = 49
1 48
2 47
and so on total sol =24
No take perimeter = 96
L + B = 48
1 47
2 46
........
.......
24 24
and so on total sol =24
@scrabbler help plz , how to proceed
I stuck here Plz help
Let us take perimeter to be 98
L + B = 49
1 48
2 47
and so on total sol =24
No take perimeter = 96
L + B = 48
1 47
2 46
........
.......
24 24
and so on total sol =24
@scrabbler help plz , how to proceed
@amresh_maverick said:no distinct rectangles having integral sides such that perimeter is an integer less than 100 cm I stuck here Plz helpLet us take perimeter to be 98L + B = 491 482 47 and so on total sol =24No take perimeter = 96L + B = 481 472 46...............24 24and so on total sol =24@scrabbler help plz , how to proceed
why are u not taking L=48 and B=1
i mean that should be a whole different rectangle than L=1 and B=48
also u cannot take L and B to be 24
since that would be a square.
1> How many 3's will be there in a book having 700 pages ?
2> 5 couples in a party .how many ways 4 persons can be seated on a table of 4 chairs such that no two husband wife are on the table ?
@amresh_maverick said:no distinct rectangles having integral sides such that perimeter is an integer less than 100 cm I stuck here Plz helpLet us take perimeter to be 98L + B = 491 482 47 and so on total sol =24No take perimeter = 96L + B = 481 472 46...............24 24and so on total sol =24@scrabbler help plz , how to proceed
is it 1176?
@amresh_maverick said:1> How many 3's will be there in a book having 700 pages ?2> 5 couples in a party .how many ways 4 persons can be seated on a table of 4 chairs such that no two husband wife are on the table ?
1) 20*6+120=240
@techgeek2050 said:is it 1176?
actually according to me it should be 1176-24=1152
24 squares will b there in between
but he says its 600..:D
@Subhashdec2 said:why are u not taking L=48 and B=1i mean that should be a whole different rectangle than L=1 and B=48also u cannot take L and B to be 24since that would be a square.
all squares are rectangles
L=1 , B=48 and B=1 , L=48 but we have to find no of distinct rectangles
L=1 , B=48 and B=1 , L=48 but we have to find no of distinct rectangles
@amresh_maverick said:no distinct rectangles having integral sides such that perimeter is an integer less than 100 cm I stuck here Plz helpLet us take perimeter to be 98L + B = 491 482 47 and so on total sol =24No take perimeter = 96L + B = 481 472 46...............24 24and so on total sol =24@scrabbler help plz , how to proceed
2(l+b) l+b
so ,l+b+k = 50 where k is any natural num
so no. of ways = 49C2 = 1176
No. of distinct rec = 1176 - 24 = 1152 ?? not sure...
