@maroof10 said:The total number of integral solutions for (x,y,z) such that xyz=24,is
5c2 * 3c2 = 10*3=30
@albiesriram said:
n/(20 - n) = k^2
=> n = 20k2 / (1 + k2)
k2 = 0,1,4,9,16,.
integers values of n possible for k2 = 0,1,4,9
=> 4 values of n
@maroof10 said:The total number of integral solutions for (x,y,z) such that xyz=24,is
xyz=2^3*3^1
a+b+c=3 and a+b+c=1
c(5,2)=10 c(3,2)=3
so we have 10*3= 30 solutions:)
Team BV --Pratik Gauri
@bodhi_vriksha said:xyz=2^3*3^1a+b+c=3 and a+b+c=1c(5,2)=10 c(3,2)=3so we have 10*3= 30 solutionsTeam BV --Pratik Gauri
sir, there will be 30 positive integral solutions. we are asked integral solutions. so that must be 120 i guess.
@pavimai said:find the sum of the first 20 terms of the series 2*3,4*6,6*9,8*12.....
2*3=6=6*1^2
4*6=24=6*2^2
6*9=54=6*3^2
so summation(6n^2) where n=1 to 20 ....
n(n+1)(2n+1) ...put n=20
we get .. 20*21*41=17220 :)
Team BV-- Pratik Gauri
@techgeek2050 said:sir, there will be 30 positive integral solutions. we are asked integral solutions. so that must be 120 i guess.
i solved for positive integral solutions. if we take negative no's into account .. there would be 120 solutions :)
Team BV -- Pratik Gauri
@maroof10 said:The total number of integral solutions for (x,y,z) such that xyz=24,is
Integral solutions for x,y,z
1,8,3 =>6 ways
1,4,6=>6 ways
1,2,12=>6 ways
1,1,24=>3 ways
2,2,6=>3 ways
2,4,3=>6 ways
Total ways =30 ways
For ordered pair any 2 of x,y,z can be negative so 30 * 3C2=90 ways for which there can be negative terms.
Total number of integral solutions=30+90=120 ways
@techgeek2050 said:sir, there will be 30 positive integral solutions. we are asked integral solutions. so that must be 120 i guess.
i too solved it first for positive solutions if negatives are also allowed than 30*2^2= 120 solutions
only 2 can be negative so 2^2
Solv this:When both 26534 and 25644 are divided by a divisor the remainder obtained is same. What is the divisor..kindly gv d xplantn too if posibl d shortest
@abhishek.2011 said:i too solved it first for positive solutions if negatives are also allowed than 30*2^3 = 240 solutions
total 120.
30 positive solutions
for negatives, permutations are => -,-,+ / -,+,- / +,-,- /
30x3 = 90 more solutions
total = 120
@heenalove said:Solv this:When both 26534 and 25644 are divided by a divisor the remainder obtained is same. What is the divisor..kindly gv d xplantn too if posibl d shortest
I am not getting getting a unique solution. Am I misinterpreting the question?
Divisor=>Remainder
10=>4
2=>0
5=>4
89=>12 ?
@heenalove said:Solv this:When both 26534 and 25644 are divided by a divisor the remainder obtained is same. What is the divisor..kindly gv d xplantn too if posibl d shortest
there is no unique solution i guess.
@techgeek2050 said:total 120.30 positive solutionsfor negatives, permutations are => -,-,+ / -,+,- / +,-,- / 30x3 = 90 more solutionstotal = 120
bhai i have edited my post as only 2 can be negative here so 30*2^2 = 120
@abhishek.2011 said:bhai i have edited my post as only 2 can be negative here so 30*2^2 = 120
oh ya.. just saw ur edited post. 😃
@heenalove said:Solv this:When both 26534 and 25644 are divided by a divisor the remainder obtained is same. What is the divisor..kindly gv d xplantn too if posibl d shortest
there wont be a single solution to the problem
26534 = dq1 + r
25644=dq2 +r
subtract them
890 =d(q1-q2)
890 = dk
d can be 2 or 5 or 89
there are 14 consecutive numbers.find the number of ways of selecting 5 numbers such that only 2 are consecutive..
@abhishek.2011 said:there are 14 consecutive numbers.find the number of ways of selecting 5 numbers such that only 2 are consecutive..
13*12C3 ?
I didnt got d last 2 lines..as thy r 2 unknwns..so hw u got it
abhishek.2011