@Gsathe89 said:find the remainder when 8^643 is divided by 132???
116 is it ?
@ScareCrow28 said:0 ?f(x,y) = ax + bySolve karne k baad f(10,4) = 0
in assuming the function why not take f(x,y) = ax+by+c as constant c can also come in a linear function ?
i took ax+by+c and got stuck up
i took ax+by+c and got stuck up
@rnishant231 said:in assuming the function why not take f(x,y) = ax+by+c as constant c can also come in a linear function ?i took ax+by+c and got stuck up
That answers your question! 😃 "c" b lagaoge to asnwer kaise nikaloge? OR another value should have been given.
@abhishek.2011 said:it will be 61200!/ 100! 100!now u need to find the highest prime number that contributes a power of 3 in numerator will a power of 2 in the denominatorfor 61 it is 61^3/61^2 =61for next prime 67 it is 67^2/67^2 67*3=201 so 200/67 =2
pls explain this..61 kaise aaya ?
@pakkapagal said:For Bold Part 2 case: either side of the stick1 case :jisme possible hai..1 case :jisme one is more than or equal to other two total 4 case out of which one is possible...so 1/4Aisa kya????(m confused with the cases)
sir mera bhi doubt clear kr dijiye na
@rnishant231 said:pls explain this..61 kaise aaya ?
well 200!/100! 100!
now all primes after 100 have their power as 1 in 100!
now as denominator has 2 100s their power becomes square
now in numerator we have 200!
we need those primes who have their power more than 2 in numerator
61 is the highest prime which satisfies this thats why 61
now all primes after 100 have their power as 1 in 100!
now as denominator has 2 100s their power becomes square
now in numerator we have 200!
we need those primes who have their power more than 2 in numerator
61 is the highest prime which satisfies this thats why 61
If A and B are the roots of x^-p(x+1)-c=0 then the value of
[(A^2+2A+1)/(A^2+2A+c)]+[B^2+2B+1)/(B^2+2B+c)] is
1. 2 2. 3/4 3. 1 4. 6/5
p.s. answers with approach.. Gud evening!!
@Highway66 said:If A and B are the roots of x^-p(x+1)-c=0 then the value of[(A^2+2A+1)/(A^2+2A+c)]+[B^2+2B+1)/(B^2+2B+c)] is 1. 2 2. 3/4 3. 1 4. 6/5p.s. answers with approach.. Gud evening!!
Is the answer 2 ?
I put p = 2 and c= 1
@ScareCrow28 nope
10 straight lines, no two of which are parallel nd no three of which pass through any common point, are drawn on a plane. The total number of regions (including finite and infinite regions) into which the plane would be divided is
1. 56 2. 255 3. 1024 4. not unique
P.s. answer with approach
@Highway66 said:If A and B are the roots of x^-p(x+1)-c=0 then the value of[(A^2+2A+1)/(A^2+2A+c)]+[B^2+2B+1)/(B^2+2B+c)] is 1. 2 2. 3/4 3. 1 4. 6/5p.s. answers with approach.. Gud evening!!
it will be 1 i guess
make a quadratic equation
x^ -px -(p+c)
p=4 c =8
roots -2 , 6
roots -2 , 6
put it and get 1 as the answer
@ScareCrow28 said:Is the answer 2 ?I put p = 2 and c= 1
bhai c =1 main 0/0 ki form banti h last b^2+2b+1/b^2+2b+c
plz check maine bhi yahi dala tha
@Highway66 said:@ScareCrow28 nope10 straight lines, no two of which are parallel nd no three of which pass through any common point, are drawn on a plane. The total number of regions (including finite and infinite regions) into which the plane would be divided is1. 56 2. 255 3. 1024 4. not uniqueP.s. answer with approach
n(n+1)/2 + 1
where n =10
answer 56 i guess
@abhishek.2011 said:bhai c =1 main 0/0 ki form banti h last b^2+2b+1/b^2+2b+cplz check maine bhi yahi dala tha
Haan yaar! 
Sai hai.. I didn't check it!
Sai hai.. I didn't check it! Then put, p = 2 and c = 6
A = 4 and B = -2
Ans will be 1 :)
@Highway66 said:If A and B are the roots of x^-p(x+1)-c=0 then the value of[(A^2+2A+1)/(A^2+2A+c)]+[B^2+2B+1)/(B^2+2B+c)] is 1. 2 2. 3/4 3. 1 4. 6/5p.s. answers with approach.. Gud evening!!
framing quadratic eq with p=1 , c=5
x^2 - x - 6 = 0
A = 3
B = -2
OA = 1 ??
x^2 - x - 6 = 0
A = 3
B = -2
OA = 1 ??
@Highway66 said:If A and B are the roots of x^-p(x+1)-c=0 then the value of[(A^2+2A+1)/(A^2+2A+c)]+[B^2+2B+1)/(B^2+2B+c)] is 1. 2 2. 3/4 3. 1 4. 6/5p.s. answers with approach.. Gud evening!!
Is it 1?
@Highway66 said:@abhishek.2011 ans sahi h dono hi.. straight line wale ka concept bata dijiye
read it bro