@iLoveTorres said:bro it should be 7/52 n not 7/50.. if i am wrong kindly correct me
nahi 7/50 hi hoga....
@techsurge said:13c1*7c1/26c27/25
sale darata hai meko.... 

@iLoveTorres said:bro it should be 7/52 n not 7/50.. if i am wrong kindly correct me
@techsurge said:13c1*7c1/26c27/25

a set of 15 different words are given . in how many ways is it possible to choose a subset of not more than 5 words ?
@audiq7 said:bhai mere.. pehla banda mila hai tu muze jo 7/50 keh raha hai.. in succession hi tha. u sure?
@raopradeep said:a set of 15 different words are given . in how many ways is it possible to choose a subset of not more than 5 words ?49444^1515^44943
@raopradeep said:a set of 15 different words are given . in how many ways is it possible to choose a subset of not more than 5 words ?49444^1515^44943
@techsurge said:15c1+15c2+15c3+15c4+15c515+ 105 + 420+1365+3003last digit 3 hoga islye only 4th satisfy
@scrabbler said:In succession does not mean order fixed as red and then blue. Just means 1 at a time. Still need to consider both cases RB and BR and hence should be 7/25 I feel.regardsscrabbler

@raopradeep said:a set of 15 different words are given . in how many ways is it possible to choose a subset of not more than 5 words ?49444^1515^44943
@raopradeep said:oa is 4944kya 15c0 be count karenge kya ?
@iLoveTorres said:by the rule a null set is a subset.. so you should include it in my opinion.. hope @scrabbler bhai provides some reason to it being selected or not selected
@audiq7 said:13 red balls, 7 blue balls and 6 yellow balls are present in the box. What is the probability that 2 balls are selected such that 1 ball is red and the other blue?
@iLoveTorres said:by the rule a null set is a subset.. so you should include it in my opinion.. hope @scrabbler bhai provides some reason to it being selected or not selected
@raopradeep said:a set of 15 different words are given . in how many ways is it possible to choose a subset of not more than 5 words ?49444^1515^44943