GMAT Problem Solving Discussions

A jar contains 30 marbles, of which 20 are red and 10 are blue. If 9 of the marbles are removed, how many of the marbles left in the jar are red?

(1) Of the marbles removed, the ratio of the number of red ones to the number of blue ones is 2 : 1.
(2) Of the first 6 marbles removed, 4 are red.

A Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
B Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
C BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
D EACH Statement ALONE is sufficient.
E Statements (1) and (2) TOGETHER are NOT sufficient.

Statement A gives a ratio of 2:1. 6 red marble and 3 blue. 14 red are left in the jar. Statement 2 talks about first 6 marble. what bout the next 3. So not enough info to answer. Hence the answer is A.

Folks - just wanted to give everybody here a heads-up - Once we move to the new forum, I will be closing this thread down. It's anyway gotten way too long.

Once we move to the new section, what I'd like you to do is create a thread for each problem that you want to discuss. The title should follow the format - "Source" "Type" "Question Number" "Misc information"
So thread titles will now look like "OG12 DS #247" or "TIME PS #7 Book5Pg38"

Why I am doing this -
In this thread alone there are a ton of good problems that most likely nobody is ever going to read because it's buried too deep. And that's a serious waste. The new format allows somebody to more efficiently use the tags to find a particular solution rather than re-posting the question.

As always - open to suggestions and discussion.

The diagonal coordinates are 6,2 and 0,6. so these are 2 vertices.
Now the mod point of the diagonal joining these vertices = 3,4
and equation of line perpendicular to the diagonal and passing through 3,4 is 2y=3x-1
We are finding this equation because we want to find out the other two vertices and these vertices will lie on the other diagonal.
2y=3x-1 is the equation of other diagonal.

Now the slope of this diagonal = 3/2 =>sin(theta) = 3/sqrt(13)
cos(theta)=2/sqrt(13)
Now diagonal length = d=2xsqrt(13)
so other vertices will be given by
x-coordinate of mid point +/- ((d/2) x cos(theta))
y-coordinate of mid point +/- ( (d/2) x sin(theta))

that gives points as (0,1) and (6,7)
so nearest point is 0,1 and hence distance is 1 unit.

Is that the answer ???




Hi,
The step till equation of diagonal 2y=3x-1 is correct.
After this substitue the value of x =1 to find the value of y which is also 1.
So the nearest vertex can be 1,1. So the distance between origin and 1,1 is root 2 by pythagorus theorm.
Thanks.
@Neo2000 said:Folks - just wanted to give everybody here a heads-up - Once we move to the new forum, I will be closing this thread down. It's anyway gotten way too long.
Once we move to the new section, what I'd like you to do is create a thread for each problem that you want to discuss. The title should follow the format - "Source" "Type" "Question Number" "Misc information"
So thread titles will now look like "OG12 DS #247" or "TIME PS #7 Book5Pg38"
Why I am doing this -
In this thread alone there are a ton of good problems that most likely nobody is ever going to read because it's buried too deep. And that's a serious waste. The new format allows somebody to more efficiently use the tags to find a particular solution rather than re-posting the question.
As always - open to suggestions and discussion.
When is this going to happen???
Sorry wrong post.

@[124631:prashantdilse] it's actually going to be a little while longer than expected. Tags and Search aren't complete yet and I don't want to move into a new format without there being an easy way to get to the questions.

@[26975:Neo2000] Thank you...

Here is one question of Stats

Set X consists of different positive numbers arranged in ascending order:K,L,M,5,7. If K,L and M are consecutive integers, what is the arithmetic mean of set X?

1.) the product k*L*M is a multiple of 6
2.) There are at least 2 prime numbers among K,L and M

If sets X and Y have an equal number of elements, does set X have a greater standard deviation than set Y?


1.) The difference between each pair of the neighboring elements is consistent through out each set.

2.) each of the first two elements in Set y is twice greater than the corresponding first and second elements in Set y.

@[198102:vaibhavwadhera]..E

@vaibhavwadhera said: Here is one question of Stats
Set X consists of different positive numbers arranged in ascending order:K,L,M,5,7. If K,L and M are consecutive integers, what is the arithmetic mean of set X?
1.) the product k*L*M is a multiple of 6
2.) There are at least 2 prime numbers among K,L and M
answer is D

@vaibhavwadhera said: If sets X and Y have an equal number of elements, does set X have a greater standard deviation than set Y?
1.) The difference between each pair of the neighboring elements is consistent through out each set.
2.) each of the first two elements in Set y is twice greater than the corresponding first and second elements in Set y.
answer is A

@Neo2000 is this thread closed?

@[178529:sankalp.verma] the fact that you are able to post a reply should be answer enough no? :mg:

I didnt see many replies in this thread so I thought may be it has been closed. Didnt know that once thread is closed we can no longer post replies..now I know..

@Neo2000 said: Folks - just wanted to give everybody here a heads-up - Once we move to the new forum, I will be closing this thread down. It's anyway gotten way too long.Once we move to the new section, what I'd like you to do is create a thread for each problem that you want to discuss. The title should follow the format - "Source" "Type" "Question Number" "Misc information" So thread titles will now look like "OG12 DS #247" or "TIME PS #7 Book5Pg38"Why I am doing this - In this thread alone there are a ton of good problems that most likely nobody is ever going to read because it's buried too deep. And that's a serious waste. The new format allows somebody to more efficiently use the tags to find a particular solution rather than re-posting the question.As always - open to suggestions and discussion.
when planning to change ? and its a good idea..

A certain roller coaster has 3 cars, and a passenger is equally likely to ride in any 1 of the 3 cars each time that passenger rides the roller coaster. If a certain passenger is to ride the roller coaster 3 times, what is the probability that the passenger will ride in each of the 3 cars?

(A) 0 (B) 1/9 (C) 2/9 (D) 1/3 (E) 1

Though I got this one correct, I am looking for the most optimal/quickest method of solving this problem (and other similar poblems)

Five pieces of wood have an average length of 124 cms. and a median length of 140 cms. What is the maximum possible length, in cms., of the shortest piece of wood?

(A) 90 (B) 100 (C) 110 (D) 130 (E) 140

Came across this in one of the MGMATs :


Q) Car B starts at point X and moves clockwise around a circular track at a constant rate of 2 mph. Ten hours later, Car A leaves from point X and travels counter-clockwise around the same circular track at a constant rate of 3 mph. If the radius of the track is 10 miles, for how many hours will Car B have been traveling when the cars have passed each other for the first time and put another 12 miles between them (measured around the curve of the track)?
A) n4– 1.6
B) n4+ 8.4
C) n4+ 10.4
D) n2– 1.6
E) n2– 0.8

(n = Pi. Cant seem to figure how to include the Greek letter for it!)

Q) In a rectangular co-ordinate system, (Quadrants 1 to 4 goes anti-clockwise), which quadrant, if any, contains no point (x,y) that satisfies the inequality 2x-3y


a) none
b) Quadrant I
c) Quadrant II
d) Quadrant III
e) Quadrant IV