@sam05 said:
humme bhul gaye :(
How many integer values of x and y are there such that 4x+3y=3 while mod(x)
Plz give answer along with explanation.
Plz give answer along with explanation.
@Exodia said:How many integer values of x and y are there such that 4x+3y=3 while mod(x)
4x = 3(1-y)
x = 3(1-y)/4
y=1,x=0
y=5,x=-3
y=9,x=-6
y=13,x=-9
.
.
.
y=497,x=-372
=> total = (372-0)/3 + 1 = 125 solutions
3y = 3-4x
y = (3-4x)/3 or y = 1 - 4x/3
x=3,y=-1
x=6,y=-5
x=9,y=-9
.
.
.
x=375,y=-497
=> total = (375-3)/3 + 1 = 125 solutions
So, total number of solutions = 125+125 = 250...
@sam05 said:
jo hukum sahaab!! I was getting myself geared up... but u tell me, u have got calls na?
EDIT: i WILL BE BACK after dinner....
@Exodia said:How many integer values of x and y are there such that 4x+3y=3 while mod(x)4x+3y=3x=0,y=1 satisfies.So general solution is of the form x=3t,y=1-4tNow for |3t|we have -166also for |1-4t|-500-499-124so total of 250 values of t
@Exodia said:How many integer values of x and y are there such that 4x+3y=3 while mod(x)4x + 3y = 3y = 3 - 4x/3x = 0.....y = 1x = 3.....y = -3...............................x = 375.....y = -499no. of solutions = (375 - 3)/3 + 1 = 125x = 0......y = 1x = -3.......y = 5x = -6......y = 9..................................x = -372.......y = 497no . of solutions = (497 - 1)/4 + 1 = 125total solutions = 125 + 125 = 250 ?
The area of triangle formed by the point (p,2-2p) , (1-p,2p) and (-4-p,6-2p) is 70 units. How many integral values of p are possible.?
A. 2 B. 3 C. 4 D. None of these
A. 2 B. 3 C. 4 D. None of these
@mailtoankit said:4x + 3y = 3y = 3 - 4x/3x = 0.....y = 1x = 3.....y = -3...............................x = 375.....y = -499no. of solutions = (375 - 3)/3 + 1 = 125 x = -3.......y = 5x = -6......y = 9..................................x = -372.......y = 497no . of solutions = (497 - 5)/4 + 1 = 124total solutions = 125 + 124 = 249 ?
bold wale mein ek miss kar diya aapne --> y=1,x=0 wala...
total 250 honge...
@bs0409 said:The area of triangle formed by the point (p,2-2p) , (1-p,2p) and (-4-p,6-2p) is 70 units. How many integral values of p are possible.?A. 2 B. 3 C. 4 D. None of these
i m gettin nly 1 integral value i.e 4???
@bs0409 said:The area of triangle formed by the point (p,2-2p) , (1-p,2p) and (-4-p,6-2p) is 70 units. How many integral values of p are possible.?A. 2 B. 3 C. 4 D. None of these
8p^2 + 4p - 144 = 0
only 1 integer value of p?? none of these??
@bs0409 said:The area of triangle formed by the point (p,2-2p) , (1-p,2p) and (-4-p,6-2p) is 70 units. How many integral values of p are possible.?A. 2 B. 3 C. 4 D. None of these
only 1 value ?
70 = 1/2 |(2p - 1)(4p - 6) - 5(2 - 4p)|
8p^2 + 4p - 144 = 0
2p^2 + p - 36 = 0
(p - 4)(2p + 9) = 0
p = 4 ?
@mailtoankit said:only 1 value ?70 = 1/2 |(2p - 1)(4p - 6) - 5(2 - 4p)|8p^2 + 4p - 144 = 02p^2 + p - 36 = 0(p - 4)(2p + 9) = 0p = 4 ?
How did you get this equation. I tried the matrix method...
@saurav205 said:How did you get this equation. I tried the matrix method...
yaar matrix method se hi aaye hai....
@saurav205 said:How did you get this equation. I tried the matrix method...
gt it by using d formula!!!
@saurav205 said:which formula??
area=1/2mod(x1(y2-y3)+x2(y3-y1)+x3(y1-y2)
aftr dis we get d equation as 2p^2+p=36
and solving dis we get p=4
aftr dis we get d equation as 2p^2+p=36
and solving dis we get p=4