agar kisi ka exam baki hao to yeh lo
NICL Final Result for Recruitment of Assistant out
State-wise List of Candidates selected for Interview for the Recruitment of Assistants in 4 PSU General Insurance Companies
- See more at: http://sapaliga.com/nicl-final-result-recruitment-assistant/
Learn the difference between marketing and branding....
Here the article on Marketing and Branding to gear you up for upcoming sessions of WAT/GD and PI. The terms Marketing and Branding are two different terms. The differences between these two confusing terms are as follow: Branding is why. Marketing is how. Branding is long term. Marketing is...
how to remember days for po exam
anyone plz help me how to remember capital's of all the countries. anu one plz helpme
yaar ek baat batao, is there a huge difference between RRB PO and PO in a Nationalised banks?
Can somebody elaborate about the growth prospects in RRBs? and the payscale revision is appplicable to rrbs?
hi puys, really tensed abt the gk part can someone tell me what wud be the approximate safe no of attempts to atleast reach the cutoff.
anyone plz help me how to remember capital's of all the countries. anu one plz helpme
Random acts of kindness , such a wonderfulthing 😃
There s no denying that the world is full of cruel, evil people capable of things you probably couldn t even imagine. We see it on the news pretty much every day. But believe it or not, there s a lot more good and kindness out there than you probably realize.
whn will the result of ibps cum?
20 years from now you will be disappointed by the things you didn't do than by the one's you did. So throw off the bowlines. Sail away from the safe harbor. Catch the trade winds in your sails. Explore. Dream. Discover.....👼👼👼👼👼👼👼👼👼👼
how to remember all the days for po exam any one help me plz
The average of 30 boys of a class is equal to 14 yrs. When the age of the class teacher is included the average becomes 15 yrs. Find the age of the class teacher.
(1) 45 yrs (2) 50 yrs
(3) 30 (4) 22 yrs
2.The average weight of 4 men is increased by 3kg when one of them who weighs 120 kg is replaced by another man. What is the weight of the new man?
(1) 125 kg (2) 150 kg
(3) 122 kg (4) 132 kg
3.The average of marks obtained by 120 candidates in a certain examination is 35. If the average marks of passed candidates is 39 and that of the failed candidates is 15, what is the number of candidates who passed the examination?
(1) 90 (2) 85
(3) 100 (4) 120
4.The average of 11 results is The average of 11 results is50. If the average of first six results is 49 and that of last six is 52, find the sixth result?
(1) 45 (2) 46
(3) 55 (4) 56
5.A bats man is his 17th innings makes a score of 85, and thereby increases his average by 3. What is his average after 17 innings?
(1) 40 (2) 36
(3) 37 (4) 38
6.A train travels from A to B at the rate of 20kmper hour and from B to A at the rate of 30 km/hr. What is the average rate for the whole journey?
(1) 24 km/hr (2) 25 km/hr
(3) 26 km/hr (4) 28 km/hr
7.The average salary of the entire staff in a office is Rs 120 per month. The average salary of officers is Rs 460 and that of non- officers is Rs 110. If the number of officers is 15, then find the number of non – officers in the office.
(1) 500 (2) 510
(3) 520 (4) 550
8.There were 35 students in a hostel. If the number of students increases by 7, the expenses of the mess increase by Rs. 42 per day while the average expenditure per head diminishes by Rs1. Find the original expenditure of the mess.
(1) Rs. 400 (2) Rs. 340
(3)Rs. 420 (4)Rs. 450
ANSWERS WITH SOLUTION:
1.Total ages of 30 boys = 14 x 30 = 420 yrs.
Total ages when class teacher is included = 15 x 31 = 465 yrs
Age of class teacher = 465 – 420 = 45 yrs.
Shortcut :
Age of new entrant = New average + No. of old members x increase in average
2.If the average is increased by 3 kg, then sum of weights increases by 3 x 4 = 12 kg .
And this increase in weight is due to the extra weight included due to the inclusion of new person.
Weight of new man = 120 + 12 = 132 kg.
3.Let the number of passed candidates be x. then total marks = 120 x 35 = 39x + ( 120 – x ) x 15 or, 4200 = 39x + 1800 – 15x
or, 24x = 2400 So x = 100
4.The total of 11 results = 11 x 50 = 550
The total of first 6 results = 6 x 49 = 294
The total of last 6 results = 6 x 52 = 312
The 6th result is common to both;
Sixth result = 294 + 312 - 550 = 56
5.Let the average after 16th innings be x, then 16x + 85
= 17 ( x + 3 ) = Total score after 17th innings.
x = 34
average after 17 innings = x + 3 = 34 + 3 = 37
6.By the formula : average speed = (2 x 20 x 30) / (20 + 30) = 24 km/hr
7.Let the required number of non – officers = x
Then, 110x + 460 x 15 = 120 ( 15 + x )
or, 120 x – 110 x = 460 x 15 – 120 x 15 = 15 ( 460 – 120 )
So, x = 510
8.Suppose the average join the mess , total expenditure = 35x + 42
Now, the average expenditure = (35x + 42)/ (35 + 7) = x – 1
or, 35x + 42 = 42x – 42
or, x = 12
Thus the original expenditure of the mess = 35 x 12 = Rs. 42
Read more:
http://www.bankersadda.com/2013/09/quant-quiz-on-average-with-solution.html#ixzz2jyj8XhzA
Formulae
(i) Speed = Distance/Time
(ii) x km/hr = (x × 5/18 ) m/sec.
(ii) x metres / sec = (x × 18/5 )km/hr.
1.A man covers a certain distance between his house and office on scooter.Having an average speed of 30 km/hr, he late by 10 min. However, with a speed of 40 km/hr. he reaches his office 5 min earlier. Find the distance between his house and office.
(1) 20 km (2) 40 km
(3) 30 km (4) 25 km
2.A man car does a journey in 10 hrs, the first half at 21 km/hr and the second half at 24 km/hr. Find the distance.
(1) 220 km (2) 215 km
(3) 210 km (4) 224 km
3.Walking 3/4 of his usual speed, a person is 10 min late to his office. Find his usual time to cover the distance.
(1) 10 minutes (2) 50 minutes
(3) 30 minutes (4) None of these
4.Running 4/3 of his usual speed, a person improves his timing by 10 minutes. Find his usual time to cover the distance.
(1) 60 minutes (2) 40 minutes
(3) 25 minutes (4) 30 minutes
5.A train travelling 25 km an hour leaves Delhi at 9 a.m. and another train travelling 35 km an hour starts at 2 p.m. in the same direction. How many km from Delhi will they be together?
(1) 437 ½ km (1) 436 ½ km
(3) 435 ½ km (4) 434 ½ km
6.Two men A and B walk from P to Q, a distance of 21 km, at 3 and 4 km an hour respectively. B reaches Q, returns immediately and meets A at R. Find the distance from P to R.
(1) 18 km (2) 20 km
(3) 35 km (4) 15 km
7.A man sets out to cycle from Delhi to Rohtak, and at the same time another man starts from Rohtak to cycle to Delhi. After passing each other they complete their journeys in 3 1/3and 4 4/5hours respectively. At what rates does the second man cycle if the first cycles at 8 km per hour?
(1) 6 2/3 (2) 5 2/3
(3) 4 2/3 (4) None of these
8.A monkey tries to ascend a greased pole 14 metres high. He ascends 2 metres in first minute and slipsdown 1 metre in the alternate minute. If he continues to ascend in this fashion, how long does he take to reach the top?
(1) 25 minutes (2) 20 minutes
(3) 15 minutes (4) None of these
9.A man leaves a point P at 6 a.m. and reaches the point Q at 10 a.m. Another man leaves the point Q at 8 a.m. and reaches the point P at 12 noon. At what time do they meet?
(1) 10 a.m. (2) 9 a.m.
(3) 9: 30 a.m. (4) 8 a.m
10.Without any stoppage a person travels a certain distance at an average speed of 80 kmph, and with stoppages he covers the same distance at an average of 60 kmph. How many minutes per hour does he stop?
(1) 25minutes (2) 15 minutes
(3) 10 minutes (4) None of these
Answers with Solution:
1.(3) :
Solution: Let the distance be x km.
Time taken to cover x km at 30 km/hr = x/30 hrs
Time taken to cover x km at 40 km/hr = x/ 40 hrs.
Difference between the time taken = 15 min = ¼ hr.
x/30 – x/40 = ¼ or 4x – 3x = 30 or x = 30 km.
Shortcut: (Try this your self)
Required distance
= Product of two speeds/ Difference of two speeds x Difference between arrival times.
2.(4)
Solution:
Let the distance be x km.Then x/2 km is travelled at a speed of 21 km/hr and x/2 km at a speed of 24 km/hr.
Then time taken to travel the whole journey
= x/(2x21) + x/(2 x 24) = 10 hrs.
so, x = 224 km
Short cut : (Try this your self)
Distance =(2 x Time x S1 x S2 ) / (S1 + S2 )
Where , S1 = Speed during first half and
S2 = Speed during second half of journey
3.(3) :
Solution:
Let the usual time be x min.
Time taken at ¾ of the usual speed = 4x/3 min
4x/3 – x = 10
x/3 = 10 à x = 30 min.
Shortcut : (Try this your self)
Usual time = Late time / ( 1 ÷ ¾ - 1) = 10/1/3 = 30 minutes
4.(2) Shortcut:
Improved time / (1 - 1 + 4/3 ) = 40 minutes
5.(1) :
Solution:
The first train has a start of 25 / 5 km and the second train gains ( 35 – 25 ) or 10 km per hour.
The second train will gain 25 x 5 km in (25 x5) / 10 or 12 ½ hours.
The required distance from Delhi = 12 ½ x 35 km = 437 ½ km
Shortcut : (try this )
Meeting point's distance from starting point
= (S1 x S2 x Difference in time) / Difference in speed ( S1 and S2 are the speed )
6.(1)
Solution:
When B meets A at R, B has walked the distance PQ + QR and A the distance PR. That is , both of them have together walked twice the distance from P to Q, i.e 42 km.
Now the rates of A and B are 3 : 4 and they have walked 42 km.
Hence the distance PR travelled by A = 3/7 of 42 km = 18 km
7.(1)
Solution:
If two persons ( or train) A and B start at the same time in opposite directions from two points and arrive at the pint a and b hrs respectively after having met, then
A's rate : B's rate = √b : √a
= (√ 4 4/5 ) / ( √3 1/3 ) = 6/5
2nd man's rate = 5/6 x 8 = 6 2/3 km/hr.
8.(1)
Solution:
In every 2 minutes he is able to ascend 2 – 1 = 1 metre. This way he ascends upto 12 metres because when he reaches at the top. He does not slip down. thus, upto 12 metres he takes 12 x 2 = 24 minutes and for the last 2 metres he takes 1 minutes. Therefore he takes 24 + 1 = 25 minutes to reach the top.
9.(2)
Solution:
Let the distance PQ = A km.
And they meet x hrs after the first man starts.
Average speed of first man = A/10 – 6 = A /4 km/hr
Average speed of second man = A / 12 – 8 = A / 4 K/hr.
distance travelled by first man = Ax/4 km
They meet x hrs and the first man starts. The second man, as he starts 2 hrs late, meets after ( x- 2 ) has from has start. Therefore, the distance travelled by the second man = A(x-2) / 4 km
Now , Ax/4 + A (x-2) /4 km = A
x = 3 hrs.
They meet at 6 a.m. + 3 hrs = 9 a.m.
Shortcut: (Try this your self)
= Starting time + [ ( Time taken by first ) (2nd's arrival time – 1st starting time ) ] / (sum of time taken by both)
10.(1)
Solution:
Let the total distance be x km.
Time taken at the sped of 80 km/hr = x/80 hrs.
Time taken at the sped of 60 km/hr = x/60 hrs.
He rested for ( x/60 – x/80) hrs = 20x / 60 x 80 = x/240 hrs.
his rest per hour = x/240 ÷ x/60 = ¼ hrs. = 15 minutes.
Read more:http://www.bankersadda.com/2013/09/quant-quiz-time-and-distance-with.html#ixzz2jyjUl0t0
1. A certain sum of money lent out at S.I. amounts to Rs. 690 in 3 years and Rs. 750 in 5 years. The sum lent is
(1) Rs. 500 (2) Rs. 600
2. The rate at which a sum becomes four times of itself in 15 years at S.I. will be:.
(1) Rs. 15% (2) Rs% 20
(3) Rs. 25 (4) Rs. 10 %
3. A sum of money at simple interest amounts to Rs. 2240 in 2 years and to Rs. 2600 in 5 years. What is the principal amount?.
(1) Rs. 2000 (2) Rs. 1900
(3) Rs. 2100 (4) Rs. 2150
4. The simple interest on a certain sum of money at the rate of 5% p.a. for 8 years is Rs. 840. At what rate of interest the same amount of interest can be received on the same sum after 5 years ?. [S
(1) 5% (2) 10 %
(3) 7 % (4) 8 %
5. If a sum of money doubles itself in 8 years at simple interest, the ratepercent per annum is
(1) 10.5 (2) 12.5
(3) 9.5 (4) 13.5
6. Ashok took a loan of Rs. 15000 for 3 years at simple interest. If the total interest paid is R. 2700, what is the rate of interest per annum?.
(1) 4 % (2) 5 %
(3) 6 % (4) 7 %
7. Ram borrowed Rs. 5000 from Sanjay at simple interest. After 3 years, Sanjay got Rs. 300 more than what he had given to Ram . What was the rate of interest per annum '?.
(1) 2 % (2) 4 %
(3) 6 % (4) 8 %
8.Ram took a loan of Rs. 1200 with simple interest for as many years as the rate of interest. If he paid Rs. 432 as interest at the end of the loan period, what was the rate of interest?
(1) 6 (2) 5
(3) 4 (4) 8
9.A certain amount earns simple interest of Rs. 1750 after 7 years. Had the interest been 2% more, how much more interest would it have earned?
(1) Rs. 40 (2) Rs. 50
(3) Rs. 30 (4) Cannot be determined
10.A person borrows Rs. 5000 for 2 years at 4% p.a. simple interest. He immediately lends it to another person at 6 ¼ p.a for 2 years. Find his gain in the transaction per year.
(1) Rs. 111.50 (2) Rs. 113.50
(3) Rs. 110.50 (4) Rs. 112.50
ANSWERS:
1
2
2
2
3
1
4
4
5
2
6
3
7
1
8
1
9
4
10
4
1. A man can row 18 kmph in still water. It takes him thrice as long to row up as to row down the river. Find the rate of stream.
(1) 7 km/h (2) 5 km/h
(3) 8 km/h (4) 9 km/h
2.A man rows downstream 32 km and 14 km upstream. If he takes 6 hours to cover each distance, then the Velocity (in kmph) of current is:
(1) 1/2 (2) 3/2
(3) 2 (4) 5/2
3.A man can row at 5 kmph in still water. If the velocity of current is 1 kmph and it takes him 1 hour to row to a place and come back, how far is the place?
(1) 1.5 km (2) 2.5 km
(3) 3.5 km (4) 1 km
4.A man can row 40 km upstream and 55 km downstream in 13 hours. Also, he can row 30 km upstream and 44 km downstream in 10 hours. Find the speed of the man in still water and the speed of the current.
(1) 5 (2) 3
(3) 6 (4) 4
5.In a stream running at 2 kmph, a motorboat goes 6 km upstream and back again to the starting point in 33 minutes. Find the speed of the motorboat in still water.
(1) 22 km/hr (2) 20 km/hr
(3) 25 km/hr (4) 18 km/hr
6.A man takes 3 hours 45 minutes to row a boat I5 km downstream of a river and 2 hours 30 minutes to cover a distance of 5 km upstream. Find the speed of the river current in km/hr.
(1) 1 km/hr (2) 2 km/hr
(3) 3 km/hr (4)4 km/hr
7.A person can row a boat d km upstream and the same distance downstream in 5 hours 15 minutes. Also, he can row the boat 2d km upstream in 7 hours. How long will it take to row the same distance 2d km downstream?
(1) 3/2 hours (2) 7 hours
(3) 7 ( ¼) (4) 7/2 hours
8.A man swimming in a stream which flows 1.5 kmph, finds that in a given time he can swim twice as fast with the stream as he can against it. At what rate does he swim?
(1) 4 km/hr (2) 4.5 km/hr
(3) 6 km/hr (4) 7 km/hr
9.a motorboat in still water travels at a sped of 36 kmpn. It goes 56 km upstream in 1 hour 45 minutes. The time taken by it to cover the same distance down the stream will be:
(1) 2 hours 25 minutes (2) 3 hours
(3) 1 hour 24 minutes (4) 2 hours 21 minutes
10. A man can row 6 km/h in still water. If the speed of the current is 2 km/h, it takes 3 hours more in upstream than in the downstream for the same distance.
(1) 30 km (2) 24 km
(3) 20 km (4) 32 km
ANSWER WITH EXPLANATION:
1.Answer: (4)
Explanation:
Let man's rate upstream be x kmph.
Then, his rate downstream = 3x kmph
Rate in still water = 1/2 (3x + x) kmph = 2x kmph
So, 2x = 18 or x = 9
Rate upstream = 9 km/hr, Rate downstream = 27 km/hr
Hence, rate of stream = 1/2 (27 – 9) km/hr = 9 km/hr
2.Answer: ( 2)
Explanation:
Rate downstream = 32/6 kmph; Rate upstream = 14/6 kmph
Velocity of current = 1/2 (32/6 - 14/6) kmph
= 3/2 kmph = 1.5 kmph
3.Explanation: (2)
-Speed downstream = (5 + 1) kmph = 6 kmph.
Speed upstream = (5 – 1) kmph = 4 kmph.
Let the required distance be x km.
Then, x/6 + 4/4 = 1
2x + 3x = 12
5x = 12
x = 2.5 km.
4.Answer: (2)
Explanation:Let rate upstream = x km / hr and rate downstream = y km / hr. Then, 40/x+ 55/y =13 ...(i)
and 30/x+44/y=10 ...(ii)
Multiplying (ii) by 4 and (i) by 3 and subtracting, we get :
11/y=1 or y=11.
Substituting y = 11 in (j), we get : x = 5.\threrefore Rate in still water =
1/2(11+5)kmph=8kmph.
Rateofcurrent= 1/2(11−5)kmph=3kmph.
5.Answer: ( 1 )
Explanation: Let the speed of the motorboat in still water be x kmph. Then,Speed downstream = (x + 2) kmph; Speed upstream = (x - 2) kmph. 6/x+2+6/x−2 = 33/60
11x2−242x+2x−44=0
«=> (x - 22) (11x + 2) = 0 x = 22. Hence, speed of motorboat in still water = 22 kmph.
6.Answer : (1) Explanation:Rate downstream=15334 km/hr
=15×415km/hr=4km/hr.
Rate upstream=(5212) km/hr
=(5×25)=2km/hr
Speed of current=12(4−2)km/hr=1km/hr.
7.Answer: (4)
Explanation: Let the speeds of boat and stream be x and y km/hr respectively.
Then, Rate downstream = (x + y) km/hr and Rate upstream = (x - y) km/hr
Given d / (x+y) + d / ( x-y ) =5 hrs 15 minutes = 21/4 hours
and 2d / (x+y) = 7 => d / (x+y)=7/4 => 2d / (x+y)=7/2
Hence, he takes 7/2 hours to row 2d km distance downstream.
8.Answer : (2)
Explanation: Rate of stream =1.5 km/hr
Let speed of man in still water = x km/hr and Distance = d
Upstream speed = (x - 1.5) km/hr Downstream speed = (x + 1.5) km/hr
Given, 2d / (x+1.5) = d/ (x-1.5) => 2x - 3 = x + 1.5 => x = 4.5 km/hr
9.Answer: ( 3)
Explanation : Speed of the motorboat upstream
= 56km/1 ¾ hours
=32 kmph
Let the speed of the current = x kmph
36 – x = 32
à 36 – 32 = 4 kmph
speed of motorboat down stream = 36 + 4 = 40 kmph
Time taken to cover 56 km at 40 kmph = 56/40 = 7/5 hours
= 1 hour 24 minutes
10.Answer: (2)
Explanation: Let he required distance be x km.
x/6-2 + x/ 6 + 2 = 3
à x/4 – x/8 = 3
à 2x –x/8 = 3
= x=3 x 8 = 24 km.
Read more:http://www.bankersadda.com/2013/07/quant-quiz-boats-and-streams.html#ixzz2jymLl75R
Which device can understand the difference between data and programs?
(1) Input device
(2) Output device
(3) Memory
(4) Microprocessor
(5) None of these
2.Which command is used to open (open) dialogue box?
(1) F12
(2) Shift+F12
(3) Alt+F12
(4) Ctrl+F12
(5) None of these
3.The pattern of printed lines on most products are called-
(1) prices
(2)OCR
(3) scanners
(4) barcodes
(5)None of these
4.The main advantage of magnetic disk compared to magnetic tape is
(1) low cost
(2) rigidity
(3) direct access
(4) high packet density
(5) sequential access
5.To copy cell contents using drag and drop, press the:
(1) End key
(2) Shift key
(3) Esc key
(4) All of above
(5) None of these
6.To add two cells (A1 and A2) together you use which of the formula?
(1) = A1+ A2
(2) = Add (A1 + A2)
(3) = together (A1:A2)
(4) A1 + A2
(5) None of these
7.Which one is NOT shared by the threads of the same process?(1) Message Queue
(2) Address Space
(3) Stack
(4) Database
(5) None of these
8.The updating of master files to reflect the effects of current transactions is called?(1) Direct processing
(2) File processing
(3) Flow chart
(4) Front-end Processor
(5) None of these
9.One or more operations performed on data to achieve a desired objective is called?(1) Database
(2) Data processing
(3) Data collection
(4) Data communication
(5) None of these
10.The total set of interlinked hypertext documents worldwide is
(1) HTTP
(2) Browser
(3) WWW
(4) B2B
(5) None of these
ANSWERS:
1.
4
2.
4
3.
4
4.
3
5.
5
6.
1
7.
3
8.
2
9.
2
10.
3
Read more:http://www.bankersadda.com/2013/11/computer-quiz.html#ixzz2jynQ6BcW
Pick out the one which can substitute bold group of words correctly, without changing the meaning of the sentence.
1.If you have power or money you misuse and if you don't have it you yearn for it.
(1) you misuse it when you don't
(2) you misuse it and if you don't
(3) you misuse so that you don't
(4) you misuse and if you can't
2.With the number of vehicles on the roads going up fast, the traffic in the metros have become heavy and uncontrollable.
(1) has become heavily
(2) had become heavy
(3) have become heavily
(4) has become heavy
3.The tehelka.com revelations and their aftermath have shaked up entrenched political - bureaucratic networks in New Delhi
(1) its aftermath has shaken up
(2) their aftermaths have shaked up
(3) its aftermath has shook
(4) their aftermath have shaken up
4.The editor cut up all the long words from his article and mad the text easier.
(1) cut up some of the
(2) cut across all the
(3) cut out all the
(4) cut back all
5.The man is mortal and ultimately he has to leave everything here, yet how irrationally he remains attached to his worldly possessions.
(1) The man is immortal
(2) Man is considered to be mortal
(3) Man is mortal
(4) Though the man is mortal
6.I already thrice have read this story.
(1) I have already read this story thrice.
(2) I thrice have already read this story.
(3) I have thrice already read this story.
(4) I have already read thrice this story.
7.He has requested for an interview of the principal this morning
(1) an interview by the principal
(2) an interview with the principal
(3) the interview of the principal
(4) an interview from the principal
8.Can you tell me where does your uncle live?
(1) where your uncle does live
(2) whether your uncle does live
(3) where your uncle lives
(4) where lives your uncle
9.All the newcomers enjoyed at the welcome party.
(1) enjoyed in
(2) themselves enjoyed at
(3) enjoyed themselves
(4) enjoyed thoroughly at
10.This milk has got a funny taste – it can have gone sour.
(1) can go sour
(2) had soured
(3) can have gone sourly
(4) may have gone sour
Solutions:
1.(2)
Explanation: Misuse is a transitive verb; so it must have an object.
2.(4)
Explanation: Since subject-word traffic is singular, auxiliary have should also be replaced by singular has.
3.(4)
Explanation: The V3 of shake is shaken.
4.(3)
Explanation: If you cut out part of something that someone has written, you do not print it. Now, isn't that the job of an editor?
5.(3)
Explanation: Here no particular man is being talked about. What is being stated here holds good for every man.
6.(1)
Explanation: Note the positions of the adverbs.
7. (2)
Explanation: You have an interview with someone.
8.(3)
Note that the underlined part is a subordinate clause. And the subordinate clause is assertive, not interrogative.
9.(3)
Explanation: Enjoy is one of those verbs which take a reflexive pronoun when used reflexively.
10.(4)
Explanation: Note that here we are talking of probability, which is indicated by auxiliaries could and may.
Concept of percentage or Percentage formula
To express x% as a fraction: We have, x%x/100 Thus, 30%=30/100= 3/10
In simple terms we can conclude that percentage symbol "%" means 1/100
In case we are having a fraction and we have to calculate its percentage then we will multiply it by 100.that is,a/b=(a/b)×100)%
2.Increase or decrease in percentage with price
(1) If the price of a commodity increases by R%, then the reduction in consumption so as not to increase the expenditure will be = [R/ (100+R)×100]%
( 2) If the price of a commodity decreases by R%, then the increase in consumption so as not to decrease the expenditure will be = [R/(100−R)×100]
3.Results on populationFormula's on result of population are very important when we have to calculate the population n years after or n years before,Let the population of a town be P now and suppose it increases at the rate of R% per annum, then(1) Population after n years =P(1+R/100)n
(2) Population before n years =P/(1+R/100)n
4.Results on DepreciationWe know that value of a machine depreciate with time, so it will decrease with the time. To calculate the value of machine after n years or before n years, we use these formula's
Let the present value of a machine be P. Suppose it depreciates at the rate of R% per annum.(1) Population after n years = P(1−R/100)n
(2) Population before n years =P/(1−R/100)n
5.Important results for PercentageThe formulas we are going to mention below is same as of increase or decrease in consumption with increase or decrease in the commodity price, just here we are in a bit different context.(1) If A is R% more than B, then B is less than A by = [R/(100+R)×100]%
(2) If A is R% less than B, then B is more than A by = [R/(100−R)×100]%
QUESTIONS :
1.Two numbers are less than third number by 30% and 37% respectively. How much percent is the second number less than by the first
(1) 20% (2) 30 %
(3) 10% (4) 40%
2.In an examination, 34% of the students failed in mathematics and 42% failed in English. If 20% of the students failed in both the subjects, then find the percentage of students who passed in both the subjects.
(1) 40% (2) 41%
(3) 43% (4) 44%
3.In the new budget , the price of kerosene oil rose by 25%. By how much percent must a person reduce his consumption so that his expenditure on it does not increase ?
(1) 20% (2) 30%
(3) 22% (4) 24%
4.The value of a machine depreciates at the rate of 10% per annum. If its present is Rs.1,62,000.? What was the value of the machine 2 years ago ?
(1) 200000 (2) 20000
(3) 2000 (4) None of these
5.A student multiplied a number by 3/5 instead of 5/3. What is the percentage error in the calculation?
(1) 60% (2) 62%
(3) 64% (4) 65%
ANSWERS WITH EXPLANATIONS:
1.(3) : Let the third number is x.then first number = (100-30)% of x= 70% of x = 7x/10
Second number is (63x/100)Difference = 7x/10 - 63x/100 = 7x/10So required percentage is, difference is what percent of first number=> (7x/100 * 10/7x * 100 )% = 10%
2.(4) : Failed in mathematics, n(A) = 34Failed in English, n(B) = 42
n(AUB) = n(A) + n (B) – n (A∩ B )
= 34 + 42- 20 = 56Failed in either or both subjects are 56
Percentage passed = (100−56)%=44%
3.(1) : Reduction in consumption = [((R/(100+R))*100]%? [(25/125)*100]%=20%.
4.(1): Value of the machine 2 years ago= Rs.[162000/(1-(10/100)2)]=Rs.[162000*(10/9)*(10/9)]= Rs.200000
5.(3) : Let the number be x
Then, error = (5/3)x – (3/5)x =(16/15)x
Error% = [(16x/15) /(5x/3)] * 100% = 64%