A went on a tour. He visited a total of 8 cities. In each city he spent Rs.2 less than half the amount he had with him. He spent Rs.100 in the last city he visited. Find the amount he had initially (in Rs.)?
A went on a tour. He visited a total of 8 cities. In each city he spent Rs.2 less than half the amount he had with him. He spent Rs.100 in the last city he visited. Find the amount he had initially (in Rs.)?
A went on a tour. He visited a total of 8 cities. In each city he spent Rs.2 less than half the amount he had with him. He spent Rs.100 in the last city he visited. Find the amount he had initially (in Rs.)?
Sir, Acc to you he had 25604 initially, so he must have spent 25604/2 - 2 = 12802 - 2= 12800 in the 1st city whereas he has spent 12804 acc to you.. anomaly?
Aur ek me "-" use hua aur bakiyo me "+" ?? I couldn't get the solution..
Sir, Acc to you he had 25604 initially, so he must have spent 25604/2 - 2 = 12802 - 2= 12800 in the 1st city whereas he has spent 12804 acc to you.. anomaly?
bhai sir na bolo yaar
he spent = 100 at last city
100 = (x/2) - 2 => x = 204
now 204 is the amount which he had at 7th city after spending some amount there so this amount is nothing but half + 2 of the amount which he had at 6th after spending and so on
Sir, Acc to you he had 25604 initially, so he must have spent 25604/2 - 2 = 12802 - 2= 12800 in the 1st city whereas he has spent 12804 acc to you.. anomaly?
bhai sir na bolo yaar he spent = 100 at last city 100 = (x/2) - 2 => x = 204 now 204 is the amount which he had at 7th city after spending some amount there so this amount is nothing but half + 2 of the amount which he had at 6th after spending and so on
bhai sir na bolo yaar he spent = 100 at last city 100 = (x/2) - 2 => x = 204 now 204 is the amount which he had at 7th city after spending some amount there so this amount is nothing but half + 2 of the amount which he had at 6th after spending and so on
last city he will spend {(X-508)/256}-2 and this is equal to 100.
Ways if 1 woman holds VP/P = 4C3*3C1*4C2*2*24C3 --- Taking 3 females of 4 3C1 --- Taking 1 lady of those 3 and assigning some position ( P/VP)4C2 --- Taking 2 Males2 ------ Ways of assigning a post to a female2 ------ Ways of assigning a post to two malesSimilarly others have been realised. Hope you can make out others too. Sorry for late reply.
Thank you for your explanation.:)
If 2 women hold P/VP position = 4C4*4C1*3*4 = 48
I can't understand that particular step. What do 3 and 4 represent? And also, is it not necessary to divide everything by 3!, because of the three secretary jobs?
Thank you for your explanation.If 2 women hold P/VP position = 4C4*4C1*3*4 = 48I can't understand that particular step. What do 3 and 4 represent? And also, is it not necessary to divide everything by 3!, because of the three secretary jobs?
If 2 women hold P/VP position = 4C4*4C1*3*4 = 48
4C4 --- Take 4 Females of 4
4C1 --- Take 1 Male of 4
Now, the male has 1 place to go to. ( Any of 3 secretaries )
And Take any 2 females in 4C2 ways which can be arranged in 2! ways or 4P2 ways = 3*4
Sorry for directly writing the values 😞 and being late in reply ( SBI PO form ni bhar par )
Calc error!
