1> Rem when 17^36 + 19^36 is div by 111
2>Rem when 6^83 + 8^83 is div by 49
@amresh_maverick said:1> Rem when 17^36 + 19^36 is div by 1112>Rem when 6^83 + 8^83 is div by 49
seems everybody is off to sleep , posting the OA
OA :
1> 2
2>35
OA :
1> 2
2>35
@raopradeep said:find the number of terms in the expression (a+b+c+d)^201671177117177171
23C3 = 1771
@amresh_maverick said:seems everybody is off to sleep , posting the OAOA :1> 22>35
sir jee solution please??
@raopradeep said:find the number of terms in the expression (a+b+c+d)^201671177117177171
23c3 hoga....too 
to calculate right now...
to calculate right now...
find the number of terms in the expression (1+x+x^2+x^3+x^4)^7
@amresh_maverick said:find the number of terms in the expression (1+x+x^2+x^3+x^4)^7
@saurav205 said:11c4 ??
find the number of terms in the expression (a1+a2+a3+.....+an)^m
No of terms = m+n-1 C n-1
find the number of terms in the expression (1+x+x^2+x^3+x^4+.....x^n)^m
No of terms = m*n +1
The purpose of giving this question :)
@amresh_maverick said:find the number of terms in the expression (a1+a2+a3+.....+an)^mNo of terms = m+n-1 C n-1find the number of terms in the expression (1+x+x^2+x^3+x^4+.....x^n)^mNo of terms = m*n +1The purpose of giving this question
Logic kya hai??
@joyjitpal said:iska solution koi batao
i dint understand the solution and so posted..hope everyone had a great time squeezing their heads 
i have never seen such an ugly camel
anyone from banglore here
@amresh_maverick said:1> Rem when 17^36 + 19^36 is div by 1112>Rem when 6^83 + 8^83 is div by 49
1) 111 = 37*3
remainder by 37 = 2
remainder by 3 = 2
remainder by 111 = 2
2) 6^84 mod 49 = 1
R*6 mod 49 = 1
=> R = 41
=> R = 41
R*8 mod 49 = 1
=> R = 43
remainder by 49 = (41 + 43) mod 49 = 35
@pavimai said:Abdullah, a trader had 3000 bananas with him and he had to take them to a market 1000 km away on his only camel, which can carry a maximum of 1000 bananas at a time. Unfortunately, the camel eats one banana for every 1 km, or a part thereof, that it travels while carrying the bananas. What is the maximum number of bananas that Abdullah can take to the market?467533767833
General approach for this problem is
Divide 3000 by maximum limit which is 1000 ,Result is 3
so split 3000 in 1000's
P1 ,P2,P3
P1-- to move 3000
to move 1km 5 bananas
1000/5 which is 200 it has to travel
1. Move forward with 1000 bananas – Will eat up 1 banana in the way forward
2. Leave 998 banana after 1 km and return with 1 banana – will eat up 1 banana in the way back
3. Pick up the next 1000 bananas and move forward – Will eat up 1 banana in the way forward
4. Leave 998 banana after 1 km and return with 1 banana - will eat up 1 banana in the way back
5. Will carry the last 1000 bananas from point a and move forward – will eat up 1 banana
Note: After point 5 the camel does not need to return to point A again.
So to shift 3000 bananas by 1km Camel will eat up 5 bananas.
After moving to 200 km the camel would have eaten up 1000 bananas and is now left with 2000 bananas.
P2---to move 2000
to move 1km 3 bananas
so divide 1000/3 kms it can travel
by spending 1000 bananas
P2---to move 1000
remaining distance is 1000-533 1/3
bananas left is 1000-1000+533 1/3 which is 533 1/3
Note : If Bananas can not be used in fractions then it is 533
Divide 3000 by maximum limit which is 1000 ,Result is 3
so split 3000 in 1000's
P1 ,P2,P3
P1-- to move 3000
to move 1km 5 bananas
1000/5 which is 200 it has to travel
1. Move forward with 1000 bananas – Will eat up 1 banana in the way forward
2. Leave 998 banana after 1 km and return with 1 banana – will eat up 1 banana in the way back
3. Pick up the next 1000 bananas and move forward – Will eat up 1 banana in the way forward
4. Leave 998 banana after 1 km and return with 1 banana - will eat up 1 banana in the way back
5. Will carry the last 1000 bananas from point a and move forward – will eat up 1 banana
Note: After point 5 the camel does not need to return to point A again.
So to shift 3000 bananas by 1km Camel will eat up 5 bananas.
After moving to 200 km the camel would have eaten up 1000 bananas and is now left with 2000 bananas.
P2---to move 2000
to move 1km 3 bananas
so divide 1000/3 kms it can travel
by spending 1000 bananas
P2---to move 1000
remaining distance is 1000-533 1/3
bananas left is 1000-1000+533 1/3 which is 533 1/3
Note : If Bananas can not be used in fractions then it is 533
Find fifth digit from the end of 5^(5^(5^(5^5)))
Acc. to a plan a drilling team had to drill a depth of 270 mtrs. below the ground level. For the first 3 days the team drilled as per the plan. However subsequently finding that their resources were getting underutilized acc. to the plan, it started to drill 8 more mtrs. than the plan every day. therefore the day before the planned date they had drilled to a depth of 280 mtrs. how many mtrs of drilling was the plan for each day.
plz help....
Acc. to a plan a drilling team had to drill a depth of 270 mtrs. below the ground level. For the first 3 days the team drilled as per the plan. However subsequently finding that their resources were getting underutilized acc. to the plan, it started to drill 8 more mtrs. than the plan every day. therefore the day before the planned date they had drilled to a depth of 280 mtrs. how many mtrs of drilling was the plan for each day.ANS 30