Please help me in these questions:
Q1. In a nationwide poll, N people were interviewed. If 1/4 of them answered "yes" to question 1, and of those, 1/3 answered "yes" to question 2, which of the following expressions represents the number of people interviewed who did not answer "yes" to both questions? ( Ans is 11N/12, but i am not able to get it)
Guys,
I have been breaking my head on this simple ques but somehow have not managed to match with the correct answer. Please help.
A bottle contains a mixture of two juices, apple and orange in the ratio 4:1. When 10 liters of the mixture is taken out and 10 liters of orange juice is poured into the bottle, the ratio becomes 2:3. How many liters of apple juice were contained in the bottle?
Ans : Apple juice = 16 in the original mixture.
N people
Let people who said Yes to Q1 be denoted by 1Y
Let people who said Yes to Q2 be denoted by 2Y
Let people who said No to Q1 be denoted by 1N
Let people who said No to Q2 be denoted by 2N
total N people
1Y= 1/4N
1Y & 2Y = (1/4)N*1/3 = (1/12)N
People who didnt say yes to both the questions would be
= N- People who said yes to both the questions
=N- (1/12)N
11/12N
HTH
~Lass
Please help me in these questions:
Q1. In a nationwide poll, N people were interviewed. If 1/4 of them answered "yes" to question 1, and of those, 1/3 answered "yes" to question 2, which of the following expressions represents the number of people interviewed who did not answer "yes" to both questions? ( Ans is 11N/12, but i am not able to get it)
Puys,
Just started my GMAT preps, have a couple of queries wrt Quant..
1) how do we find the square root of large numbers? Ex: 15250
2) Division is annoying me - need to spend a lot of time for a small silly result..is there any simple way to divide large numbers, decimals and get to know the quotients and remainders?
Mba2014
Need help can some give me solution for this question:
Q) At a loading dock, each worker on the night crew loaded 3/4 as many boxes as each worker on the day crew. In the night crew has 4/5 as many workers as the day crew, what fraction of all the boxes loaded by the two crews did the day crew load ?
Puys,
Just started my GMAT preps, have a couple of queries wrt Quant..
1) how do we find the square root of large numbers? Ex: 15250
2) Division is annoying me - need to spend a lot of time for a small silly result..is there any simple way to divide large numbers, decimals and get to know the quotients and remainders?
Mba2014
1) The GMAT will never explicitly ask you for square roots of such large numbers. For improving your speed and to enable you to make educated guesses, you can just remember the squares upto 20 and square roots of important numbers. That should be more than enough.
2) Generally on the GMAT, explicit, exact division might not be required. Approx values should be good enuf. For eg, 12.45/10.1, can be easily approximated to 12.5/10 , depending on the answer choices, if not, begin by makng the expression look a little less daunting, like, 124.5/101
Please post any specific questions that you faced problem with, hopefully other puys will be able to help you better.
Need help can some give me solution for this question:
Q) At a loading dock, each worker on the night crew loaded 3/4 as many boxes as each worker on the day crew. In the night crew has 4/5 as many workers as the day crew, what fraction of all the boxes loaded by the two crews did the day crew load ?
boxes per night crew= 3/4(boxes per day crew) => n1 = 3/4(n2)
no of night crew = 4/5(no of day crew) => c1 =4/5(c2)
Total boxes = n1c1+n2c2 = (3/4)n2 * (4/5)c2 + n2c2 = (3/5)n2c2 + n2c2
= (8/5)n2c2
Fraction reqd = loaded by day crew/Total = n2c2/ = 5/8
What part of this question did you not understand? This is a simple problem and you need to analyze what problem you faced so that it does not happen again.
Another fast solution could be to plug in numbers.
Take n2 = 4 and thus we get n1 = 3 (4 is taken to ease the value got after taking 3/4th )
Take c2 = 5 (for a similar reason as earlier), we get c1 = 4
Total = n1c1+n2c2 = (4*3)+(5*4) = 32
Reqd Fraction = n2c2/Total = 20/32 = 5/8
E, both are insufficient
Can anyone pls tell how to approach the sum using algebra method as well as picking numbers
Is a = b - c ?
(1) a + c not equal to b
(2) a
nairpraveenk SaysOops essa, unfortunately, ur analysis is wrong. Look @ mukul's post. He has given the wright solution. :)
ok
im gettin x=y on solving but not xy=0
can sumone explain ?? :/
Each of 435 bags contains at least one of the following three items: raisins, almonds, and
peanuts. The number of bags that contain only raisins is 10 times the number of bags that contain
only peanuts. The number of bags that contain only almonds is 20 times the number of bags that
contain only raisins and peanuts. The number of bags that contain only peanuts is one-fifth the
number of bags that contain only almonds. 210 bags contain almonds. How many bags contain
only one kind of item?
(A) 256
(B) 260
(C) 316
(D) 320
(E) It cannot be determined from the given information.
may i know the ans for it?
Each of 435 bags contains at least one of the following three items: raisins, almonds, and
peanuts. The number of bags that contain only raisins is 10 times the number of bags that contain
only peanuts. The number of bags that contain only almonds is 20 times the number of bags that
contain only raisins and peanuts. The number of bags that contain only peanuts is one-fifth the
number of bags that contain only almonds. 210 bags contain almonds. How many bags contain
only one kind of item?
(A) 256
(B) 260
(C) 316
(D) 320
(E) It cannot be determined from the given information.
may i know the ans for it?
Answer should be D->320
Use Venn Diagrams, post it as an attachment, we can discuss further.
Each of 435 bags contains at least one of the following three items: raisins, almonds, and
peanuts. The number of bags that contain only raisins is 10 times the number of bags that contain
only peanuts. The number of bags that contain only almonds is 20 times the number of bags that
contain only raisins and peanuts. The number of bags that contain only peanuts is one-fifth the
number of bags that contain only almonds. 210 bags contain almonds. How many bags contain
only one kind of item?
(A) 256
(B) 260
(C) 316
(D) 320
(E) It cannot be determined from the given information.
may i know the ans for it?
I solved it using Venn Diagrams and got 320 .Option D)320
-Deepak.
D is the only answer...Venn diagram made it simpler...
Ran into this one yesterday and was looking for some help.
I started with
For every positive even integer n, the function h(n) is defined to be the product of all the even integers from 2 to n inclusive. If p is the smallest prime factor of h(100)+1 then p is
1) Between 2 and 10
2) Between 10 and 20
3) Between 20 and 30
4) Between 30 and 40
5) Greater than 40
Answer is #5.
h(n) = 2.4.6........n Where n is even and there are n/2 terms
h(n) = 2^n/2 x (1.2.3..........n/2) Where n is even
Thus
h(100)+1 = 2^n/2 x (1.2.3.......50) +1
And did not know what to do further. Any pointers?
P.S. I also tried
h(2) + 1 = 3............thus p = 3
h(4) + 1 = 9............thus p = 3
h(6) + 1 = 49...........thus p = 7
h(8 ) + 1 = 385.........thus p = 5
I didn't see any pattern so I stopped.
Ran into this one yesterday and was looking for some help.
I started with
h(n) = 2.4.6........n Where n is even and there are n/2 terms
h(n) = 2^n/2 x (1.2.3..........n/2) Where n is even
Thus
h(100)+1 = 2^n/2 x (1.2.3.......50) +1
And did not know what to do further. Any pointers?
P.S. I also tried
h(2) + 1 = 3............thus p = 3
h(4) + 1 = 9............thus p = 3
h(6) + 1 = 49...........thus p = 7
h(8 ) + 1 = 385.........thus p = 5
I didn't see any pattern so I stopped.
Where'd you get the question from? The question doesnt make sense. Perhaps it should have said: "If p is the smallest prime factor of h(100)+1 then p is:".
h(100) = 2^50 * 50!
Now h(100) is divisible by every prime less than 50.
So h(100) + 1 will not be divisible by any of these primes.
We can say for sure, that least prime that divides 'h(100) + 1' will be greater than 50
So option 5 is correct.
Where'd you get the question from? The question doesnt make sense. Perhaps it should have said: "If p is the smallest prime factor of h(100)+1 then p is:".
h(100) = 2^50 * 50!
Now h(100) is divisible by every prime less than 50.
So h(100) + 1 will not be divisible by any of these primes.
We can say for sure, that least prime that divides 'h(100) + 1' will be greater than 50
So option 5 is correct.
Sorry. That was a typo. Corrected it in the original post.
The question is from the older version of GMAT prep.
Could you please elaborate on "If h(100) is divisible by every prime less than 50, h(100) + 1 not be divisible by any prime less than 50" ?
Sorry. That was a typo. Corrected it in the original post.
The question is from the older version of GMAT prep.
Could you please elaborate on "If h(100) is divisible by every prime less than 50, h(100) + 1 not be divisible by any prime less than 50" ?
Well, if any no. 'n' is divisible by another no. 'd', then 'n+1' wont be divisible by d.
I mean, if n leaves 0 remainder when divided by d, then 'n+1' wont leave 0 remainder with d. (it'l leave remainder 1)
So same way, since we know that h(100), which comprises all primes less than 50, is divisible by all primes less than 50, h(100)+1 wont be divisible by those same primes.
So that does the trick 😃
Where'd you get the question from? The question doesnt make sense. Perhaps it should have said: "If p is the smallest prime factor of h(100)+1 then p is:".
h(100) = 2^50 * 50!
Now h(100) is divisible by every prime less than 50.
So h(100) + 1 will not be divisible by any of these primes.
We can say for sure, that least prime that divides 'h(100) + 1' will be greater than 50
So option 5 is correct.
I just solved GMAT prep and th same problem was there...couldn't get how to tackel...
n is multiple of 5. n=(p^2 )q ..p and q are prime num..which is multiple of 25
1.p^2
2.q^2
3. p * q^2
4. (p^2) * (q^2)
5. (p^3) * q
ans:4
On 1 jully, the total number of employee decreased by 10%. Without any change in the remaining employees, the avg employee salary was 10% more after the decrease in number of employees that before decrease. The total of all combined salary of all employees after 1 jully was what percent of that before 1jully
1. 90%
2.99%
3.100%
4. 101 %
5. 110%
ans:2