@SoniaA said:Hii,This is my first post 78. The following is known about three real numbers x,y and z.-4d) -4
@Logrhythm said:nah..i was wrong...check @scrabbler's post on this...
yeah.. that's what i did and got two values for d. but everyone was answering 4, so i got confused
Can you please let me know the procedure to solve it
@scrabbler said:Take -0.5, 1.5, 2.5, 3.5 satisfy ho jayega.So d is either 3.5 or 4, total 15/2...regardsscrabbler
bro here you wont get a pair whose sum is 1.
@SoniaA said:Can you please let me know the procedure to solve it
look the range for Y and Z are same so M would be dependent only on the range of X. A simpler approach will be to take the minimum values of X,Y,Z and substitute in the equation to get the minimum value of the equation then substitute the maximum values to get the maximum value of the equation.
@scrabbler said:a+b = -0.5 +1.5....regardsscrabbler
sorry dint notice that "-" sign. but this is by trial and error.. is there any generalized method for such type of problems?
@iLoveTorres said:sorry dint notice that "-" sign. but this is by trial and error.. is there any generalized method for such type of problems?
Not trial and error na - I gave a rigorous solution above :(
http://www.pagalguy.com/posts/4723406
regards
scrabbler
http://www.pagalguy.com/posts/4723406
regards
scrabbler
Divya and Raveena can do a work alone exactly in 20 and 25 days respectively. However, when they work together, they do 25% more work than is expected. If they work for a few days alone and for few days together (both being integers only), then the work could not have been completed in exactly
(1) 10 days (2) 14 days (3) 16 days (4) 17 days (5) either none or at least 2 of these
(1) 10 days (2) 14 days (3) 16 days (4) 17 days (5) either none or at least 2 of these
@jain4444 said:Divya and Raveena can do a work alone exactly in 20 and 25 days respectively. However, when they work together, they do 25% more work than is expected. If they work for a few days alone and for few days together (both being integers only), then the work could not have been completed in exactly (1) 10 days (2) 14 days (3) 16 days (4) 17 days (5) either none or at least 2 of these
14 days
@jain4444 said:Divya and Raveena can do a work alone exactly in 20 and 25 days respectively. However, when they work together, they do 25% more work than is expected. If they work for a few days alone and for few days together (both being integers only), then the work could not have been completed in exactly (1) 10 days (2) 14 days (3) 16 days (4) 17 days (5) either none or at least 2 of these
@jain4444 said:Divya and Raveena can do a work alone exactly in 20 and 25 days respectively. However, when they work together, they do 25% more work than is expected. If they work for a few days alone and for few days together (both being integers only), then the work could not have been completed in exactly (1) 10 days (2) 14 days (3) 16 days (4) 17 days (5) either none or at least 2 of these
14 days??
did it with HnT...no proper approach (as always, in case of Time and Work)...
@Logrhythm said:14 days??did it with HnT...no proper approach (as always, in case of Time and Work)...
@jain4444 this is what I did
Let total work be 100 units...
working alone
divya does 5 u/d
raveena does 4 u/d
working together -> 45/4 u/d
they wld work together either on 4 or 8 days (coz if it is 12 then 45*3 > 100)
after this it simple to form an equation and find x (x is when they work alone)
u get 10,16 and 17 but not 14... and hence 14...
method batao bhaisaab!
25% more work means 25% less time to do the same work..so if it takes 100/9 normally, it will only take 75/9 when they work together.
Yeh sahi hai.?
@VJ12
@mohitjain said:14 days
approach:
take total work =100 units
so d=5 units/day
r=4 units/day
so together=9 den 25% more=11.25
since d days r integer so no. of units 2geher shud also b n integer
2 possibility:
1)11.25*8=90 units(takes 8 days)
den remaining 10 units ..let d do dis=2 days..so total 10 days
2)11.25*4=45 units(takes 4 days)
remaining 55 units cn be done in 2 ways:
1st d=35 units(7 days) n r=20 units(5 days)
total 16 days
2nd r=40(10 dys) n d=15(3 days)
total =17 days..
so 14 is d OA
hope u get it!!!
take total work =100 units
so d=5 units/day
r=4 units/day
so together=9 den 25% more=11.25
since d days r integer so no. of units 2geher shud also b n integer
2 possibility:
1)11.25*8=90 units(takes 8 days)
den remaining 10 units ..let d do dis=2 days..so total 10 days
2)11.25*4=45 units(takes 4 days)
remaining 55 units cn be done in 2 ways:
1st d=35 units(7 days) n r=20 units(5 days)
total 16 days
2nd r=40(10 dys) n d=15(3 days)
total =17 days..
so 14 is d OA
hope u get it!!!
The no of ways of dividing 15 men and women into 15 couples each consisting of man and woman is
1240?
@jain4444 said:The no of ways of dividing 15 men and women into 15 couples each consisting of man and woman is
15!-1?
1m and 1w can be chosen among 15m and 15w is 15c1*15c1=225
again 1m and 1w can be chosen among 14m and 14w is 14c1*14c1=196
.again 1m and 1w can be chosen among 13m and 13wis 13c1*13c1=169
.
.
similarly 1m and 1w can be chosen among 1m and 1w is 1c1*1c1=1
sum of squares till 15 which is ÎŁn^2 (where n=15) = 1240