Official Quant thread for CAT 2013

MBA CAT 2024
22387
@Shrutim90 said:
@karan20
Nope. The answer is 0.20833%. But meko solution nai samajh aya
ok..got it...cal mistake..
see total land of sukhiya is 800 sq units as he is paying tax on 60% of the total land....
480 = k x 60/100 x Area ;;; Area = 800/k
384000 = k x 60/100 Area ;;;;; Area = 640000/k
Now v r asked to find Total Land of sukhiya as % of total cultivable Land
Hence = 800/k / 384000/k
= 800/384000 = 0.2083 %....
PS:For convinience consider 1 Rs per 1 Sq unit as the Tax...
22388
@saurav205 said:
Questions
1st waala kaise hoga ??

2. 128^500 mod 153
2^3500 mod 153
E(153) = 100
2^100k mod 153 = 1
so ...rem = 1...ans option d??
22389
@mailtoankit said:
1st waala kaise hoga ??2. 128^500 mod 153 2^3500 mod 153E(153) = 1002^100k mod 153 = 1so ...rem = 1...ans option d??
1St one take condition as difference of digits at alternate places as 11...
Y-x =8
22390
@Shrutim90 said:
Lagaan is levied on the 60% of the cultivated land. The revenue dept collected total Rs. 384000 through the lagaan from the village of Sukhiya. Sukhiya, a very rich farmer, paid only Rs. 480 as lagaan. What is the percentage of total land of Sukhiya over the total taxable land of the village?
480 is 0.125% of 384000
now since lagaan is collected on 60% for cultivated land.. so..
.125/0.6 will gv the total land sukhiya owns over total taxable land.
=.20833
22391
@mailtoankit said:
1st waala kaise hoga ??2. 128^500 mod 153 2^3500 mod 153E(153) = 1002^100k mod 153 = 1so ...rem = 1...ans option d??
2nd waala ...153= 17*9
Individual remainders nikaal kar use chinese remainder theorem
17A-1and 9b+4....
Find eska solution
It will come as 67
22392
@saurav205 said:
Questions
OA:
67
9
22393
@mailtoankit said:
1st waala kaise hoga ??2. 128^500 mod 153 2^3500 mod 153E(153) = 1002^100k mod 153 = 1so ...rem = 1...ans option d??
E(153) = 96 nhi h kya?
153(1-1/3)(1-1/17) .. 96?

22394
@ChirpiBird said:
E(153) = 96 nhi h kya? 153(1-1/3)(1-1/17) .. 96?
@saurav205 said:
2nd waala ...153= 17*9Individual remainders nikaal kar use chinese remainder theorem17A-1and 9b+4....Find eska solutionIt will come as 67
abe haan yaar....51 ko prime maan liya.......thanks..
22395
@mailtoankit said:
1st waala kaise hoga ??2. 128^500 mod 153 2^3500 mod 153E(153) = 1002^100k mod 153 = 1so ...rem = 1...ans option d??
or you can fix x (different values) and check the value of y..
like for x=0 i got y as 8. (this is not the answer as y>x>0)
second case (ans) x=1, y as 9. .. (this worked)
22396

n= 4711 *4713 *4715 .find the remainder when n is divided by 48.


22397
@jain4444 said:
In a class of 100 students 70 passed in physics, 62 passed in mathematics, 84 passed in english and 82 passed in chemistry. 37 students passed in all 4 subjects. How many maximum students could have failed all four subjects?(a) 12 (b) 17 (c) can not be determined (d) none of the foregoing
d?


22398
@ChirpiBird said:
E(153) = 96 nhi h kya?
153(1-1/3)(1-1/17) .. 96?

bhai... i was about 2 point dis ... lekin ankit ne post kiya toh doubt aa gaya ..
PS: sorry 4 spamng
22399
@ChirpiBird said:
d?
answer kitna aaya tera??
Me getting 16...
22400
@sachisurbhi said:
n= 4711 *4713 *4715 .find the remainder when n is divided by 48.
21 hai kya??
4711/48 gives a remainder of 7
so 4713 gives 9
and 4715 gives 11
7*9*11/48
7*3 = 21
22401
@sachisurbhi said:
n= 4711 *4713 *4715 .find the remainder when n is divided by 48.
21?
22402
@saurav205 said:
answer kitna aaya tera??Me getting 16...
13
22403
@mailtoankit said:
bhai attachment dekh lo....waise OA kya hai...i dont knw if my solution is correct
sorry 4 late rply..ur ans is correct.
thnx 4 explaining.
22404
PLZ HELP....
In how many ways 10 identical presents can be distributed among 6 children ,so that each child gets atleast one present.
(a) C(15,5) (b) C(16,6) (c) C(9,5) (d) 6^10
Ans : (c) C(9,5)
22405
@ChirpiBird said:
13
Kaise??
22406
@sachisurbhi said:
n= 4711 *4713 *4715 .find the remainder when n is divided by 48.
21 ?