@hatemonger said:Solve
2 ??
What is the largest two digit prime factor of 200 C 100?
@albiesriram said:What is the largest two digit prime factor of 200 C 100?
i m getting a weird feeling that it should be 13
no 
@hatemonger said:Solve
P = (2-1)1! + (3-1)2!+ (4-1)3! + .....
P = 13! - 1
P+3 = 13! + 2
Hence remainder by 13! = 2 ?
no.:(
200!/ 100! .100!
200! mein two 97
100! mein one 97 = >no 97 in 200!/100!.100!
@albiesriram said:What is the largest two digit prime factor of 200 C 100?
67 ?
67*3 = 191 ( Largest prime) ..
no .
3p
p = 66.666
largest prime below 66 is 61
.
.@albiesriram said:no.200!/ 100! .100!200! mein two 97100! mein one 97 = >no 97 in 200!/100!.100!
thats wat...... no 97 in 200 C100...
to 97 prime factor hua na.......... nahi ????
EDIT: aa gya samajh me ... thanks
to 97 prime factor hua na.......... nahi ????
EDIT: aa gya samajh me ... thanks
@ScareCrow28 said:67 ?67*3 = 191 ( Largest prime) ..
@albiesriram said:no .3p p = 66.666largest prime below 66 is 61.
Damn!!! 
@albiesriram said:sir, 97 factor nahi hoga.Two 97s were there in numerator of 200! not in 200C100,That will anyway get cancelled by 2 100! WHICH OWNS A 97 EACH.200C100 = 200!/(100!*100) if we prime factorise this we wont have a 97 in the expression.
correct correct got it.....
X+1/X=4 than find the value of X^4-1/X^4????
@hatemonger said:X+1/X=4 than find the value of X^4-1/X^4????
112Root(3) ?
x + 1/x = 4
=> x^2 + 1/x^2 = 14
(x - 1/x)^2 = x^2 + 1/x^2 -2
=> ( x - 1/x ) = 2_/3
x^4 - 1/x^4 = (x^2 + 1/x^2) * ( x - 1/x ) * ( x + 1/x ) ..