@Dexian said:2X*(8+2X)=24...... where x is the radius of circle...in that kite wala sum....is it correct???
😞
The area of the kite is half the product of its diagonals. 1/2 (2r )(2r+ 8)= 24
so the radius =2
KI = 2 _/2 (isosceles right triangle) and KE = _/2^2 +10^2 = 2 _/26 . The product is
so the radius =2
KI = 2 _/2 (isosceles right triangle) and KE = _/2^2 +10^2 = 2 _/26 . The product is
8 _/13
@albiesriram said:The area of the kite is half the product of its diagonals. 1/2 (2r )(2r+ 8)= 24so the radius =2 KI = 2 _/2 (isosceles right triangle) and KE = _/2^2 +10^2 = 2 _/26 . The product is 8 _/13
U r one big geometry BANK.....
yeah thoda difficult hai atleast for me 
.
Mods are gonna ban me for extensive use of bandwidth..@albiesriram said:yeah thoda difficult hai atleast for me .
(rt5 - 1) /2
Note that the inner radius is r then the inner chord is r*rt3. Hence distance from centre is r/2. But this is dist from centre of big circle too (radius 2r) so can use Pyth to get the length off the full chord. Then minus and....(too lazy to do)
regards
scrabbler
Note that the inner radius is r then the inner chord is r*rt3. Hence distance from centre is r/2. But this is dist from centre of big circle too (radius 2r) so can use Pyth to get the length off the full chord. Then minus and....(too lazy to do)
regards
scrabbler
€Ž10 men & 8 women ca complete a work in 20 day working together. In how many days 8 men & 10 women can do same work?
@Estallar12 said:€Ž10 men & 8 women ca complete a work in 20 day working together. In how many days 8 men & 10 women can do same work?
1600/164 days ??
PS: nice ques, good to see you back in action :)
PS: nice ques, good to see you back in action :)
the weight of an iron bucket increases by 33.33% when filled with water to 50% of its capacity .which of these may be 50% of weight of the bucket when it is filled with water (assume weight of bucket and its capacity in kg to be integers )
7
6
5
8
@raopradeep said:the weight of an iron bucket increases by 33.33% when filled with water to 50% of its capacity .which of these may be 50% of weight of the bucket when it is filled with water (assume weight of bucket and its capacity in kg to be integers )7658
Here, W/2 = IB/3
For W/2 to be an integer, W can be 2, 4, 6, 8 ...
=> IB = 3, 6, 9, 12, ...
So, IB + C = 5, 10, 15, 20 ...
Thus, it should be a multiple of 5.
Hence, Option C.
@Estallar12 said:€Ž10 men & 8 women ca complete a work in 20 day working together. In how many days 8 men & 10 women can do same work?
1000/49 ? 
@raopradeep said:the weight of an iron bucket increases by 33.33% when filled with water to 50% of its capacity .which of these may be 50% of weight of the bucket when it is filled with water (assume weight of bucket and its capacity in kg to be integers )7658
0.5*w(1+2/3)=5w/6. If w is an integer, the required ans = 5 kg
Team BV - Vineet
@Estallar12 said:€Ž10 men & 8 women ca complete a work in 20 day working together. In how many days 8 men & 10 women can do same work?
No relation is given regarding capacity of man and woman...
answer can be 20 or may be 24 also .... :)
answer can be 20 or may be 24 also .... :)
@albiesriram said:yeah thoda difficult hai atleast for me .
If the triangle is of side length a, then x(x+y) = (a/2)^2 (use property of intersecting chords)
Also, y= 2*Inradius*sin60 = a/2 =>x=(root5 -1)a/4 => x/y = (root5 -1)/2
Team BV - Vineet
@Estallar12 said:€Ž10 men & 8 women ca complete a work in 20 day working together. In how many days 8 men & 10 women can do same work?
Between 16 and 25 days, assuming (a) all men equal to each other, all women equal to each other and (b) everyone has a non-negative efficiency.
Long time! Howdy...
regards
scrabbler
Long time! Howdy...
regards
scrabbler
@Estallar12 said:€Ž10 men & 8 women ca complete a work in 20 day working together. In how many days 8 men & 10 women can do same work?
Given each gender group has the same efficiency and one man alone can do a job in m days while one women alone can do the job in w days, then m/10 + w/8=20.
Also, m/8 + w/10 = d => d=16+(9m/200) and d=25-(9w/160).
Vary the value of m or w to get the number of days.
Note: d=16 has an implication that men are completely lazy (do not work at all per unit time). d =25 has similar implications for women :)
Team BV - Vineet
Solve this one..
Team BV - Vineet
@raopradeep Let weight of bucket=x
Weight off 50% water (1/3)x
Weight of 100% water (2/3)x
New weight = (2/3+1)x=(5/3)x
Half the weight is (5/6)x
if we put x=6 we get 5kg.
Weight off 50% water (1/3)x
Weight of 100% water (2/3)x
New weight = (2/3+1)x=(5/3)x
Half the weight is (5/6)x
if we put x=6 we get 5kg.