@scrabbler said:10?regardsscrabbler
Sorry 5, chote triangle ka 1/6th lene tha...
regards
scrabbler
regards
scrabbler
@scrabbler said:Sorry 5, chote triangle ka 1/6th lene tha...regardsscrabbler
going by your approach if i am not wrong from what i have understood is the 1st median will divide the triangle by 1/2 the second median will divide it by 1/4 so when you extend this it should divide it by 1/6?
@iLoveTorres said:going by your approach if i am not wrong from what i have understood is the 1st median will divide the triangle by 1/2 the second median will divide it by 1/4 so when you extend this it should divide it by 1/6?
No, starting from the 1/2 triangle, I found that the smaller one has half the height and 1/3rd the base....at least I think so, my figure is a mess as usual.
regards
scrabbler
regards
scrabbler
@nyancat said:120 days------ 5/6so in 90 days-3/4*5/6=15/24=5/8so saved..5/6-5/8=5/24 so fraction saved5/24/5/6=1/4?????????
thanx so much 
@scrabbler said:1/4th hai kya?See, basically if earlier you spent 1 hour studying every 3 days and now you spend 1 hour studying every 4 days, you would studying only 3/4 time as much as you were earlier. So the fraction reduced is 1/4.Similarly here,if we required 5/6 hour every 90 days, and now the same time 5/6 hour is spent every 120 days (4/3 times as long) then you are only spending 3/4th of the original average-time-per-day right? So you are saving 1/4th.At least that is how I am interpreting the problem OA please?regardsscrabbler
"See, basically if earlier you spent 1 hour studying every 3 days and now you spend 1 hour studying every 4 days, you would studying only 3/4 time as much as you were earlier. So the fraction reduced is 1/4"
this means total 1 hr spent in 4days and 1hr in 3 days. Didn't get "you would studying only 3/4 time as much as you were earlier. So the fraction reduced is 1/4" 
please xplain in step by step simpler terms
@nam2aspire said:"See, basically if earlier you spent 1 hour studying every 3 days and now you spend 1 hour studying every 4 days, you would studying only 3/4 time as much as you were earlier. So the fraction reduced is 1/4"this means total 1 hr spent in 4days and 1hr in 3 days. Didn't get "you would studying only 3/4 time as much as you were earlier. So the fraction reduced is 1/4" please xplain in step by step simpler terms
Consider total study in 12 days. Earlier 4 hrs, now 3. Reduction of 1/4th.
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regards
scrabbler
Chalo bhai log me off 😞 Work beckons!
regards
scrabbler
@nam2aspire said:thanx so much
y the sol'n doesn't end with 5/6-5/8=5/24
explain why to do this
5/24/5/6=1/4
@nam2aspire said:y the sol'n doesn't end with5/6-5/8=5/24explain why to do this5/24/5/6=1/4
fraction nikalana hai..
need to get fraction amount saved
@nyancat said:120 days------ 5/6so in 90 days-3/4*5/6=15/24=5/8so saved..5/6-5/8=5/24 so fraction saved5/24/5/6=1/4?????????
y the sol'n doesn't end with 5/6-5/8=5/24
explain why to do this???
5/24/5/6=1/4
explain why to do this???
5/24/5/6=1/4
@amresh_maverick said:There are 3 states and 3 students representing each state. In how many ways can 5 students be chosen such that at least one student is chosen from each state ?PS: sabha yahi samapt hoti hai
405?
first select 1 student from each state to satisfy at least criteria. this can be done in 3c1*3c1*3c1=27 ways. other two students can be chosen randomly from remaining lot of 9-3=6 students. and this can be done in 6c2= 15 ways. therefore the answer should be 27*15= 405.
first select 1 student from each state to satisfy at least criteria. this can be done in 3c1*3c1*3c1=27 ways. other two students can be chosen randomly from remaining lot of 9-3=6 students. and this can be done in 6c2= 15 ways. therefore the answer should be 27*15= 405.
i got that bt i m little confused wth the sol'n given in the book.it is
LCM of 90 and 120 = 360
So, in 360 days, the pre-overhauling service time = 5/6*360/90 = 10/3 hrs
and after overhauling,the service time = 5/6*360/120 = 5/2 hrs
Time saved = 10/3-5/2 = 5/6 hrs
therefore, the required answer = 5/6/10/3 = 1/4
i didn't get that why they hav divided 5/6 with 10/3 while in the question they have asked the fraction of pre-overhauling service time saved in latter case.
isn't the latter case the one which comes out to be 5/2 hrs
whts the latter case.....m i interpretating the question in the wrong way!!!!!!!!?????????
please clear this last doubt also
Thanx in advance :)
@nyancat said:fraction nikalana hai..need to get fraction amount saved
i got that bt i m little confused wth the sol'n given in the book.it isLCM of 90 and 120 = 360
So, in 360 days, the pre-overhauling service time = 5/6*360/90 = 10/3 hrs
and after overhauling,the service time = 5/6*360/120 = 5/2 hrs
Time saved = 10/3-5/2 = 5/6 hrs
therefore, the required answer = 5/6/10/3 = 1/4
i didn't get that why they hav divided 5/6 with 10/3 while in the question they have asked the fraction of pre-overhauling service time saved in latter case.
isn't the latter case the one which comes out to be 5/2 hrs
whts the latter case.....m i interpretating the question in the wrong way!!!!!!!!?????????
please clear this last doubt also
Thanx in advance
So, in 360 days, the pre-overhauling service time = 5/6*360/90 = 10/3 hrs
and after overhauling,the service time = 5/6*360/120 = 5/2 hrs
Time saved = 10/3-5/2 = 5/6 hrs
therefore, the required answer = 5/6/10/3 = 1/4
i didn't get that why they hav divided 5/6 with 10/3 while in the question they have asked the fraction of pre-overhauling service time saved in latter case.
isn't the latter case the one which comes out to be 5/2 hrs
whts the latter case.....m i interpretating the question in the wrong way!!!!!!!!?????????
please clear this last doubt also
Thanx in advance
they took solution by taking 360 days as reference..
I took solution by taking 90 days as reference
@nyancat said:@nam2aspirethey took solution by taking 360 days as reference..I took solution by taking 90 days as reference
thats ok but why divide 5/6 with 10/3 instead of 5/2 ???????
@scrabbler said:Also, long time no see ATDH sir!! Hi pal regardsscrabbler
Hi scrabbler sir.... was too busy with things around. Was missing PG action for quite a sometime now so back in the arena.
PG is an addiction and once addicted always addicted!
ATDH.
Ten students have been shortlisted to form two teams of six students each, such that there are exactly three common between the two teams, In how many ways can the teams be formed?
@Estallar12
is there a way to solve the firs one without chinese remainder ?
u have asked is it a or b ? It is b .
is there a way to solve the firs one without chinese remainder ?
u have asked is it a or b ? It is b .
@joyjitpal said:Ten students have been shortlisted to form two teams of six students each, such that there are exactly three common between the two teams, In how many ways can the teams be formed?
10C3*7c3*4C3/2??
@joyjitpal said:Ten students have been shortlisted to form two teams of six students each, such that there are exactly three common between the two teams, In how many ways can the teams be formed?
Select the loner=10 ways, select common people 9C3, select people for one group 6C3/2 (dividing by two to avoid double counting). Multiplying everything =8400