In a regular octagon1.how many pairs of parallel diagonals are there? 1. 4 2. 8 3. 12 4. 162. if there is a regular polygon of 20 sides, how many diagonals originate from one vertex?1.17 2. 18 3. 19 4. 20p.s. second question ke liye approach plz
This one is a nice ques:A pencil, eraser and notebook together cost Rs 100. the notebook cost more than two pencils. three pencils cost more than four erasers and three erasers cost more than one notebook. Answer the questions given that cost are positive, non-zero, integers.1) The cost of pencil isa) 27 b) 26 c) 28 d) data insufficient2) if u paid the shopkeeper Rs 210 for 2 notebooks, 3 pencils and 1 eraser, how many change would he returna) 3 b) 5 c) 7 d) data insufficient
This one is a nice ques:A pencil, eraser and notebook together cost Rs 100. the notebook cost more than two pencils. three pencils cost more than four erasers and three erasers cost more than one notebook. Answer the questions given that cost are positive, non-zero, integers.1) The cost of pencil isa) 27 b) 26 c) 28 d) data insufficient
a) P=27 N(min)=55 E=18
it doesn't satisfy the 3rd quation(3E>N)
u cannt increase N as it will decrease E and again 3rd equation
b)P=26 N(min)=53 E=21 EDIT: it satisfy the 3rd quation(3E>N)
This one is a nice ques:A pencil, eraser and notebook together cost Rs 100. the notebook cost more than two pencils. three pencils cost more than four erasers and three erasers cost more than one notebook. Answer the questions given that cost are positive, non-zero, integers.1) The cost of pencil isa) 27 b) 26 c) 28 d) data insufficient2) if u paid the shopkeeper Rs 210 for 2 notebooks, 3 pencils and 1 eraser, how many change would he returna) 3 b) 5 c) 7 d) data insufficient
@DexianLet the cost of Pencil, Eraser and Notebook be P, E and N respectively. 4P+4E+4N=400 4P+(3P-K1)+(8P+K2)=400 15P+(K2-K1)=400 P={400-(K2-K1)}/15 ~~~~eqn -1 Thus,the numerator should be less than 400. From the given options only 26 is the value which when divided by 15 gives 390(less than 400) where 27 and 28 gives value more than 400. Thus they are not the possible values. Hence 1)-option b)-26 4E=3P-K1 E=(78-K1)/4 4N=8P+K2 N=(208+K2)/4 K2-K1=10(can be obtianed from eqn -1) only 1 pair of value satisfies this condition i.e. K1=2 and K2=12 hence P=26 E=19 N=55 2) 2N+3P+1E=207 210-207=3(change returned) Option-a)-3
a) P=27N(min)=55E=18it doesn't satisfy the 3rd quation(3E>N)u cannt increase N as it will decrease E and again 3rd equationb)P=26N(min)=53E=21it doesn't satisfy the 3rd quation(3E>N)c)P=28N(min)=57E=15it doesn't satisfy the 3rd quation(3E>N)to D hua na....
E=19 aayeha.. 26*3=78 but E can be got only by dividing by 4 hence E=76/4=19