A merchant buys two articles for Rs.600. He sells one of them at a profit of 22% and the other at a loss of 8% and makes no profit or loss in the end. What is the selling price of the article that he sold at a loss?
A merchant buys two articles for Rs.600. He sells one of them at a profit of 22% and the other at a loss of 8% and makes no profit or loss in the end. What is the selling price of the article that he sold at a loss?
Rs. 404.80
Rs. 440
Rs. 536.80
Rs. 160
Answer: 440
a+b = 600 .92a+1.22b = 600 .22b = .08a a = 11b/4
b+11b/4 = 600 15b=600*4 b=160; a=440
Though i used the answer options directly to solve it.
A merchant buys two articles for Rs.600. He sells one of them at a profit of 22% and the other at a loss of 8% and makes no profit or loss in the end. What is the selling price of the article that he sold at a loss?
Rs. 404.80
Rs. 440
Rs. 536.80
Rs. 160
Answer: 440
a+b = 600 .92a+1.22b = 600 .22b = .08a a = 11b/4
b+11b/4 = 600 15b=600*4 b=160; a=440
Though i used the answer options directly to solve it.
dude, u need to find out the selling price...nt the cost price....
Oh my mistake.. didnt read the question properly. Its 404.8 :(
Of the 50 researchers, 40% are assigned to Team 1 and the rest are assigned to Team 2. However 70% prefer Team 1 and the rest prefer Team 2.What is the lowest possible number of people researchers who will not be assigned to the team they prefer? 15 17 20 25 30
Hi ! Can some one provide an easy way to solve this kind of problem ?
A certain portfolio consisted of 5 stocks, priced at $20, $35, $40, $45, and $70, respectively. On a given day, the price of one stock increased by 15%, while the price of another stock decreased by 35% and the prices of the remaining three remained constant. If the average price of a stock in the portfolio rose by approximately 2%, which of the following could be the prices of the shares that remained constant? (A) $20, $35, and $70 (B) $20, $45, and $70 (C) $20, $35, and $40 (D) $35, $40, and $70 (E) $35, $40, and $45
A circular rim 28 inches in diameter rotates the same number of inches per second as a circular rim 35 inches in diameter. If the smaller rim makes x revolutions per second, how many revolutions per minute does the larger rim make in terms of x?
Hi ! A certain portfolio consisted of 5 stocks, priced at $20, $35, $40, $45, and $70, respectively. On a given day, the price of one stock increased by 15%, while the price of another stock decreased by 35% and the prices of the remaining three remained constant. If the average price of a stock in the portfolio rose by approximately 2%, which of the following could be the prices of the shares that remained constant? (A) $20, $35, and $70 (B) $20, $45, and $70 (C) $20, $35, and $40 (D) $35, $40, and $70 (E) $35, $40, and $45
TIA
Note that the change is increase of only 15% in one stock (say x) and decrease of a huge 35% in another stock say y). Inspite of this, there is overall increase! Thus we need to find 2 numbers in the original 5 such that 35% of y is smaller than 15% of x - in other words x must be easily more than 2 times y....hence only possible are 20 and 70. The other 3 stocks would be unchanged. Hence (E) ~scrabbler
A circular rim 28 inches in diameter rotates the same number of inches per second as a circular rim 35 inches in diameter. If the smaller rim makes x revolutions per second, how many revolutions per minute does the larger rim make in terms of x?
48/x
75x
48x
24x
x/75 Please tell me the answer and explanation
The key point here: rotates same number of inches . So The number of revolutions done by rim1 & rim2 are equal.
X - revolutions by 1, Y= revolutions by 2
28 * x = 35 * y
So y is 4x/5 (unit - seconds). Mutliply by 60 to get in minutes. 48x
Oh my mistake.. didnt read the question properly. Its 404.8 :(
Of the 50 researchers, 40% are assigned to Team 1 and the rest are assigned to Team 2. However 70% prefer Team 1 and the rest prefer Team 2.What is the lowest possible number of people researchers who will not be assigned to the team they prefer? 15 17 20 25 30
The key point here: rotates same number of inches . So The number of revolutions done by rim1 & rim2 are equal.
X - revolutions by 1, Y= revolutions by 2
28 * x = 35 * y
So y is 4x/5 (unit - seconds). Mutliply by 60 to get in minutes. 48x
Got the answer correct till 4x/5 but didnt see this in options... later saw the explaination the units are different ... I need to be more carefule while reading problem.. If 4x/5 would have been an option, I am sure it would have been one wrong answer.
you can get in touch with me and we can talk more about it. feel free to call me during the day or to sms during the later part of the day
Hi Sid,
It is really nice of you to offer the service and I am sure a lot of people will take you up on this. However, please remove your phone number from the post as this is against forum rules. You can share it over PM (Private Message) when people contact you though.
If on coordinate plane (6,2) and (0,6) are the end points of the diagonal of a square, what is the distance between point (0,0) and the closest vertex of the square please explained me the answer.
If on coordinate plane (6,2) and (0,6) are the end points of the diagonal of a square, what is the distance between point (0,0) and the closest vertex of the square please explained me the answer.
1/sqrt 2 1 Root 2 Root 3 2root 3
The diagonal coordinates are 6,2 and 0,6. so these are 2 vertices. Now the mod point of the diagonal joining these vertices = 3,4 and equation of line perpendicular to the diagonal and passing through 3,4 is 2y=3x-1 We are finding this equation because we want to find out the other two vertices and these vertices will lie on the other diagonal. 2y=3x-1 is the equation of other diagonal.
Now the slope of this diagonal = 3/2 =>sin(theta) = 3/sqrt(13) cos(theta)=2/sqrt(13) Now diagonal length = d=2xsqrt(13) so other vertices will be given by x-coordinate of mid point +/- ((d/2) x cos(theta)) y-coordinate of mid point +/- ( (d/2) x sin(theta))
that gives points as (0,1) and (6,7) so nearest point is 0,1 and hence distance is 1 unit.
three dice are rolled simultaneously . What are the total no of ways in which the sum of the digits on the three dice is equal to 15.(Its not a probability problem).
three dice are rolled simultaneously . What are the total no of ways in which the sum of the digits on the three dice is equal to 15.(Its not a probability problem).
three dice are rolled simultaneously . What are the total no of ways in which the sum of the digits on the three dice is equal to 15.(Its not a probability problem).
The largest sum that 2 dice can have is 12. So, all 3 dice must have atleast 3 on their faces. Following are the possible cases:
Can u please help me out with this problem? A man invests rs.1395 in a 3% stock at rs.93. After holding the stock for a month, he sells rs.1000 worth of stock at rs.95 and the remaining at rs.80. What is the overall profit or loss in the above purchase and sale transaction? Options: a) rs.75 loss b) rs.15 loss c) rs.22 profit d) rs.45 loss