Guys,
I have been breaking my head on this simple ques but somehow have not managed to match with the correct answer. Please help.
A bottle contains a mixture of two juices, apple and orange in the ratio 4:1. When 10 liters of the mixture is taken out and 10 liters of orange juice is poured into the bottle, the ratio becomes 2:3. How many liters of apple juice were contained in the bottle?
In a family, there is a mother, a father, 2 daughters and a son. The family is planning to go for a picnic. They decide to travel in their new car.The car has 2 seats in the front and 3 seats in the back.The car should be driven either by the dad or the mother.The two daughters should never sit together.How many ways can this arrangement be done?
Regards,
Sabby :)
ANS = (No of ways with no restriction) - (No of ways in which daughters sit together)
Driving seat can b taken in 2 ways.
Assume there is no restriction, total no of ways in which family can be seated :
2* 4!= 48
Seats A B
C D E
i) Now 2 daughters always sit together, (only back seat) in 2 ways.- say in CD
Drivers seat (B) = 2 ways (M or F)
son and other parent can sit in 2 ways.
That means 2*2*2= 8 ways
ii) Again daughters can sit in DE. So for this scenario, 8 possible ways.
Hence total ways daughter can sit toghter = 8+8= 16
Ans= 48-16= 32
Hope this explains!!
PS: its so easy to solve this problem, but so difficult to put down the reasoning, with diagram!! 😐
Guys,
I have been breaking my head on this simple ques but somehow have not managed to match with the correct answer. Please help.
A bottle contains a mixture of two juices, apple and orange in the ratio 4:1. When 10 liters of the mixture is taken out and 10 liters of orange juice is poured into the bottle, the ratio becomes 2:3. How many liters of apple juice were contained in the bottle?
Easier to work on this question with options.
I just took 2 numbers- multiples of 5- 15, 20.
Assume total juice= 20 lit, 10 taken out, 10 remain in ratio 4:1 i.e 8 apple and 2 orange.
10 lit orange added, now it becomes 8 apples and 12 orange->> ratio 2:3
so apple juice contained= 16 lit.
Easier to work on this question with options.
I just took 2 numbers- multiples of 5- 15, 20.
Assume total juice= 20 lit, 10 taken out, 10 remain in ratio 4:1 i.e 8 apple and 2 orange.
10 lit orange added, now it becomes 8 apples and 12 orange->> ratio 2:3
so apple juice contained= 16 lit.
Can that be solved using variables? What made you choose 20 to start with? Why not some other multiple of 5 (30, 35, 40)?
JRP4MBA SaysCan that be solved using variables? What made you choose 20 to start with? Why not some other multiple of 5 (30, 35, 40)?
I didnt take 5 or 10 because 10 lit. were to be withdrawn later. I started with 15. It didnt work. then thought of trying 20 and told myself that if 25 too doesnt work, i will not solve this problem.
I said earlier, working with options is way easier than algebraic approach.
JRP4MBA SaysCan that be solved using variables? What made you choose 20 to start with? Why not some other multiple of 5 (30, 35, 40)?
Okay heres another way for equation lovers!
A and O
4x and x
4x-8 and x-2 (10 lit withdrawn will be proportionate)
4x-8 and x-2+10 (10 lit orange added)
Hence 4x-8: x+8 = 2:3
Solve for x, x= 4
Apple juice= 4x=16 lit.
HTH
Puys..need ur help in this..
On a certain road, 10% of the motorists exceed the posted speed limit and receive speeding tickets,but 20% of the motorists who exceed the posted spped limit do not receive speeding tickets.What percent of the motorists on the road exceed the posted speed limit?
1) (21/2)%
2) 15%
3) 30%
4) (25/2)%
5) 22%
I got this in GMATPrep Mock..
Regards,
Sabby
My take 30%
Please confirm OA
Puys..need ur help in this..
On a certain road, 10% of the motorists exceed the posted speed limit and receive speeding tickets,but 20% of the motorists who exceed the posted spped limit do not receive speeding tickets.What percent of the motorists on the road exceed the posted speed limit?
1) (21/2)%
2) 15%
3) 30%
4) (25/2)%
5) 22%
I got this in GMATPrep Mock..
Regards,
Sabby
One more..
This one is easy...
3 grades of milk are 1%, 2% and 3% fat by volume.If "X" gallons of 1% grade, "Y" gallons of 3% grade and "Z" gallons of 3% grade are mixed to give (X+Y+Z) gallons of 1.5% grade,What is "X" in terms of "Y" and "Z"?
1) y + 3z
2) (y+z)/4
3) 2y+3z
4) 3y+z
5)3y+4.5z
Regards,
Sabby
sausi007 SaysDamadol to mera bhi chal raha hai 😞 But my date is on 6th Sept, keeping my fingers crossed.....
Same Date
Puys..need ur help in this..
On a certain road, 10% of the motorists exceed the posted speed limit and receive speeding tickets,but 20% of the motorists who exceed the posted spped limit do not receive speeding tickets.What percent of the motorists on the road exceed the posted speed limit?
1) (21/2)%
2) 15%
3) 30%
4) (25/2)%
5) 22%
I got this in GMATPrep Mock..
Regards,
Sabby
I think the answer is (4) (25/2)%
Let Total motorists be T, Let the motorists who exceed the speed limit be X,
we need to find (X/T)*100
From first sentence,
Motorists who exceed and recieve tickets = (10/100)T
From Second Sentence, Motorists who exceed but dont recieve tickets = (20/100)X
Another way to interpret this sentence will be,
Motorists who exceed and recieve tickets = (80/100)X, since 20% do not recieve tickets, the remaining 80% should recieve tickets
Thus, (10/100)T = (80/100)X
X/T = 1/8, or (25/2)%
One more..
This one is easy...
3 grades of milk are 1%, 2% and 3% fat by volume.If "X" gallons of 1% grade, "Y" gallons of 3% grade and "Z" gallons of 3% grade are mixed to give (X+Y+Z) gallons of 1.5% grade,What is "X" in terms of "Y" and "Z"?
1) y + 3z
2) (y+z)/4
3) 2y+3z
4) 3y+z
5)3y+4.5z
Regards,
Sabby
Ans. 1) X=Y+3Z
One more..
This one is easy...
3 grades of milk are 1%, 2% and 3% fat by volume.If "X" gallons of 1% grade, "Y" gallons of 3% grade and "Z" gallons of 3% grade are mixed to give (X+Y+Z) gallons of 1.5% grade,What is "X" in terms of "Y" and "Z"?
1) y + 3z
2) (y+z)/4
3) 2y+3z
4) 3y+z
5)3y+4.5z
Regards,
Sabby
Yup, this was simple indeed !
Just the 3% for Y should be 2% actually.
x+2y+3z = 1.5(x+y+z)
x = (4y-3y) + (6z-3z)
x = y+3z, (1)
If n is a positive number and f(n) = 2x3x4...xn, what is the lowest prime factor of f(100) + 1?
Puys..need ur help in this..
On a certain road, 10% of the motorists exceed the posted speed limit and receive speeding tickets,but 20% of the motorists who exceed the posted spped limit do not receive speeding tickets.What percent of the motorists on the road exceed the posted speed limit?
1) (21/2)%
2) 15%
3) 30%
4) (25/2)%
5) 22%
I got this in GMATPrep Mock..
Regards,
Sabby
(25/2)%
Easier to solve by building a table as follows. Let the total be 100
Exceeded Did Not Exceed Total
Tickets 10
No Tickets 0.2x
Total x 100
10+0.2x=x => 10=0.8x => x=10/0.8=80/10=25/2 (Answer)
If n is a positive number and f(n) = 2x3x4...xn, what is the lowest prime factor of f(100) + 1?
Is this a GMAT question? Could you tell the source of the question?
f(100) + 1 = 100! + 1
100! is divisible by all primes less than 100.
So 100! + 1 could be div only by primes > 100
But we neednt look too far.
100!mod101 = -1
So (100!+1)mod101 = 0
So the least prime that divides 100! + 1 = 101
Is this a GMAT question? Could you tell the source of the question?
f(100) + 1 = 100! + 1
100! is divisible by all primes less than 100.
So 100! + 1 could be div only by primes > 100
But we neednt look too far.
100!mod101 = -1
So (100!+1)mod101 = 0
So the least prime that divides 100! + 1 = 101
I got this in the GMATPrep S/w... Thanks for the answer though!
Zoheb Haider SaysI got this in the GMATPrep S/w... Thanks for the answer though!
I just noticed this one, this question is NOT from GMATPrep,
that question goes something like this:
f(n) = 2*4*6*8......*n, the least prime factor, P for f(100)+1, could be,
(options are the KEY to this question, i remember the options exactly),
A) Between 2 & 10
B) Between 10 & 20
C) Between 20 & 30
D) Between 30 & 40
E) >40
@Zoheb : Please post the Exact Question, the one that you posted is totally different and way off for GMAT, although, food for thought, it might be !
I just noticed this one, this question is NOT from GMATPrep,
that question goes something like this:
f(n) = 2*4*6*8......*n, the least prime factor, P for f(100)+1, could be,
(options are the KEY to this question, i remember the options exactly),
A) Between 2 & 10
B) Between 10 & 20
C) Between 20 & 30
D) Between 30 & 40
E) >40
@Zoheb : Please post the Exact Question, the one that you posted is totally different and way off for GMAT, although, food for thought, it might be !
This seems more like it.
With same logic here as well, we can say that least prime will be > 50
So option E 😃
