@scrabbler said:Or, 7^3 - 6^3 fits your description regardsscrabbler
yea...ye waala answer nikaalne ke baad strike kiya...
@scrabbler said:Or, 7^3 - 6^3 fits your description regardsscrabbler
We have diff cases in this kind of qs:
1) cover a cube (with no conditions given): 8^3-6^3
2) cube is on table: 8*8*7-6^3
3) cube is in the corner, the one i posted above..so for this is it: 7^3-6^3?
Plz confirm.
1) cover a cube (with no conditions given): 8^3-6^3
2) cube is on table: 8*8*7-6^3
3) cube is in the corner, the one i posted above..so for this is it: 7^3-6^3?
Plz confirm.
@sonamaries7 said:We have diff cases in this kind of qs:1) cover a cube (with no conditions given): 8^3-6^32) cube is on table: 8*8*7-6^33) cube is in the corner, the one i posted above..so for this is it: 7^3-6^3?Plz confirm.
Yes seems to make sense....all three...visualise it...for example 1st mein you are adding a top and bottom layer in each direction (x, y, z axis) so 6 ka side will become 8 ka side...and in the last only 1 layer in each direction added so 7^3...
regards
scrabbler
regards
scrabbler
@scrabbler said:Yes seems to make sense....all three...visualise it...for example 1st mein you are adding a top and bottom layer in each direction (x, y, z axis) so 6 ka side will become 8 ka side...and in the last only 1 layer in each direction added so 7^3...regardsscrabbler
and if it is just against a wall, like not in a corner, then: 8*7*7-6^3, right?
@sonamaries7 said:We have diff cases in this kind of qs:1) cover a cube (with no conditions given): 8^3-6^32) cube is on table: 8*8*7-6^33) cube is in the corner, the one i posted above..so for this is it: 7^3-6^3?Plz confirm.
1st one correct
2nd one correct = 1st one answer - 8^2= 232
3rd one correct..
@sonamaries7 said:and if it is just against a wall, like not in a corner, then: 8*7*7-6^3, right?
....haan, exactly!
regards
scrabbler
regards
scrabbler
How to find tan when sec(x) is given? 
@sonamaries7 said:There is a cube of dimensions: 6*6*6 placed in a corner in a room.FInd no of cubelets required to cover the cube completely.
36.3+18+1=127
@sonamaries7 said:How to find tan when secx is given?
sec^2(x) - tan^2(x) = 1
Ye kaisa ques pucha tumne?? :sneaky:
@saurav205 said:Whats the OA??
@saurav205 said:M getting 504 ..way over all the options...Approach :a = 0 ; b+c =30 where b.c >= 4total ways 22(subtracted the case where they are equal i.e. 15)a = 1 ;total cases 22a =2 ; total cases 20a = 3 ; total cases 20in all 84 cases..since they are all different any value from the above values can be assigned..so it should be multiplied by 3!..pata nai kya kiya hai...but answer toh nai aa raha hai esse....
sorry for posting late oa is 294
kyu kya prob hai...
@raopradeep said:
@scrabbler Bhai eska approach please...
i am getting 504 or something..
cause I multiplied 84*3! (3! cause number of solutions mein a,b and c can be interchanged..
approach galat hai kya??
@sonamaries7 said:There is a cube of dimensions: 6*6*6 placed in a corner in a room.FInd no of cubelets required to cover the cube completely.
as it is placed in a corner --7*7+7*6+6*6=127..drawing the figure would help
@saurav205 said:@scrabbler Bhai eska approach please...i am getting 504 or something..cause I multiplied 84*3! (3! cause number of solutions mein a,b and c can be interchanged..approach galat hai kya??
bhai iam not having solution @scrabbler @Logrhythm bhai throw some light on this question