Official Quant thread for CAT 2013

@vijay_chandola said:
for unit digit 2, 3, 5 = 5! combinations eachfor 4 and 6 = 2*4! eachtotal = 5!+5!+2*4!+5!+2*4! = 456
oa is 528

@ScareCrow28 said:
3*5! + 2*2*4! = 456
@vijay_chandola
oa is 528

@raopradeep said:
find the number of 6 digit numbers that can be found using 1,2,3,4,5,6 once such that the 6 digit number is divisible by its unit digit (the unit digit is not 1)620456520372
I am getting 528...
when unit digit is either 2,3,5 or 6 then each number would be divisible by the unit digit..
so possible numbers are 5*4*3*2*1*4 = 480
when unit digit is 4 then only two digits can be at ten's place i.e 2 and 6.
so possible numbers are 4*3*2*1*2*1= 48
total numbers are = 480 + 48 = 528..
plz tell me where i am getting wrong??
@vijay_chandola said:
for unit digit 2, 3, 5 = 5! combinations eachfor 4 and 6 = 2*4! eachtotal = 5!+5!+2*4!+5!+2*4! = 456
oa is 528

@Jackson1 said:
I am getting 528...when unit digit is either 2,3,5 or 6 then each number would be divisible by the unit digit..so possible numbers are 5*4*3*2*1*4 = 480when unit digit is 4 then only two digits can be at ten's place i.e 2 and 6.so possible numbers are 4*3*2*1*2*1= 48total numbers are = 480 + 48 = 528..plz tell me where i am getting wrong??
right answer bro :)

@raopradeep said:
My solution was incorrect, There is no 528 in the options and m answer is coming out to be
4*5! + 2*4! = 528
@raopradeep said:
oa is 528
Which is what I was getting...par woh options mein tha hi nahin :(

regards
scrabbler

@raopradeep said:
yeas it would be 528.
Misjudged the division by 6 :embarrassed:
Number of cases would be 5!
@vijay_chandola said:
for unit digit 2, 3, 5 = 5! combinations each
for 4 and 6 = 2*4! each

total = 5!+5!+2*4!+5!+2*4! = 456
bro 6 k case main
_ _ _ _ _ 6
as sum of numbers is 21 so any combination will be divisible by 3
as last digit is even so divisible by 2
hence by 6
so why 2*4! ???????

there are N men sitting around acircular table at N distinct points . every possible pair of men except the ones sitting adjacent to each other sings a 2 minute song one pair after other. of total time taken is 88 min. find N ?

8
10
9
11

@scrabbler said:
Which is what I was getting...par woh options mein tha hi nahin regardsscrabbler
SORRY bhai typo tha options me
@raopradeep said:
there are N men sitting around acircular table at N distinct points . every possible pair of men except the ones sitting adjacent to each other sings a 2 minute song one pair after other. of total time taken is 88 min. find N ?810911
11 is it?

Just go by options

@abhishek.2011 said:
bro 6 k case main_ _ _ _ _ 6as sum of numbers is 21 so any combination will be divisible by 3as last digit is even so divisible by 2hence by 6so why 2*4! ???????
See my previous post :embarrassed:
@vijay_chandola said:
Kadbury offers a packet of 5 chocolates at the list price of 4 chocolates and on purchasing 19 such packets gives one packet absolutely free. A trader receives 20 packets of the chocolates in the offer and sells each chocolate at its list price. What is his net percentage profit?

(a) 24% (b) 31.58% (c) 35% (d) 53.75%
31.58 it will be
@raopradeep said:
there are N men sitting around acircular table at N distinct points . every possible pair of men except the ones sitting adjacent to each other sings a 2 minute song one pair after other. of total time taken is 88 min. find N ?810911
11 hoga....

N(N-3)/2 = 44

This is a CAT actual question I guess? From early 2000s...

regards
scrabbler

ABC is the internal bisector of the angle meets BC at D. If Ab 2root3 AC is 4root3, angle A is 60 degrees, find AD.

@scrabbler said:
11 hoga....N(N-3)/2 = 44This is a CAT actual question I guess? From early 2000s...regardsscrabbler
bhai this eqtn means i think n * (n-3) means the man himself and his two neighbors including him =88 min song
rectify if iam wrong

@veertamizhan said:
ABC is the internal bisector of the angle meets BC at D. If Ab 2root3 AC is 4root3, angle A is 60 degrees, find AD.
You mean AD is the angle bisector of angle A, meets BC at D, right ?
@veertamizhan said:
ABC is the internal bisector of the angle meets BC at D. If Ab 2root3 AC is 4root3, angle A is 60 degrees, find AD.
4 hi hoga....right angle hai...Bahut time laga diya :(

regards
scrabbler

zada has to distribute 15 choclates among her 5 kids(a,b,c,d,e) . such that "a" gets atleast 3 and at most 5 chocolates .in how many ways she can do this ?

495
77
417
435

@raopradeep said:
bhai this eqtn means i think n * (n-3) means the man himself and his two neighbors including him =88 min song rectify if iam wrong
N people....each have to be paired with N - 3 people (exclude him and ppl next to him)....but each such pair is counted twice (once from each person's point of view) so divide by 2. Now this should be 44 as 88 min @ 2 min per pair => 44 pairs.

regards
scrabbler