here's my approach, if there are any mistakes do point then out.
Given: |x-y|
When x-y=0 ==> x=y you would not get an integer solution to the first equation.
when x-y=1 you would get y=-3,2
when x-y=2 you would get y=-4,3,1
Similarly |x-y|=|x-(-y)|=|-x+y| so you would get 5 values for x as well. hence 10
@albiesriram said:
8.6 ?
Total distance = 35*2 + 45*2= 160 km
3 equal distances => 160/3 km each =x (say)
Litres = x/16 + x/24 + x/16 = 8.6 litres
@iLoveTorres said:A car which was driven in fog passed a man walking at 3 km/hr in the same direction. He could see the car for 4 min & upto a distance of 100 m.what was the speed of the car.
( x-3) = (1/10)/ (4/60) = 1.5+3 =4.5
@albiesriram said:
total distance = 2*35+2*45=160
Aditi will cover three equal distances (160/3) each with 30, 40, 50 km/hr
=> 160/3*16 +160/3*24 +160/3*16 =80/9=8.89
@mohitjain said:thoda explain kardo
Orally kiya tha, using 30-60-90 and equilateral triangles...figure would be painful to draw (am in office)...how to explain...:(
regards
scrabbler
regards
scrabbler
@albiesriram said:
Approx 112.
Y train will reach at C in 60/50=6/5 hrs
It will wait for 15 min=1/4 hrs
A total of time 6/5+1/4=29/20 hrs
In 29/20 hrs, train X will cover 29/20*70=101.5 km.
so from there, train x would cover {(120-101.5)/120}*70=10.8 km more before it will meet train Y.
=> distance from A = 101.5 +10.8=112.3 km
@scrabbler said:Orally kiya tha, using 30-60-90 and equilateral triangles...figure would be painful to draw (am in office)...how to explain...regardsscrabbler
k..do tel wen u r free
@albiesriram said:
50000(1+2/25)^2=50000 *27*27/25*25 = 58320
4 years SI=58320 *r /25
Paresh paid =3/4 *58320(1+r/25)
50000(27/25)^6=79343.7
79343.7-3/4 *58320(1+r/25)=18982.51
r=9.5