The number of ways in which the letters of the word “PROGRESSION” can be arranged such that the letter R is always after (not necessarily immediately after) the letter N in the word, is
(1) 10!/8
(2) 10!/2!(8)
(3) 11!/24
(4) 9!/(2!)(2!)
The number of ways in which the letters of the word “PROGRESSION” can be arranged such that the letter R is always after (not necessarily immediately after) the letter N in the word, is
(1) 10!/8
(2) 10!/2!(8)
(3) 11!/24
(4) 9!/(2!)(2!)
ABCD is a parallelogram with ∠ABC=60°. If the longer diagonal is of length 7 cm and the area of the parallelogram ABCD is 15(_/3/2) sq cm. then the perimeter of the parallelogram (in cm) is -1515root31616root3
ABCD is a parallelogram with ∠ABC=60°. If the longer diagonal is of length 7 cm and the area of the parallelogram ABCD is 15(_/3/2) sq cm. then the perimeter of the parallelogram (in cm) is -1515root31616root3
- In triangle ABC,angle B=90,AB = 80,BC = 60. Point D is on AC. Perimeter of ABD = BCD.Length of BD=?
Three guys rent a hotel room for the night. when they get to the hotel they pay the $30 fee, then go up to their room. soon the bellhop brings up there bags and gives the lawyers back $5 bcoz the hotel was having a special discount that weekend. so the three lawyers decide to each keep one of the $5 and to give the bellhop a $2 tip. however when they sat down to tally up their expenses for the weekend they made the following calculation-
each one of them had originally paid $10(towards the initial $30), then each got back$1 which meant that they each paid $9. then they gave the bellhop a $2 tip. however, 3*$9 + $2= $29.
the guys couldn't figure out what happened to the one dollar. after all, the three paid out $30 but could only account for $29.
can u determine what happened?😃
For a scholarship, at the most n candidates out of 2n + 1 can be selected. If the number of different ways of selection of at least one candidate is 63, the maximum number of candidates that can be selected for the scholarship is ?
A triangle ABC is right angle at C. The medians to the sides AC and CB intersect at F. Find the ratio of the area of triangle AFB to that of quadrilateral CDFE.
A triangle ABC is right angle at C. The medians to the sides AC and CB intersect at F. Find the ratio of the area of triangle AFB to that of quadrilateral CDFE.
@mehulpahuja1 solution in the attachment.
Number of positive integral solutions of the equation: (1/x)+(1/y)=(1/N!)
AC = diameter of a circle.
B and D are points on the circumference such thatGiven hat the perimeter of quadrilateral ABCD = 20 ,find the radius of the circle
If (y+z-x)/x , (x+z-y)/y and (x+y-z)/z are in arithmetic progression (A.P.) , then which of the following are in the A.P.?
please help me with this question puys!!!!
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Each of the following ffive statements is either true or false.
(1) Statements (3) and (4) are both true.
(2) Statements (4) and (5) are not both false.
(3) Statement (1) is true.
(4) Statement (3) is false.
(5) Statements (1) and (3) are both false.
How many of statements (1) - (5) are true?
Let T = {0,1,2,3,5,7,11}. How many diffu000berent numbers can be obtained as the sum of three difu000bferent members of T?
“My two sisters, all of my children and my younger brother and I were born between Jan. 1, 1901 and Dec. 31, 1999, each of us in a diffu000berent year. Oddly, we all satisfy a very peculiar property. Each of us turned yx in some year 19xy where 0 0 has one of my children turned yx?”
There are 360 students in an assembly on the eve of christmas. They were asked to stand in a rows and columns, such that each row had equal number of students. Now, santa started distributing toffees in a typical manner, where he would gift a toffee to exactly one student in each row in the first round. In the second round, he would gift a toffee to exactly one student in each column.
1. If 337 students did not received any toffee, then how many toffees did santa distribute in all?
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