Official Quant thread for CAT 2013

@jain4444 said:
8 litres are drawn from a cask full of wine and is then filled with water.This operation is performed three more times.The ratio of the quantity of wine now left in cask to that of water is 16:81.How much wine did the cask hold originally ?
24?
@jain4444 said:
8 litres are drawn from a cask full of wine and is then filled with water.This operation is performed three more times.The ratio of the quantity of wine now left in cask to that of water is 16:81.How much wine did the cask hold originally ?
C= ( 1 - 8/V)^4 = (2/3)^4
=> V = 24
@jain4444 said:
8 litres are drawn from a cask full of wine and is then filled with water.This operation is performed three more times.The ratio of the quantity of wine now left in cask to that of water is 16:81.How much wine did the cask hold originally ?
Wine to water? or wine to total? doubt lag raha hai mujhe...

regards
scrabbler

@ScareCrow28 said:
C= ( 1 - 8/V)^4 = (2/3)^4 => V = 24
this formula is

(ratio of solution not replaced)/(total volume) = initial ratio * (vol. after removal/vol. after replacing)^n

16/97 = 1 * [(V - 8)/V]^4
@jain4444 said:
this formula is (ratio of solution not replaced)/(total volume) = initial ratio * (vol. after removal/vol. after replacing)^n 16/97 = 1 * [(V - 8)/V]^4
Should be wine to total na?
Ohhh...Didn't pay attention to that
@nole said:
A shipping clerk has five boxes of different but unkown weights each weighing less than 100 kg,the clerk weighs the boxes in pairs.The weights obtained are 110,112,113,114,115,116,117,118,120 and 121 kgs.What is the weight,in kgs of the heaviest box ?a) 60b) 62c) 64d) can't be determined.
My approach : solve it using options ..
trying option a ie. 60 ..so take 121 ..we need a weight of 61 kg ..this violates the condition as 60 kg is supposed to be the heaviest ..so A option is rejected ..

trying option B.. assume heaviest weight is 62 kg.. to make 118 ..other weight has to be 59 kg... similarly to make 120(62+58),,, so our third weight is 58kg... similarly solving we get fourth and fifth weights as 56 and 54 kg respectively ..
Hence our weight s are 62,59,58,56 and 54 kg .. This option B satisfies..
Hence B is the answer.

Team BV--Pratik Gauri
@bodhi_vriksha said:
One from my side: Three cubes of edge lengths 8cm, 6m and 2cm are placed face to face to form a solid object. Find the difference between the maximum and minimum possible surface area of the solid object formed.Team BV - Kamal Lohia
is it 144?
[Image]

EDIT : it's 72?
@ScareCrow28 If the ratio was 16:65 then wine:water chalega... ๐Ÿ˜ :D

Which the smallest two digit integer from the below options??


a) 24
b) 56
c) 10
d) None
@nole said:
A shipping clerk has five boxes of different but unkown weights each weighing less than 100 kg,the clerk weighs the boxes in pairs.The weights obtained are 110,112,113,114,115,116,117,118,120 and 121 kgs.What is the weight,in kgs of the heaviest box ?a) 60b) 62c) 64d) can't be determined.
4(w1+w2+w3+w4+w5) = 1156 , so w1+w2+w3+w4+w5 = 289

since , w1+w2 =121 and w4+w5 = 110 ,we have w3 = 58

No we can find w2 as w2+w3 = 117 is a possible case , so w2 = 59

so w1 = 62..


@jai.tuteja said:
Which the smallest two digit integer from the below options??a) 24b) 56c) 10d) None
Hmmm...tough hai :banghead:
@ScareCrow28 Kal he kisi ne office main poochaa tha....
Maine daaannnggg reh gayaa tha ek second k liye..!!!!
@jai.tuteja said:
Which the smallest two digit integer from the below options??a) 24b) 56c) 10d) None
-99 is the smallest integer.
so none?

btw #RIPenglish! :mg:
@ChirpiBird Absolutely correct..!!!!
@ChirpiBird What if i rephrase the question for the smallest integer???
@jai.tuteja said:
@ChirpiBird What if i rephrase the question for the smallest integer???
Then also none! Yaar tum apne he comments like kare ho? :splat:
@ScareCrow28 None ki jagah kya hogaa fir???
@jai.tuteja said:
@ChirpiBird What if i rephrase the question for the smallest integer???
sir , chit chat section mein post karo. :mg:
link : http://www.pagalguy.com/posts/4856061

plz Do not spam here. :)
x= 1+ โˆš2+ โˆš3, then the value of 2x^4 - 8x^3 - 5x^2 + 26x - 28?

Copied from CGL 2013 Thread!
@ScareCrow28 said:
x= 1+ ห†ลก2+ ห†ลก3, then the value of 2x^4 - 8x^3 - 5x^2 + 26x - 28?Copied from CGL 2013 Thread!
8 kareeb hain kya?...x ki value 4.1 approx hain..wahi daal ke ddekh liya....aur kuch nahi samjah aa raha..:P