In a right circular cone of radius 4cm and height 10cm, largest cube is inscribed whose base rests at base of the cone. A sphere is then inserted between top of cube and the vertex of cone. What can be the maximum radius of the sphere?Team BV--Pratik Gauri
aprox. near 1.5 cm?? options would be helpful to eliminate and use..
approach ? I dunt know the answer Team BV--Pratik Gauri
the side of the cube came out to be 40/9 cm which is the diameter of the cone in which sphere in inscribed, next sphere is like an inscribed circle in the triangle of the cone.... found the inradius of the triangle...
What is the probability that a path from (0,0) to (8,6) pass through (5,4), assuming that all paths move along grid lines and that movement must be either the positive x or the positive y direction?
What is the probability that a path from (0,0) to (8,6) pass through (5,4), assuming that all paths move along grid lines and that movement must be either the positive x or the positive y direction?
What is the probability that a path from (0,0) to (8,6) pass through (5,4), assuming that all paths move along grid lines and that movement must be either the positive x or the positive y direction?
Approach: Total ways to reach from 0,0 to 8,6 = 14!/8!*6!
No. of ways to reach 0,0 to 5,4 and then to 8,6 = 9!/5!*4! X 5!/3!*2!
what i mean to say is thisif one of a,b,c>=10let a = a' + 10 , the equation becomesa' + b + c + k = 6similarly for b and c, a + b' + c + k = 6 , and a + b + c' + k = 6for each solution = 9C3so total = 3*9C3 ways are there wherein one of a,b,c is >=10 , so that is what should be subracted. P.S - bhai don't call me sir.. m just a noob.
my brain not working in this particular problem, i would try understanding and getting back to you, would tag you here if i am able to do so...
In a right circular cone of radius 4cm and height 10cm, largest cube is inscribed whose base rests at base of the cone. A sphere is then inserted between top of cube and the vertex of cone. What can be the maximum radius of the sphere?Team BV--Pratik Gauri
around 1.5 , exactly getting 100/9*1/(2+root(29)) ??
the side of the cube came out to be 40/9 cm which is the diameter of the cone in which sphere in inscribed, next sphere is like an inscribed circle in the triangle of the cone.... found the inradius of the triangle...
How can it be 40/9? 3D figure hai...will be less... regards scrabbler
What is the probability that a path from (0,0) to (8,6) pass through (5,4), assuming that all paths move along grid lines and that movement must be either the positive x or the positive y direction?
sirjee , itna visualisation mujhse nei hota,,, maine toh triangle main square ghusa ke kar diya...
Wohi to...instead of quad with sides x and x it will be a quad with sides x and xrt2 (the horizontal one). Bahut painful number aata hai... regards scrabbler
Wohi to...instead of quad with sides x and x it will be a quad with sides x and xrt2 (the horizontal one). Bahut painful number aata hai...regardsscrabbler
isn't it fine if we consider a cross section of 3D figure and solve it... like in ths case , sabse middle wala cross section with max area ?
What is the probability that a path from (0,0) to (8,6) pass through (5,4), assuming that all paths move along grid lines and that movement must be either the positive x or the positive y direction?
maine to aajtak 3D mein film bhi nahi dekhiHow many integers b/w 1 and 10000 have the sum of their digits equal to 18 ?PS: @bodhi_vriksha sir ur method to solve above type of q's got over my head , bouncer
There would be one 2 digit no ie. 99
coming to 3 digit nos .. abc --> a+b+c=18
a' +b+c=17 --> C(19,2) solutions... subtract cases when b or c >9