A dice is rolled six times. One, two, three, four, five and six appears on consecutive throws of dices. How many ways are possible of having 1 before 6?
1) 120
2) 360
3) 240
4) 280
@Exodia said:In an examination, the maximum marks for each of the three papers is 50 each. The maximum marks for the fourth paper is 100. Find the number of ways in which a student can score a total of 150 marks in aggregate1) 3,30,8502) 2,33,5513) 1105514) None of these
NOT?
guys please solve this question:
Study the following information carefully and answer the questions given below:
1. A, B, C, D, E and F are six members in a family in which there are two married couples.
2. D is brother of F. Both D and F are lighter than B.
3. B is the mother of D and lighter than E.
4. C, a lady is neither the heaviest nor the lightest in the family.
5. E is lighter than C.
6. The grandmother is heaviest in the family.
Q1. How many male members are there in the family?
a) Data inadequate
b) 2
c) 4
d) 3
e) None of these
Q2. How is E related to F?
a) Grandmother
b) Brother
c) Father
d) Data inadequate
e) None of these
Q3. How is C related to D?
a) Sister
b) Grandmother
c) Mother
d) Cousin
e) None of these
Q4. Which of the following is a married couple?
a) AD
b) BC
c) AB
d) BE
e) None of these
Q5. Which among the following will be in the second place, if all the members in the family are arranged in descending order of their weight?
a) D
b) A
c) C
d) Data inadequate
e) None of these
1. A, B, C, D, E and F are six members in a family in which there are two married couples.
2. D is brother of F. Both D and F are lighter than B.
3. B is the mother of D and lighter than E.
4. C, a lady is neither the heaviest nor the lightest in the family.
5. E is lighter than C.
6. The grandmother is heaviest in the family.
Q1. How many male members are there in the family?
a) Data inadequate
b) 2
c) 4
d) 3
e) None of these
Q2. How is E related to F?
a) Grandmother
b) Brother
c) Father
d) Data inadequate
e) None of these
Q3. How is C related to D?
a) Sister
b) Grandmother
c) Mother
d) Cousin
e) None of these
Q4. Which of the following is a married couple?
a) AD
b) BC
c) AB
d) BE
e) None of these
Q5. Which among the following will be in the second place, if all the members in the family are arranged in descending order of their weight?
a) D
b) A
c) C
d) Data inadequate
e) None of these
Q2
@Exodia said:A dice is rolled six times. One, two, three, four, five and six appears on consecutive throws of dices. How many ways are possible of having 1 before 6?1) 1202) 3603) 2404) 280
360 ?
@Exodia said:A dice is rolled six times. One, two, three, four, five and six appears on consecutive throws of dices. How many ways are possible of having 1 before 6?1) 1202) 3603) 2404) 280
120?
@Exodia said:A dice is rolled six times. One, two, three, four, five and six appears on consecutive throws of dices. How many ways are possible of having 1 before 6?1) 1202) 3603) 2404) 280
360? In exactly half of the arrangements 1 fill precede 6.
@vbhvgupta said:explain?
750 items at 60p = total cost = 450...
now at 600 items, he realizes profit of 40 % on the whole..
so 600 * S / 450 = 1.4
S = 1.05
now since he was able to sell only 630 items..
thus SP/CP = 630 * 1.05 / 450 = 1.47
thus profit = 47 %
@vbhvgupta said:explain?
he spends 750*.6=450 rupees
Then if he has to fix a SP based on the assumption that he will be able to sell only 600 then
450*1.4=630
SP of each article=630/600
Now he sells 630 articles so he gets 630*630/600
To find the profit
(630*630/600-450)/450*100=47%
Then if he has to fix a SP based on the assumption that he will be able to sell only 600 then
450*1.4=630
SP of each article=630/600
Now he sells 630 articles so he gets 630*630/600
To find the profit
(630*630/600-450)/450*100=47%
@vbhvgupta said:Q2
22,000 is the no of units he would give so he would have to manufacture 22000/.88=25000
Now by selling 22,000 at 7.5 he would earn 165000
But by manufacturing 25000 and he wants to earn a profit of 20% so 25000*1.2x=165000
x=rs 5.5/-
Now by selling 22,000 at 7.5 he would earn 165000
But by manufacturing 25000 and he wants to earn a profit of 20% so 25000*1.2x=165000
x=rs 5.5/-
@Subhashdec2 said:C aa rha h sabse close...
@iLoveTorres said:Two trains A & B start frm stations X & y towards each other.B leaves station Y half an hour aftr train A leaves station X.two hrs aftr train A has strtd,the dist between the trains A & B is 19/30th of the dist between stations X & y.how much time would it take each train (A & B) to cover the distance X to Y,if train A reaches half an hr ltr to its dest as compared to B
let the distance be d,speed be x and y
19d/30 = d-(2x+1.5y)
2x+1.5y=11d/30
also
d-x/x = d/y
putting value of d from above
49+45y/x =60x/y +45
let y/x =t
it gives 45t^2 +4t -60
t =y/x= 10/9
cheers!!!!
@nupurshrinet said:guys please solve this question:Study the following information carefully and answer the questions given below:1. A, B, C, D, E and F are six members in a family in which there are two married couples.2. D is brother of F. Both D and F are lighter than B.3. B is the mother of D and lighter than E.4. C, a lady is neither the heaviest nor the lightest in the family.5. E is lighter than C.6. The grandmother is heaviest in the family.Q1. How many male members are there in the family?a) Data inadequateb) 2c) 4d) 3e) None of theseQ2. How is E related to F?a) Grandmotherb) Brotherc) Fatherd) Data inadequatee) None of theseQ3. How is C related to D?a) Sisterb) Grandmotherc) Motherd) Cousine) None of theseQ4. Which of the following is a married couple?a) ADb) BCc) ABd) BEe) None of theseQ5. Which among the following will be in the second place, if all the members in the family are arranged in descending order of their weight?a) Db) Ac) Cd) Data inadequatee) None of these
@Exodia said:In an examination, the maximum marks for each of the three papers is 50 each. The maximum marks for the fourth paper is 100. Find the number of ways in which a student can score a total of 150 marks in aggregate1) 3,30,8502) 2,33,5513) 1105514) None of these
(50-a)+(50-b)+(50-c)+(100-d)= 150,
a+b+c+d = 100 = > 103c 3 none of the above?
The answer is not yet over this will contain values such as (51,x,y,z)= invalid. we have to exclude those cases.
so consider when
(51+a)+b+c+d= 100 or a+b+c+d = 49 or 52 c3 cases for a so
in total , 3 * 52 C3 cases we have to exclude. a and b or c cannot be simultaneously greAter than 50. and d alone cannot be greater than 100. so no other exclusions.
Hence OA should be
103C3 - 3*52C3
@Exodia said:A dice is rolled six times. One, two, three, four, five and six appears on consecutive throws of dices. How many ways are possible of having 1 before 6?1) 1202) 3603) 2404) 280
6c2*4! = 360
A mixture of milk and water in the ratio of 8:7. Another mixture of milk and water in the ratio of 5:9. In what ratio should we mix these two, if you need a mixture of milk and water in the ratio of 1:1?
Copied from CGL Thread
@ScareCrow28 said:A mixture of milk and water in the ratio of 8:7. Another mixture of milk and water in the ratio of 5:9. In what ratio should we mix these two, if you need a mixture of milk and water in the ratio of 1:1?Copied from CGL Thread
4:1 sorry, sleepy
edit @ScareCrow28 32+5 = 37
28+9 = 37
pls help me figure out where am i going wrong?