Official Quant thread for CAT 2013

@amresh_maverick said:
Pipes A and B can completely fill a water tank independently in 4 hrs and 5 hrs respectively. A pipe C can empty the tank filled completely with water in 3 hrs. Initially the tank is empty and all the pipes are closed. Pipe A is opened first at time t = 0 hrs and pipe C is opened at the instant when the tank is exactly half filled with water. Pipe B is opened after pipe C and at the instant when the tank is exactly one-fourth filled with water. Find the total time taken to fill the tank completely counting from t = 0 hrs.
time for a to make it half full= 2 hours
time for a and c together to make it v/4 empty = 3 hours
time for a b and c to make it 3v/4 full = 45/7 hours
2+3+45/7 = 80/7= 11.42 hours
@amresh_maverick said:
Y cannot be 2 as base is 2also (x - y)(x + y + 1) = 14 - 1*14 or 2*7
yaar..samajh nahi aaya??..
bold waala part se hi kiya hai meine ??
Given that w, x, y and z are natural numbers such that 4w = xyz, 4x = wyz and 4z = wxy. Which of the following is a possible value of (w + x + y €“ z)^2?


25
9
36
1
@iLoveTorres said:
ladkiya yaar yaar bolke seene pe war kar deti hai Sorry for spamming
ok.. "koi nhi bhaiya.." happy to help.. 😛 😛


@amresh_maverick said:
Pipes A and B can completely fill a water tank independently in 4 hrs and 5 hrs respectively. A pipe C can empty the tank filled completely with water in 3 hrs. Initially the tank is empty and all the pipes are closed. Pipe A is opened first at time t = 0 hrs and pipe C is opened at the instant when the tank is exactly half filled with water. Pipe B is opened after pipe C and at the instant when the tank is exactly one-fourth filled with water. Find the total time taken to fill the tank completely counting from t = 0 hrs.
80/7??
@amresh_maverick said:
Given that w, x, y and z are natural numbers such that 4w = xyz, 4x = wyz and 4z = wxy. Which of the following is a possible value of (w + x + y €“ z)^2? 25 9 36 1
25
@mailtoankit said:
yaar..samajh nahi aaya??..bold waala part se hi kiya hai meine ??
u took
(x - y)(x + y + 1) = 14 as 2*7
and got y=2 which is not possible as (222) in base 2 is not possible



(x - y)(x + y + 1) = 1 * 14 bhi ho sakta hai

Then u will get x= 7 and Y=6
@amresh_maverick said:
Given that w, x, y and z are natural numbers such that 4w = xyz, 4x = wyz and 4z = wxy. Which of the following is a possible value of (w + x + y €“ z)^2? 25 9 36 1
x=z=w=1 and y=4

so, 25??

@amresh_maverick said:
Given that w, x, y and z are natural numbers such that 4w = xyz, 4x = wyz and 4z = wxy. Which of the following is a possible value of (w + x + y €“ z)^2? 25 9 36 1
Is the answer 25?
@amresh_maverick said:
Given that w, x, y and z are natural numbers such that 4w = xyz, 4x = wyz and 4z = wxy. Which of the following is a possible value of (w + x + y €“ z)^2? 25 9 36 1
25
@amresh_maverick said:
Given that w, x, y and z are natural numbers such that 4w = xyz, 4x = wyz and 4z = wxy. Which of the following is a possible value of (w + x + y €“ z)^2? 25 9 36 1
25 ?

y = 4, x = z = w = 1
@amresh_maverick said:
Given that w, x, y and z are natural numbers such that 4w = xyz, 4x = wyz and 4z = wxy. Which of the following is a possible value of (w + x + y €“ z)^2? 25 9 36 1
x=z=w=1, y=4
..25?

m back finally....need questions..

@Logrhythm @saurav205 @raopradeep & to rest all bhai& unki behen log questions lao
@amresh_maverick said:
Given that w, x, y and z are natural numbers such that 4w = xyz, 4x = wyz and 4z = wxy. Which of the following is a possible value of (w + x + y €“ z)^2? 25 9 36 1
36?
@amresh_maverick said:
Given that w, x, y and z are natural numbers such that 4w = xyz, 4x = wyz and 4z = wxy. Which of the following is a possible value of (w + x + y €“ z)^2? 25 9 36 1
OA = 25

Beaker A and beaker B contain methanol, ethanol and phenyl in the ratio 1:3:2 and 2:1:5 respectively. Some parts of the solutions from beaker A and beaker B are thoroughly mixed and put into another beaker C. Which of the following cannot be the ratio of methanol, phenyl and ethanol in beaker C?

10 :23 :15
7 :15 :16
6 :13 :13
9 :20 :18



PS: sab phodu log padhar chuke hain
@raopradeep said:
three variables x,y,z have a sum of 30. all three of them are non-negative integers . if any two integers dont have same value and exactly one variable has a value equal or less than three .find number of possible solutiins
98
285
68
294

i banged my head yesterday 2 times just because of this question now will post 2 approaches, all the options are wrong here
x+y+z=30
let y and z be greater than 3
x+(4+a)+(4+b)=30
here y= 4+a and z = 4+b as a and b can be 0,1..... so y and z will always be greater than 3
x+a+b=22
solutions = 24c2
now these 24c2 solutions will include cases in which x is anything from 0 to 22
let x .y ,z all be greater than 3
(4+a) + (4+b) +(4+c)=30
a+b+c=18 solutions 20c2
now 24c2 - 20c2 will include all the numbers having x less than or equal to 3 and y and z greater than or equal to 4
let x be 0 y and z can be equal here (15,15) so -1case
let x be 2 y and z can again be equal here (14,14) so -1 case
total favourable cases
24c2- 20c2 -2 =84
now this i did for x similarly y and z can also be taken
so 84*3c1=252
prove me wrong if u can
@ChirpiBird said:
x=y=w=1, y=4..25?
didi y=1 & y=4? yeh kya kar diya?
@amresh_maverick said:
OA = 25

Beaker A and beaker B contain methanol, ethanol and phenyl in the ratio 1:3:2 and 2:1:5 respectively. Some parts of the solutions from beaker A and beaker B are thoroughly mixed and put into another beaker C. Which of the following cannot be the ratio of methanol, phenyl and ethanol in beaker C?


PS: sab phodu log padhar chuke hain
kahan h which of the following bhai?????
@iLoveTorres said:
didi y=1 & y=4? yeh kya kar diya?
yaar samjha karo x=Z=w=1, y=4
find the 60th digit after decimal in the expansion of 1/2013 ...

remainder when 2^2 + 22^2 + 222^2 + 2222^2 + ....(222...49twos)^2 is divided by 9?
ans options: 2,5,6,7 ?