maths assumption pe chale toh iska answer should be 0 failed in all the four.. fail hona kisse pasand hai.. min and max ko rule ke hisab se solve karte hai na? jus like that you can decide the maximum value for a variable.. agree?
We need to maximise those failing in all four so for that we need to minimise the ones in Only 1 subject and Only 2 subject.
We need to maximise those failing in all four so for that we need to minimise the ones in Only 1 subject and Only 2 subject.
that is why you need to find the correct maximum value for III because when you maximise III, II( MINIMUM) IS found.. n I minimum cant be found under any case to the best of my knowledge
The latest registration number issued by the Delhi Motor Vehicle Registration Authority is DL-5S 2234 . If all the numbers and alphabets before this have been used up then find how many vehicles have a registration number starting with DL- 5 ?
that is why you need to find the correct maximum value for III because when you maximise III, II( MINIMUM) IS found.. n I minimum cant be found under any case to the best of my knowledge
But then if III = 41 and IV = 37 as you calculated. With III = 41, None = 150 - 41*3 = 150 - 123 = 27 right ?
So, Total = 41 + 37 + 27 = 105 which has to be hundred 100 Sir. :)
So, we need to take it as 37 so that it totals up to 100. :splat:
Sir jee OA kya hai eska??If its none of these , then please can you provide the answer..as in what it should be...There has been a lot of discussion over this...people are getting D..but then the final answer is not matching....
The latest registration number issued by the Delhi Motor Vehicle Registration Authority is DL-5S 2234 . If all the numbers and alphabets before this have been used up then find how many vehicles have a registration number starting with DL- 5 ?plz provide detailed explanation.....ans=182216
Before S, we have 18 letters and 10^4 combinations for numbers => 18*10^4 = 180000 combinations. ( - 18 for those having 0000 as one combination ).
The latest registration number issued by the Delhi Motor Vehicle Registration Authority is DL-5S 2234 . If all the numbers and alphabets before this have been used up then find how many vehicles have a registration number starting with DL- 5 ?plz provide detailed explanation.....ans=182216
But then if III = 41 and IV = 37 as you calculated. With III = 41, None = 150 - 41*3 = 150 - 123 = 27 right ?So, Total = 41 + 37 + 27 = 105 which has to be hundred 100 Sir. So, we need to take it as 37 so that it totals up to 100.
if my approach is wrong as i said before answer should be 0as you stated NONE=150-3*50=0
also in my approach i got II(MINIMUM)=1
so NONE=150-3*41-2*1=25 plus no where i m assuming I(minimum)=0..
anyways if the person who has posted the question itself is saying it to be 13 toh i rest my case.
The latest registration number issued by the Delhi Motor Vehicle Registration Authority is DL-5S 2234 . If all the numbers and alphabets before this have been used up then find how many vehicles have a registration number starting with DL- 5 ?plz provide detailed explanation.....ans=182216
number using alphabets less than S = 10*10*10*10*18 - 18 = 179982
The latest registration number issued by the Delhi Motor Vehicle Registration Authority is DL-5S 2234 . If all the numbers and alphabets before this have been used up then find how many vehicles have a registration number starting with DL- 5 ?plz provide detailed explanation.....ans=182216
A group of workers was put on a job. From the second day onwards, oneworker was withdrawn each day. The job was finished when the last worker was withdrawn. Had no worker been withdrawn at any stage, the group wouldhave finished the job in two thirds the time. How many workers were there inthe group
A group of workers was put on a job. From the second day onwards, oneworker was withdrawn each day. The job was finished when the last worker was withdrawn. Had no worker been withdrawn at any stage, the group wouldhave finished the job in two thirds the time. How many workers were there inthe group
A group of workers was put on a job. From the second day onwards, oneworker was withdrawn each day. The job was finished when the last worker was withdrawn. Had no worker been withdrawn at any stage, the group wouldhave finished the job in two thirds the time. How many workers were there inthe group
