S visits a place in between 10 pm to 12 moon and stays there for 10 minutes A's friend visit this place in between 10 pm and 11 pm and stays there for 15 minutes. What's the probability that they will be there at the same time ?
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if two dice are thrown together, the probability of getting an even no. on one dice and an odd no. on other dice is?
pls explain your answer...
if four coins are tossed the probability of getting two heads and two tails is?
pls explain your answer.....
S was born on may 27 1995 ,the same year independance day is celebrated as tuesday.On which day S was born?
NOTE: a similar cat 2014 ques 😛
what is the remainder of (19!+86) when divided by 289?
Find the number of perfect square divisors of (1!*2!*3!*4!...*8!)
On which year the calendar year 2005,will repeat itself?
1)20014
2)2010
3)2011
4)2017
If f(2, 7) = 57 and f(1, 6) = 37, what is the value of f(3, 10)?(1)107 (2)127 (3)147 (4)None of these
In a milk and water solution of 300 lt there is 10% water? how much water should be added to the mixture so that water becomes 25%?
I want to know how this question can be done with allegations
a,b,c are all non negative integers then how many such triplets are there such that 1000a+300b+50c=10000 and a+b+c=100?
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In figure ABCD is square. Find the value of GQ in attached image. I don't have OA.
#Condition for two months in a year having a same calender.
**Two months will have the same calender if the period(no. of days between the two months) between them is divisible by 7.
Now, for example
(a) Case 1: June, October
June + July + Aug. + Sep. = 30 + 31 + 31 + 30 = 122 (not divisible by 7)
(b) Case 2: April, November
Apr. + May + June + July + Aug. + Sep. + Oct. = 30 + 31 + 30 + 31 + 31 +30 + 31 = 213 (not divisible by 7)
(c) Case 3: April, July
Apr. + May + June = 30 + 31 + 30 = 91 (divisible by 7)
(d) Case 4: October, December October + November = 31 + 30 = 61 (not divisible by 7)
Now, in only case 3, the period is divisible by 7. Hence April and July have the same calender.
Method 2: Another method is to find the odd days for each month in the period and add them. If the sum is divisible by 7, then the two months have the same calender.
Note: In a given period, the number of days more than the complete weeks are called odd days.
For a month with 30 days, odd days will be 2 [7*4 + 2] ,
For a month with 31 days , odd days will be 3 [7*4+3]
(a) Case 1: June, October
June + July + Aug. + Sep. = 2 + 3 + 3 + 2 = 10 (not divisible by 7)
(b) Case 2: April, November
Apr. + May + June + July + Aug. + Sep. + Oct. = 2 + 3 + 2 + 3 + 3 +2 + 3 = 18 (not divisible by 7)
(c) Case 3: April, July
Apr. + May + June = 2 + 3 + 2 = 7 (divisible by 7)
(d) Case 4: October, December October + November = 3 + 2 = 5 (not divisible by 7)
Hence answer is April, July.
Hey fellows, solve this one 😃
AB = AC = 6 are the 2 chords of a circle with radius 5. Find BC.
Options = 24/5, 12/5, 7/5 and NOT
the no 2006! is written in base 22.how many zeroes are there at the end??
500
450
200
199
nota??
101x10001x10000000001x.....x(1000...01) where the last factor has 2^7 -1 zeros between the ones. Find the number of ones in the product .
A leaf is torn form a paper back novel . The sum of the remaining pages is 15000. What are the page numbers on the torn leaf ?
Determine the integer 'n' for which n²+19n+92 is a perfect square .
25! when divided by 10^7 gives remainder??
4*10^6
2*10^6
6*10^6
nota..