@gnehagarg said:Find the maximum value of ab+bc+cd/(a^2+b^2+c^2+d^2)a,b,c,d are real
i guess this will be 3/4 putting all equal
denominator is always greater than numerator except in range (0,1).
@mohitjain said:let s(n) be d sum of consecutive natural nos..z(n)=2 s(n)+41..find d least value of n for which Z(n) is composite??
first i want to clarify that this question is a little bit wrong.
are these consecutive natural numbers starting from 1 or from somewhere in between????
if starting from 1
n=40
n(n+1) + 41
n=40 makes it composite
if starting from anywhere in middle
n=2
n(n+1) + 2nx + 41
n=2 and x=1 satisfies
so 2,3 could be that numbers
On giving 3 pencils free with every 5 pens bought, a shopkeeper makes a profit of 20% and on giving 6 pencils free with every 2 pens bought, he suffers a loss of 25%. Find the approximate profit percent made by the shopkeeper when he gives 4 pencils free with every 6 pens bought. (Assume that the pencils are identical and the same applies to the pens.)
@amresh_maverick said:On giving 3 pencils free with every 5 pens bought, a shopkeeper makes a profit of 20% and on giving 6 pencils free with every 2 pens bought, he suffers a loss of 25%. Find the approximate profit percent made by the shopkeeper when he gives 4 pencils free with every 6 pens bought. (Assume that the pencils are identical and the same applies to the pens.)
Let C.P. pencils = a
Let C.P. pens = b
Let S.P pencils = x
Let S.P. pens = y
We have 5y/(3a+5b) = 6/5
=> y = (6/25)*(3a+5b)------>1
Also, y/(3a+b) = 3/4
y= (3/4) * (3a+b)------------->2
Equating the two we get:
5b=17a----------->3
We are required to find:
3y/(3b+2a) - 1
=72/61 - 1
=11/61
=18%
Let C.P. pens = b
Let S.P pencils = x
Let S.P. pens = y
We have 5y/(3a+5b) = 6/5
=> y = (6/25)*(3a+5b)------>1
Also, y/(3a+b) = 3/4
y= (3/4) * (3a+b)------------->2
Equating the two we get:
5b=17a----------->3
We are required to find:
3y/(3b+2a) - 1
=72/61 - 1
=11/61
=18%
@aditi88 said:ans s given as 360 nd evn i fail to understand why
wellbreak it like
2^23*3^9*5^4*7^2
now in 23 we have 11 multiples of 2 and including 2^0 it gets 12
2^0 , 2^2 , 2^4 ...................... 2^22
similarly for 3 it is 5
for 5 it is 3
for 7 it is 2
12*5*3*2=360
@amresh_maverick said:On giving 3 pencils free with every 5 pens bought, a shopkeeper makes a profit of 20% and on giving 6 pencils free with every 2 pens bought, he suffers a loss of 25%. Find the approximate profit percent made by the shopkeeper when he gives 4 pencils free with every 6 pens bought. (Assume that the pencils are identical and the same applies to the pens.)
17% ?
There are ānā necklaces in a safe box (n>1). Every necklace has the same number of diamonds. Each necklace has at least 2 diamonds. The total number of diamonds in these ānā necklaces is between 500 and 600. If this data is sufficient to find the value of n, then what is the value of ānā?
a 19
b 23
c 29
d None of these
a 19
b 23
c 29
d None of these
@amresh_maverick said:On giving 3 pencils free with every 5 pens bought, a shopkeeper makes a profit of 20% and on giving 6 pencils free with every 2 pens bought, he suffers a loss of 25%. Find the approximate profit percent made by the shopkeeper when he gives 4 pencils free with every 6 pens bought. (Assume that the pencils are identical and the same applies to the pens.)
@techgeek2050 said:17% ?
a 18%
b 20%
c 24%
d 16%
OA: 18%
b 20%
c 24%
d 16%
OA: 18%
@amresh_maverick said:There are ānā necklaces in a safe box (n>1). Every necklace has the same number of diamonds. Each necklace has at least 2 diamonds. The total number of diamonds in these ānā necklaces is between 500 and 600. If this data is sufficient to find the value of n, then what is the value of ānā? a 19 b 23 c 29 d None of these
500
n and x have to be equal
has to be a square of a prime no
since otherwise there will be many values of n and x
PS:- You posted these 2 questions a few days back as well, if i remember correctly
@amresh_maverick said:There are ānā necklaces in a safe box (n>1). Every necklace has the same number of diamonds. Each necklace has at least 2 diamonds. The total number of diamonds in these ānā necklaces is between 500 and 600. If this data is sufficient to find the value of n, then what is the value of ānā? a 19 b 23 c 29 d None of these
OA: 23
@Nihilist1002
It is cat 2001 lr question.some one please solve it.
shyama and vyom walk up an escalator(moving stairway).The escalator moves at a constant speed.Shyama takes 3 steps for every two of vyom's steps.Shyama gets to the top of the escalator after taking 25 steps.while vyom takes only 20 steps to reach at the top(because her slower pace lets the escalator do a little more of the work).If the escalator were turned off,how many steps would they have to take
to walk up ?
a) 40
b) 50
c) 60
d) 80
@nole said:It is cat 2001 lr question.some one please solve it.shyama and vyom walk up an escalator(moving stairway).The escalator moves at a constant speed.Shyama takes 3 steps for every two of vyom's steps.Shyama gets to the top of the escalator after taking 25 steps.while vyom takes only 20 steps to reach at the top(because her slower pace lets the escalator do a little more of the work).If the escalator were turned off,how many steps would they have to take to walk up ?a) 40b) 50c) 60d) 80
Shyam's speed = 3 steps / unit time
Vyom's speed = 2 steps / unit time
Escalator's speed = n steps
When shyam takes 25 steps, escalator takes 25/3 n steps
When Vyom takes 20 steps , escalator takes 10n steps
(When shyam takes 3 steps, escalator takes n steps. So when he takes 25 steps escalator takes 25/3n steps)
Equating
25+25/3n = 20+10n
5 = 5/3n
n=3
Number of steps in the escalator = 20+10(3) = 50
@amresh_maverick said:On giving 3 pencils free with every 5 pens bought, a shopkeeper makes a profit of 20% and on giving 6 pencils free with every 2 pens bought, he suffers a loss of 25%. Find the approximate profit percent made by the shopkeeper when he gives 4 pencils free with every 6 pens bought. (Assume that the pencils are identical and the same applies to the pens.)
18%
@nole said:It is cat 2001 lr question.some one please solve it.shyama and vyom walk up an escalator(moving stairway).The escalator moves at a constant speed.Shyama takes 3 steps for every two of vyom's steps.Shyama gets to the top of the escalator after taking 25 steps.while vyom takes only 20 steps to reach at the top(because her slower pace lets the escalator do a little more of the work).If the escalator were turned off,how many steps would they have to take to walk up ?a) 40b) 50c) 60d) 80
50
A person walking takes 26 steps to come down on a escalator and it takes 30 seconds for him for walking. The same person while running takes 18 second and 34 steps. How many steps are there ?
@gnehagarg said:Find the maximum value of ab+bc+cd/(a^2+b^2+c^2+d^2)a,b,c,d are real
3/4 is it?
minimum value of (a^2+b^2+c^2+d^2) =4*(a^2*b^2*c^2*d^2)^1/4=4*(a*b*c*d)^1/2
which is possible only when a=b=c=d
so, Maximum value of given expression = 3a/4a =3/4
@nramachandran said:A person walking takes 26 steps to come down on a escalator and it takes 30 seconds for him for walking. The same person while running takes 18 second and 34 steps. How many steps are there ?
Length of escalator will always be same.
So, applying that concept, 26+30*v = 34+18*v
=> 12*v = 8=> v=8/12 =2/3
==> number of steps =26+30*2/3=46
@nole said:It is cat 2001 lr question.some one please solve it.
shyama and vyom walk up an escalator(moving stairway).The escalator moves at a constant speed.Shyama takes 3 steps for every two of vyom's steps.Shyama gets to the top of the escalator after taking 25 steps.while vyom takes only 20 steps to reach at the top(because her slower pace lets the escalator do a little more of the work).If the escalator were turned off,how many steps would they have to take
to walk up ?
a) 40
b) 50
c) 60
d) 80
b 50