How many 3 digit numbers can be formed by the digits 0,1,1,2,2,2
A>15
B>10
C>14
D>12
@Faruq said:The guards of two goods trains are in the respective last carriages of their trains. The two trains A and B of length 200 m and 300 m respectively, begin to enter a 500-metre long tunnel from opposite ends. The guard of one of the trains wants to pick up a flag from the other guard. How long after the instant when the two trains begin to enter the tunnel, does this exchange occur? (Given that speed of train A = 2 m/s, speed of train B = 3 m/s)
100 seconds?
@Faruq said:The guards of two goods trains are in the respective last carriages of their trains. The two trains A and B of length 200 m and 300 m respectively, begin to enter a 500-metre long tunnel from opposite ends. The guard of one of the trains wants to pick up a flag from the other guard. How long after the instant when the two trains begin to enter the tunnel, does this exchange occur? (Given that speed of train A = 2 m/s, speed of train B = 3 m/s)
200sec? 1000/5..
@Faruq said:The guards of two goods trains are in the respective last carriages of their trains. The two trains A and B of length 200 m and 300 m respectively, begin to enter a 500-metre long tunnel from opposite ends. The guard of one of the trains wants to pick up a flag from the other guard. How long after the instant when the two trains begin to enter the tunnel, does this exchange occur? (Given that speed of train A = 2 m/s, speed of train B = 3 m/s)
200 sec ?
500 + 200 + 300/(2 + 3) = 200 secs
In a box, there are 24 balls numbered 1 through 24. Out of the 24 balls, the
numbers of balls that are coloured black, red and green are 10, 8 and 6
respectively. If Alan randomly takes out 6 balls from the box, then the total
number of ways in which 2 green balls can be taken out from the box by Lamb is
15 and the probability of taking out a red ball is half the probability of taking out
a non-red one.After Alan has taken out 6 balls at random, Smith also takes out 2
balls from the box randomly. What is the probability that Smith did not take out
a red ball?
1. 11/17
2. 13/18
3. 2/3
4. 22/51
5. 7/9
numbers of balls that are coloured black, red and green are 10, 8 and 6
respectively. If Alan randomly takes out 6 balls from the box, then the total
number of ways in which 2 green balls can be taken out from the box by Lamb is
15 and the probability of taking out a red ball is half the probability of taking out
a non-red one.After Alan has taken out 6 balls at random, Smith also takes out 2
balls from the box randomly. What is the probability that Smith did not take out
a red ball?
1. 11/17
2. 13/18
3. 2/3
4. 22/51
5. 7/9
@Faruq said:The guards of two goods trains are in the respective last carriages of their trains. The two trains A and B of length 200 m and 300 m respectively, begin to enter a 500-metre long tunnel from opposite ends. The guard of one of the trains wants to pick up a flag from the other guard. How long after the instant when the two trains begin to enter the tunnel, does this exchange occur? (Given that speed of train A = 2 m/s, speed of train B = 3 m/s)
200 secs it is!
@Faruq
are you sure the options are correct, i am getting the answer as 5/17. done orally so maybe an error in visualization of equations but here you go:
lamb has 15 ways of picking out a green ball after alan takes out 6 balls: as 6c2 is 15, alan did not take out a green ball.
probability of taking a red ball = 1/2 of taking out a non red ball. Let number of red balls be r.
Solve: r/18=1/2*((24-r)/18) to get r=8. Hence alan did not take out a red ball either, means he took out 6 black balls.
now the probability of smith taking out a non red ball= 10c2/28c2= 5/17
Have i commited a silly mistake somwhere, or misinterpreted the question? @Faruq
are you sure the options are correct, i am getting the answer as 5/17. done orally so maybe an error in visualization of equations but here you go:
lamb has 15 ways of picking out a green ball after alan takes out 6 balls: as 6c2 is 15, alan did not take out a green ball.
probability of taking a red ball = 1/2 of taking out a non red ball. Let number of red balls be r.
Solve: r/18=1/2*((24-r)/18) to get r=8. Hence alan did not take out a red ball either, means he took out 6 black balls.
now the probability of smith taking out a non red ball= 10c2/28c2= 5/17
Have i commited a silly mistake somwhere, or misinterpreted the question? @Faruq
@anantn said:@Faruqare you sure the options are correct, i am getting the answer as 5/17. don e orally so maybe an error in visualization of equations but here you go:lamb has 15 ways of picking out a green ball after alan takes out 6 balls: as 6c2 is 15, alan did not take out a green ball.probability of taking a red ball = 1/2 of taking out a non red ball. Let number of red balls be r.Solve: r/18=1/2*((24-r)/18) to get r=8. Hence alan did not take out a red ball either, means he took out 6 black balls.now the porbability of smith taking out a non red ball= 10c2/28c2= 5/17Have i commited a silly mistake somwhere, or misinterpreted the question?
Bhai Check this line "Solve: r/18=1/2*((24-r)/18) to get r=8. Hence alan did not take out a red ball either, means he took out 6 black balls."
yaha (18-r) aayega (see bold part). and r will be 6
@Faruq
oh damn yeah.....why did i write 24 there....this is the problem with doing things orally...silly mistakes like these really hurt....
oh damn yeah.....why did i write 24 there....this is the problem with doing things orally...silly mistakes like these really hurt....
A man purchased 129kgs of sugar and was forced to sell it a loss equal to the selling price of 30kg of sugar. If he purchased each kilo of sugar at Rs. 15, then at what price did he sell each kilogram?
a. 11.5 b. 13.7 c. 14.28 d. 12.1
a. 11.5 b. 13.7 c. 14.28 d. 12.1
@Faruq said:A man purchased 129kgs of sugar and was forced to sell it a loss equal to the selling price of 30kg of sugar. If he purchased each kilo of sugar at Rs. 15, then at what price did he sell each kilogram?a. 11.5 b. 13.7 c. 14.28 d. 12.1
14.28
@Faruq said:A man purchased 129kgs of sugar and was forced to sell it a loss equal to the selling price of 30kg of sugar. If he purchased each kilo of sugar at Rs. 15, then at what price did he sell each kilogram?a. 11.5 b. 13.7 c. 14.28 d. 12.1
129 C = 129S + 30S = 159S
So S = (129/159) *C = (129/159) * 15 ~ 12.1 I guess
regards
scrabbler
So S = (129/159) *C = (129/159) * 15 ~ 12.1 I guess
regards
scrabbler
@Faruq since 6c2 ways of choosing greeen, 4 were removed....since p(red) is 1/3, 2 red were removed...so we have have left in the box 6 of each colour...now, the desired value is (6c2+6c2+36) / 18c2 = 22/51
@Faruq said:In a box, there are 24 balls numbered 1 through 24. Out of the 24 balls, thenumbers of balls that are coloured black, red and green are 10, 8 and 6respectively. If Alan randomly takes out 6 balls from the box, then the totalnumber of ways in which 2 green
22/51
@Faruq said:A man purchased 129kgs of sugar and was forced to sell it a loss equal to the selling price of 30kg of sugar. If he purchased each kilo of sugar at Rs. 15, then at what price did he sell each kilogram?a. 11.5 b. 13.7 c. 14.28 d. 12.1
12.1 ?
sp of 159 kg = cp of 129 kg
sp of 159 kg = 15*129
sp of 1 kg = 15*129/159 = 12.1
sp of 159 kg = cp of 129 kg
sp of 159 kg = 15*129
sp of 1 kg = 15*129/159 = 12.1
@Faruq said:A man purchased 129kgs of sugar and was forced to sell it a loss equal to the selling price of 30kg of sugar. If he purchased each kilo of sugar at Rs. 15, then at what price did he sell each kilogram?a. 11.5 b. 13.7 c. 14.28 d. 12.1
CP =129*15
SP=129*x
129*15 - 129X =30X
129*15 / 159 =x
x=12.1 ANS
SP=129*x
129*15 - 129X =30X
129*15 / 159 =x
x=12.1 ANS