k r
1 1
1-2 2
2 3
2-3 4
3 3
>3 2
yaar 3/2 chor ke saare condition kahin na kahin set ho jaa rahe hain
@scrabbler said:Then the answer is what I said earlier? 3/2? Assuming that is the only change...regardsscrabbler
Share your approach for this problem.:)
Team BV - Vineet
@bodhi_vriksha said:Share your approach for this problem.Team BV - Vineet
Graphical, just plotted the mod....hardly 1 min solution...can't draw ab...in office :(
regards
scrabbler
regards
scrabbler
@bodhi_vriksha said:Good job Amresh and Estallar12.Try this one now...The equation |z-1| - |z-2| + |z-4| = k has exactly r real solutions for some real k. Then which among the following relations between k and r can not be true?(a) k/r = 3/5 (b) k = r (c) k/r = 3/2 (d) k/r = 5/3 (e) k = r-1Team BV - Vineet
m getting option (a) and (d) not satisfying..
is anyway graph is w-shaped ?
@Buck.up said:In a multinational company, the employee ID is a three-digit number (first digit is non-zero). However, no two employees can have IDs that are identical when written in reverse order (123 and 321 are identical and hence only one of them can exist). What is the maximum number of employees that can use this coding system?450,495,540 ?
There are a total of 720 3 digit numbers possible with distinct digits a and c and which do not end in 0. .
now let the no be abc.. possible arrangements are
abc
acb
bac
bca
cab
cba
Now we can take 3 out of these 6 arrangements .. Hence 720*3/6= 360 :)
Rest 90 can be used .. Hence --> 360+2*90=540 :)
Team BV--Pratik Gauri
@bodhi_vriksha said:How did you solve it Estallar?Team BV - Vineet
Plotting the Graph for the same. It turns out to be a Zigzag line. Also,we have three points of z from modulus - 1, 2 and 4. Using them, 3/2 straightaway gets out! :splat:
@Buck.up said:In a multinational company, the employee ID is a three-digit number (first digit is non-zero). However, no two employees can have IDs that are identical when written in reverse order (123 and 321 are identical and hence only one of them can exist). What is the maximum number of employees that can use this coding system?450,495,540 ?
So 810/2 + 90 = 495?
Edit: See Estallar's solution below. Too lazy to retype.
regards
scrabbler
@bodhi_vriksha said:There are a total of 900 3 digit numbers possible .now let the no be abc.. possible arrangements areabc acbbacbcacabcba Now we can take 3 out of these 6 arrangements .. Hence 900*3/6= 450 Team BV--Pratik Gauri
Haven't you missed out on numbers of the form aba and aaa too ? :roll:
rnishant231
option a =.8 w shaped graph ke x(1,2) mein ye ratio aa jayega
option d = 1.66 w shaped graph ke last interval (>3) mein aa jayega
@Buck.up said:In a multinational company, the employee ID is a three-digit number (first digit is non-zero). However, no two employees can have IDs that are identical when written in reverse order (123 and 321 are identical and hence only one of them can exist). What is the maximum number of employees that can use this coding system?450,495,540 ?
Number like 101, 121, 212 etc => 10*9 = 90 such numbers will appear only once as they are palindromic!
Also, removing numbers having ZERO at the end. => 90 such numbers.
So, [900 - 90 - 90]/2 + 90 + 90 = 360 + 180 = 540 such numbers!
@Estallar12 said:Haven't you missed out on numbers of the form aba ?
Yes .. :)
These 6 arrangements are for nos which have distinct a and c and which end in 0 ..
So we have 720 such numbers ..
So 720 *3/6=360
Now rest remaining nos can be used as they cant be twisted to get identical nos ..
Hence 360+2*90=540 :)
Team BV--Pratik Gauri
@Buck.up said:In a multinational company, the employee ID is a three-digit number (first digit is non-zero). However, no two employees can have IDs that are identical when written in reverse order (123 and 321 are identical and hence only one of them can exist). What is the maximum number of employees that can use this coding system?450,495,540 ?
total 3 digit nos = 900
excluding nos ending with zero = 900-(9*10) = 810
all these nos will have a reverse id, so excluding them = 810/2 = 405
but all numbers ending with zero won't have any reverse id..
so adding them Oa = 495 
@scrabbler said:Graphical, just plotted the mod....hardly 1 min solution...can't draw ab...in office regardsscrabbler
Do post your solution, when you are at home because how you solved it is important and not the answer itself. :)
Till now i can only see one right solution - the one provided by psk.becks
Team BV - Vineet
@bodhi_vriksha said:There are a total of 900 3 digit numbers possible .now let the no be abc.. possible arrangements areabc acbbacbcacabcba Now we can take 3 out of these 6 arrangements .. Hence 900*3/6= 450 Team BV--Pratik Gauri
@scrabbler said:Out of 900, the cases where the first and last digit are different must be divided by 2.So 810/2 + 90 = 495?regardsscrabbler
Total number of 3 digit numbers is 900.
Number of symmetrical 3 digit number is 90. These 90 IDs will not have corresponding number when written in reverse order.
Also, numbers ending with 0 will not have corresponding 3 digit number when written in reverse order. Number of such numbers=90
Rest 900-90-90=720 can be divided in 2 groups of 360 numbers of which every number in 1 group have a corresponding number in other group.Hence only 360 IDs.
Total IDs=360+90+90=540
@Estallar12 @rnishant231 This is the solution. Is there anything wrong ?
@Buck.up said:Total number of 3 digit numbers is 900.
Rest 900-90-90=720 can be divided in 2 groups of 360 numbers of which every number in 1 group have a corresponding number in other group.Hence only 360 IDs.Total IDs=360+90+90=540@Estallar12@rnishant231 This is the solution. Is there anything wrong ?
Perfect it is.!!
aba and ab0 were the two possibilities to be removed before dividing by 2. 
:)
:)@Buck.up said:Total number of 3 digit numbers is 900.Number of symmetrical 3 digit number is 90. These 90 IDs will not have corresponding number when written in reverse order.Also, numbers ending with 0 will not have corresponding 3 digit number when written in reverse order. Number of such numbers=90Rest 900-90-90=720 can be divided in 2 groups of 360 numbers of which every number in 1 group have a corresponding number in other group.Hence only 360 IDs.Total IDs=360+90+90=540@Estallar12@rnishant231 This is the solution. Is there anything wrong ?
Sahi hai yeh to yaar...
Missed to consider symmetrical numbers as exclusion..
@Estallar12 said:Perfect it is.!! aba and ab0 were the two possibilities to be removed before dividing by 2.
Note : aba also includes cases of aaa which u had mentioned seperately .. So I have taken aba cases into account and aaa are automatically taken care of ..edited sol :)
Team BV--Pratik Gauri
@Estallar12 said:Perfect it is.!! aba and ab0 were the two possibilities to be removed before dividing by 2.
__/\__ kaisa rha cmat??Phhod diya??
@Buck.up said:In a multinational company, the employee ID is a three-digit number (first digit is non-zero). However, no two employees can have IDs that are identical when written in reverse order (123 and 321 are identical and hence only one of them can exist). What is the maximum number of employees that can use this coding system?450,495,540 ?
540
@bodhi_vriksha said:Do post your solution, when you are at home because how you solved it is important and not the answer itself. Till now i can only see one right solution - the one provided by psk.becksTeam BV - Vineet
Uska is same as mine? 3/2? :o Confused
regards
scrabbler
regards
scrabbler