@ScareCrow28 ya answer is 0 . sorry for late reply :)
@amresh_maverick said:Problem on chinese remainder theorem:Rem 128^500 when divided by 153
should be 67??
153 = 17*9
e(9) is 6
500%6 = 2
2^2%9 = 4
e(17) = 16
500%16 = 4
9^4%17 = 16
=> 9p+4 = 17q+16
or 67...
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Aur ques daalo bhailog.....aaj phadai karte hai.. :D
solve this series...4,20,24,6,2,8...
remb only 2 optn...other i forgt..
16
18...
@hari_bang said:solve this series...4,20,24,6,2,8...remb only 2 optn...other i forgt..1618...
this series i got in paxterra compny written exm..
@Logrhythm said:should be 67??153 = 17*9e(9) is 6500%6 = 22^2%9 = 4e(17) = 16500%16 = 49^4%17 = 16=> 9p+4 = 17q+16or 67...------------------------------------------Aur ques daalo bhailog.....aaj phadai karte hai..
i have a doubt
153 ko 3 *51 se spit kar sakte the kya
ya 9 aur 17 me isi liye split kiya kyu ki they are co prime to each other?
153 ko 3 *51 se spit kar sakte the kya
ya 9 aur 17 me isi liye split kiya kyu ki they are co prime to each other?
@joyjitpal said:i have a doubt153 ko 3 *51 se spit kar sakte the kyaya 9 aur 17 me isi liye split kiya kyu ki they are co prime to each other?
Must be co-prime while using CRT :)
@joyjitpal said:i have a doubt153 ko 3 *51 se spit kar sakte the kyaya 9 aur 17 me isi liye split kiya kyu ki they are co prime to each other?
to use CRT
if x is a*b
and remainder is ap+k = bq+l
then a and b should not have any factor common to them other than 1...
@joyjitpal said:i have a doubt153 ko 3 *51 se spit kar sakte the kyaya 9 aur 17 me isi liye split kiya kyu ki they are co prime to each other?
Very first point in my post above... :)
regards
scrabbler
regards
scrabbler
@hari_bang said:solve this series...4,20,24,6,2,8...remb only 2 optn...other i forgt..1618...
4
5*4 =20
20+4 = 24
24/4 =6
6-4 = 2
2*4 = 8
8+4 = 12..
Repetition of operators *, +, / and - with "4" ..
Ans 12 hai kya?
@ScareCrow28 said:45*4 =2020+4 = 2424/4 =66-4 = 22*4 = 88+4 = 12..Ans 12 hai kya?
First step is the only one which doesn't match...should have been 4*4 = 16. Or else 1st term should have been 5.
regards
scrabbler
regards
scrabbler
@scrabbler said:First step is the only one which doesn't match...should have been 4*4 = 16. Or else 1st term should have been 5.regardsscrabbler
Yeah! I guess, only he would tell! You are absolutely correct ( As Always )@ScareCrow28 said:45*4 =2020+4 = 2424/4 =66-4 = 22*4 = 88+4 = 12..Repetition of operators *, +, / and - with "4" ..Ans 12 hai kya?
@scrabbler said:First step is the only one which doesn't match...should have been 4*4 = 16. Or else 1st term should have been 5.regardsscrabbler
such questions have frail logic, don't you guys think?? hence they don't appear in any of the bade wale exams ie CAT,XAT et al
@Logrhythm said:such questions have frail logic, don't you guys think?? hence they don't appear in any of the bade wale exams ie CAT,XAT et al
Actually, they can make better questions in series! It's useless to make whatever they want! I can make a series question which no one may be able to solve! Possibilities are immense 
@amresh_maverick said:Problem on chinese remainder theorem:Rem 128^500 when divided by 153
9k+4 = 17l+16
we get the first common term as 67..
hence 67 should be the remainder..
One from my side :
Options are :
50
60
70
80
90
Question 2 :
Question 3 ;
options are :
9
11
12
15