Official Quant thread for CAT 2013

8------->10

1------->10/8
12----->120/8=15

50%
@amresh_maverick said:
A dishonest dealer claims to sell a product at its cost price. He uses a counterfeit weight which is 20% less than the real weight. Further greed overtook him and he added 20% impurities to the product. Find the net profit percentage of the dealer?
OA 50%

Let the actual value be 100x. After he used the counterfeit weight, the value becomes 80% of the actual value or 80x. Also, after adding 20% impurities to the value now, it becomes 120% of 80x = 96x. And because of faulty balance it becomes 1.25 * 96x =120x So, the profit will be (120x - 80x )/80x or 50%.
@amresh_maverick said:
OA 50%Let the actual value be 100x. After he used the counterfeit weight, the value becomes 80% of the actual value or 80x. Also, after adding 20% impurities to the value now, it becomes 120% of 80x = 96x. And because of faulty balance it becomes 1.25 * 96x =120x So, the profit will be (120x - 80x )/80x or 50%.
8------->10
1------->10/8
12----->120/8=15

10 to 15 .............. 50 %
ye bhi thik hain na??

@Dexian said:
8------->101------->10/812----->120/8=1510 to 15 .............. 50 %ye bhi thik hain na??
Any method fine...as long as there is a logic and it gives you the right answer fast....

No step marking in CAT thank goodness :D

regards
scrabbler

@scrabbler said:
Any method fine...as long as there is a logic and it gives you the right answer fast....No step marking in CAT thank goodness regardsscrabbler
bhai kuch ache geometry questions post kardo

Last two digits of 1989^91 ?

@Calvin4ever said:
Last two digits of 1989^91 ?
89 only?

regards
scrabbler

A train is travelling at a speed of 96 km/hr. It takes 3 s to enter a tunnel and 30 s more to pass through it completely. What is the length of the train?
@scrabbler said:
89 only?regardsscrabbler
Inspite of there being no step marks, pls do tell me the method u used. mine is taking a lot of time !
@Calvin4ever said:
Last two digits of 1989^91 ?
89 ...??
@Calvin4ever said:
Last two digits of 1989^91 ?
89
@amresh_maverick said:
A train is travelling at a speed of 96 km/hr. It takes 3 s to enter a tunnel and 30 s more to pass through it completely. What is the length of the train?
80m?
@Calvin4ever said:
Last two digits of 1989^91 ?
1989^91 --- 89^91 ----> (89^2)^45 *89---> 21^45 * 89----> 01 * 89 ----> 89
@amresh_maverick said:
A train is travelling at a speed of 96 km/hr. It takes 3 s to enter a tunnel and 30 s more to pass through it completely. What is the length of the train?
80 m ??
@Calvin4ever said:
Inspite of there being no step marks, pls do tell me the method u used. mine is taking a lot of time !
9 when raised to odd power will have 9 in units place and when raised to even power will have 1 in units place.
For Tens place multiply the Tens place digit with the unit digit of the power in this case it will be 8(Tens digit)*1(Unit digit)

1> Ten's digit of 24^257 - 13^131
2> 97^97^97 when divided by 11 leaves rem
3> X = 1! +2!+3!.....+100! , unit digit of x^xxxx
4> rem when 19^92 is divided by 92

PS: OA at 2:20

=2000^91 - 2000^90 *11 +2000^89 *11^2 - ..................... +2000 * 11^90 - 11^91

11^91:
=10^91 + 10^90+............................+10+1
=last 2 digit 11

so XXXXX00 - YY11 = K89
@iLoveTorres said:
9 when raised to odd power will have 9 in units place and when raised to even power will have 1 in units place. For Tens place multiply the Tens place digit with the unit digit of the power in this case it will be 8(Tens digit)*1(Unit digit)
nice 😃 but is this general or shud it be applied in particular cases alone ??
@amresh_maverick said:
1> Ten's digit of 24^257 - 13^131 2> 97^97^96 when divided by 11 leaves rem3> X = 1! +2!+3!.....+100! , unit digit of x^xxxx4> rem when 19^92 is divided by 92
3>3

@amresh_maverick said:
1> Ten's digit of 24^257 - 13^131 2> 97^97^97 when divided by 11 leaves rem3> X = 1! +2!+3!.....+100! , unit digit of x^xxxx4> rem when 19^92 is divided by 92PS: OA at 2:15
1)2
2)4
3)3
4)49