OK so bear with me, this is gonna be a bit long…Consider a number 123456. Let's try and get the remainder with 999.Let's split it as 123000 + 456.Now 123000 = 123 *1000 = 123 * (999+1) = 123*999 + 123. So remainder with 999 is 123.Also 456 ka remainder with 999 is of course 456. So total remainder is equivalent to 123 + 456 = 579.Similarly if we try to find the remainder of 123234345 with 999 we can show it will be ≡ 123 + 234 + 345 = 702 and so on.So if we want to find the remainder of a number with 999, split it into groups of 3 digits (starting from the last) and add them.So in this case 1212121212121212….300 digits ≡ 121212 50 times ≡ (121 + 212) + (121 + 212)…50 times which is ≡ 333 * 50 when divided by 999.Now Rem(333 * 50) /999 ≡ 333 *Rem (50/3) = 333 * 2 = 666. And there I was trying to apply Chinese Remainder and whatnot @iLoveTorres @Narci @techgeek2050 @amresh_maverick regardsscrabbler
1> A no N when increased by 50% has its no of factors as unchanged . But when decreased by 75% , the no of factors is decreased by 33.33%. Min value of N ?
1> A no N when increased by 50% has its no of factors as unchanged . But when decreased by 75% , the no of factors is decreased by 33.33%. Min value of N ?
1> A no N when increased by 50% has its no of factors as unchanged . But when decreased by 75% , the no of factors is decreased by 33.33%. Min value of N ?
1> A no N when increased by 50% has its no of factors as unchanged . But when decreased by 75% , the no of factors is decreased by 33.33%. Min value of N ?
2592 satisies. Min hai ki nahin pata nahin :( regards scrabbler
12 = 2^2*3 no of factors = 3*2=6 now when 12 is decreased by 75% it becomes 3.. no of factors 2Decrease 6 by 33.33% i.e 6/3=2Also increase 12 by 50% you get 18 no of factors of 18=2*3^2 = 3*2=6Agar koi galti hai toh batao
no of factorrs should decrease by 1/3...
in your case.. the no of factors reduced to 1/3...
1> A no N when increased by 50% has its no of factors as unchanged . But when decreased by 75% , the no of factors is decreased by 33.33%. Min value of N ?
this means when it is 3/2 N it has same no, of factors.. therefore it is of the form
2^a*3^a-1*x where x and 3 are co-prime and 2 and x are also co-prime...
when decrease by 75% then it decreases by 33.33%
therefore 2^a-2*3^a-1*x has no of factors = 2/3(a+1)a*X = (a-1)a*X--> 2/3(a+1) = a-1 -->
1> A no N when increased by 50% has its no of factors as unchanged . But when decreased by 75% , the no of factors is decreased by 33.33%. Min value of N ?
