Height max for a given base...take the 10 as base, draw an arc of 7 from one end, see where max height will come....it is when the 7 is perpendicular to the 10... regards scrabbler
1,2,3,7... seq is generated by adding 1 to first term to get second, adding 2 to second term to get third, adding 3 to third term to get the fourth.. so on value of 156th term.??
a billiard ball is hit at 45 degree angle from the corner of 6 by 8 foot billiard table How many times ball rebound off an edge of the table before landing into corner>? 5,6,7,8,2. ?
1,2,3,7... seq is generated by adding 1 to first term to get second, adding 2 to second term to get third, adding 3 to third term to get the fourth.. so onvalue of 156th term.??1209012091120891209412088
a billiard ball is hit at 45 degree angle from the corner of 6 by 8 foot billiard tableHow many times ball rebound off an edge of the table before landing into corner>?5,6,7,8,2. ?
a billiard ball is hit at 45 degree angle from the corner of 6 by 8 foot billiard tableHow many times ball rebound off an edge of the table before landing into corner>?5,6,7,8,2. ?
bhai i have a query heretime is constant hereso we can say they are travelling in opposite direction they will together cover the distance in the ratio of the speedisnt it?
yeah and if they were travelling in the same direction then the distance covered and also the relative speed will be different.. in a simple case in the first round they wil travel distance "d" in the second round they wil travel a distance of "2d"
Well....series was quadratic....so found equation...1/2 * (x^2 - x + 2) then substituted x = 156.Before that figured that it should be odd (looking at pattern) but 3 options got eliminated and 2 remained regardsscrabbler
bhai agar isme right spin ya left spin ya screw back karke mare toh bhi 5 rails pe lagke pot hoga? :P P.S sorry for spamming but i am a snooker addict so i was tempted to post something like this :P
1, 2, 4, 7....first level difference is: 1, 2, 3, 4...so second level difference is: 1, 1, 1, 1...so this is a quadratic equivalent (continuous function mein "second derivative constant" ka equivalent)
So try ax^2 + bx +c For x = 1 a+b+c = 1 For x = 2 4a+2b+c = 2 For x = 1 9a+3b+c = 4 solve for a, b, c
I saved one step by recognising that if the second level difference is 2, it is a quad with a = 1. If second level diff is 1, therefore, a must be 1/2 and so only had to find b and c. regards scrabbler
bhai agar isme right spin ya left spin ya screw back karke mare toh bhi 5 rails pe lagke pot hoga? P.S sorry for spamming but i am a snooker addict so i was tempted to post something like this
No, but sometimes more and sometimes less, roughly a Poisson distribution. I did a Monte Carlo simulation to 5 million iterations and the resultant mean value was 4.9857. Hence 5.
P.S. Sorry for spamming but I am a maths addict so I was tempted to post something like this. regards scrabbler
1, 2, 4, 7....first level difference is:1, 2, 3, 4...so second level difference is:1, 1, 1, 1...so this is a quadratic equivalent (continuous function mein "second derivative constant" ka equivalent)So try ax^2 + bx +cFor x = 1 a+b+c = 1For x = 2 4a+2b+c = 2For x = 1 9a+3b+c = 4solve for a, b, cI saved one step by recognising that if the second level difference is 2, it is a quad with a = 1. If second level diff is 1, therefore, a must be 1/2 and so only had to find b and c.regardsscrabbler
all the terms are in form :- 1 1+1 1+1+2 1+1+2+3 1+1+2+3+4 . . . 1+1+2+3+4.....................+155 1+(155*156/2) 12091 plz correct me if wrong
