The latest registration number issued by the Delhi Motor Vehicle Registration Authority is DL-5S 2234 . If all the numbers and alphabets before this have been used up then find how many vehicles have a registration number starting with DL- 5 ?plz provide detailed explanation.....ans=182216 number using alphabets less than S = 10*10*10*10*18 - 18 = 179982 BUT WHY DID YOU SUBTRACT 18???
@jain4444 Thanks for the solution.The latest registration number issued by the Delhi Motor Vehicle Registration Authority is DL-5S 2234 . If all the numbers and alphabets before this have been used up then find how many vehicles have a registration number starting with DL- 5 ?plz provide detailed explanation.....ans=182216number using alphabets less than S = 10*10*10*10*18 - 18 = 179982BUT WHY DID YOU SUBTRACT 18???
because i considered that "0000" was not a valid number
A positive integer is written on each face of a cube. On each vertex, the product of the 3 numbers on the faces containing the vertex is written. If the sum of the numbers on the vertices is 1298, what is the sum of the numbers on the faces?
A positive integer is written on each face of a cube. On each vertex, the product of the 3 numbers on the faces containing the vertex is written. If the sum of the numbers on the vertices is 1298, what is the sum of the numbers on the faces?
let the nos on faces of cube be a,b,c,d,e,f where a and f are on opposite faces.
so a/c to problem: (abc+abd+ace+ade)+(fbc+fbd+fce+fde)=1298 a(bc+bd+ce+de)+f(bc+bd+ce+de) =2*11*59; also bc+bd+ce+de =(b+e)(c+d) so, (a+f)(b+e)(c+d)=2*11*59 compare both sides, so a+f+b+e+c+d=2+11+59=72
A positive integer is written on each face of a cube. On each vertex, the product of the 3 numbers on the faces containing the vertex is written. If the sum of the numbers on the vertices is 1298, what is the sum of the numbers on the faces?
For how many positive integers n ‰¤ 1000, is the digit root of n^2 + n + 1 equal to 3?P.S - The digit root of a number is a single digit value obtained by iterative digit sums. For example, the digit root of 31^2 + 31 + 1 = 993 would be 3 since 9 + 9 + 3 = 21 , 2 + 1 = 3.
K is a 3 digit number .K1, K2, K3 are numbers obtained when K is in base 5,7 and 9 respectively. The units place in K1, K2, K3 is 2. How many such possible K values are there a) 0 b) 1 c) 2 d) 3
Selling price of a shirt and a coat is Rs. 4000. The cost price of a shirt is 58.33% of the cost price of a coat and so amount of profit on both the shirt and coat is same, then the price of the shirt could be:
K is a 3 digit number .K1, K2, K3 are numbers obtained when K is in base 5,7 and 9 respectively. The units place in K1, K2, K3 is 2. How many such possible K values are there a) 0 b) 1 c) 2 d) 3
@Dexian Plzz ....... Tell me what is ur Approach !!
5*7*9 = 315 315 wen represented in base 5, 7, 9 will havee units digit as 0 in all 3 cases. so 317 will have 2 in its units place in all 3 bases.. next number shud be 315*2+2=632 next 315*3+2=947...
K is a 3 digit number .K1, K2, K3 are numbers obtained when K is in base 5,7 and 9 respectively. The units place in K1, K2, K3 is 2. How many such possible K values are there a) 0 b) 1 c) 2 d) 3
Another Question came like this ........ 1024*2065 + 2564*2653 + 5216*5645 is in octal form ........ find number of digit 6 that comes after multiplication ?? .......... Can u plzz help !!
Selling price of a shirt and a coat is Rs. 4000. The cost price of a shirt is 58.33% of the cost price of a coat and so amount of profit on both the shirt and coat is same, then the price of the shirt could be:a) 2100b) 2525c) 2499d) 1120
Selling price of a shirt and a coat is Rs. 4000. The cost price of a shirt is 58.33% of the cost price of a coat and so amount of profit on both the shirt and coat is same, then the price of the shirt could be:a) 2100b) 2525c) 2499d) 1120
SP of shirt = x
SP of coat = (4000 - x)
let CP of coat = 300y
CP of shirt = 175y
x - 175y = 4000 - x - 300y
=> 2x + 125y = 4000
from option only 1 value will satisfy this i.e. 2100