Official Quant thread for CAT 2013

MBA CAT 2024
23087
@viewpt said:
bhai i got 80..
yaar..calc mistake hogi...check karo...meine bhi 2 baar calc mistake kari thi...
23088
@vbhvgupta said:
At what % above CP must an article be marked so as to gain 17% after allowing a discount of 10%.
Let CP be 100 and x% markup be given
So (100+x)*90/100 = 117
=> x= 30
Hence 30% markup
23089
@vbhvgupta said:
At what % above CP must an article be marked so as to gain 17% after allowing a discount of 10%.
Let CP =100 rs
Profit add karke 117 rs
Now 117 is 90% kyunki Discount bhi toh dena hai So isko 100% bana do
117/90 *100 =130
So 30% ans
23090
@KhannaiiM said:
In how many ways can 600 be expressed as a sum of two or more consecutive natural numbers?
5 ways?
Number of odd factors -1
23091
@vbhvgupta said:
At what % above CP must an article be marked so as to gain 17% after allowing a discount of 10%.
30%
23092
@KhannaiiM said:
In how many ways can 600 be expressed as a sum of two or more consecutive natural numbers?
600 = 2^3*3*5^2

Odd factors = 6

Thus, 11 ?
23093
@KhannaiiM said:
In how many ways can 600 be expressed as a sum of two or more consecutive natural numbers?
5 ?

1000 = 2^3*3*5^2
odd no. of factors = 2*3 = 6
no. of ways = 6 - 1 = 5
23094
@gs4890 said:
600 = 2^3*3*5^2Odd factors = 6Thus, 11 ?
11 nahi 5.. odd factors -1. so 6-1 =5
23095
@mailtoankit said:
5 ?1000 = 2^3*3*5^2odd no. of factors = 2*3 = 6no. of ways = 6 - 1 = 5
OA ->5

23096
@Ibanez said:
11 nahi 5.. odd factors -1. so 6-1 =5
Ya man...11 will be in case of integer solutions :)

Forgot all basics
23097
Imp. for CAT 13 Aspirants

A small tip posted earlier too

CONCEPT :-

To write the number as the sum of 2 or more consecutive natural no. or integers-

Let the no. be N which has 'O.' no. of odd factors then N can be written-

Case1:-As a sum of two or more consecutive natural no. is given by the formula-

=O-1

Case2:- As a sum of two or more consecutive integers is given by the formula-

= 2*O - 1
23098

formula toh theek h..koi aise bhi samjhao

23099
@vbhvgupta said:
At what % above CP must an article be marked so as to gain 17% after allowing a discount of 10%.
Let the CP be 100.
Let the MP be 100 + x. We need to find x.

SP= 90% of MP
Profit =17

0.9(100+x) -100 = 17
x= 30%
23100
The average of 60 positive distinct integers all greater than 7 is equal to 41. What could be the maximum possible value of any one of these 60 integers?
a. 277 b. 217 c. 210 d. 224
23101
@vbhvgupta said:
A retailer buy a tv at a discount of 15 % and sels it for 5865, thus making a profit of 15%. the discount is?
CP | MP | SP
X | Y | 1.15X = 0.85Y = 5865
Find Y and hence, 0.15Y = 1035
23102
@Faruq said:
The average of 60 positive distinct integers all greater than 7 is equal to 41. What could be the maximum possible value of any one of these 60 integers?a. 277 b. 217 c. 210 d. 224
277
23103
@Faruq said:
The average of 60 positive distinct integers all greater than 7 is equal to 41. What could be the maximum possible value of any one of these 60 integers?a. 277 b. 217 c. 210 d. 224
Approach:
Minimize the first 59 integers. Starting from 8 to 66.
Sum = 66x67/2 - 28 = 2183

Total sum of 60 integers= 60 x 41 = 2460.

Hence the 60th integer = 2460-2183 = 277
23104
@sbharadwaj said:
CP | MP | SPX | Y | 1.15X = 0.85Y = 5865Find Y and hence, 0.15Y = 1035
Y=5100....
but then this was the CP for which the retailer bought at 15% discount...
So the actual CP (for the person who sold it to the retailer) = .85a=5100
a=6000
hence the discount offered was 6000-5100=900
23105

Q. Wht is the probability tht a quad eqn : ax^2 + bx + c= 0has equal roots if a,b n c are distinct n r taken frm {1,2,3,4,6,8,9} ?


options-> a) 1/35 b) 2/35 c) 1/105 d) 2/105

need soln plz.
23106
@Faruq said:
The average of 60 positive distinct integers all greater than 7 is equal to 41. What could be the maximum possible value of any one of these 60 integers?a. 277 b. 217 c. 210 d. 224


start from 8,9,10,11,12....66(59th digit)
from n(n+1)/2, calculate sum
66*67/2 - 7*8/2=2183
average- 41*60=2460
2460-2183=277