I have been an avid follower of this thread on PG: Now, I have doubts on some questions which I am not sure of. So, here are the questions:
1. A hospital pharmacy charges $0.40 per fluidram of a certain medicine but allows a discount of 15 percent to Medicare patients. How much should the pharmacy charge a Medicare patient for 3 fluidounces of the medicine?(128 fluidrams = 16 fluidounces)
Surcharge as ______________4%_________3% a Percent of Price
Installation Charge _________$82.50______$93
2. The table above shows the various charges made by two companies for the same air conditioner. What is the total amount that can be saved on the purchase and installation of the air conditioner by dealing with the company that offers the lower total charge?
(A) $41.60 (B) $45.00 (C) $50.75 (D) $55.75 (E) $61.25 I suspected this question to be wrong, just wanted to confirm
3. According to the graph above, when x = 3, y most nearly ? (A) 1 (B) -1/2 (C) 0 (D) 1/2 (E) 1 (Refer the diagram attached for this question) By looking at the diagram, you can kind of guess,I guessed wrong (1/2). But can someone give a proper explanation using parabolic equation x^2 = 4aY + c
4. Pat will walk from intersection X to intersection Y along a route that is confined to the square grid of four streets and three avenues shown in the map above. How many routes from X to Y can Pat take that have the minimum possible length? (A) 6 (B) 8 (C) 10 (D) 14 (E) 16 (Refer the diagram attached for this question)
5. A wildlife preserve is being planned for 3,000 rhinoceroses. The preserve is to contain a total of 10,000 acres of watering area, plus 100 acres of grazing area for each rhinoceros. If the number of rhinoceroses is expected to increase by 10 percent, how many thousand acres should the preserve have in order to provide for the increased population?
I kind of figured out the last question: It asks for the number of acres in thousands. Also it asks for the total number of acres required for both the new and the old rhinoceros. Now, here 10,000 is static. and 100 acres/rhino is dynamic. 10% increase is 300 rhinos more. So, total number of acres in thousand = 10k+3300*100 = 10k + 330k= 340k. Hence the answer....
So, the first 25% of the numbers are less than 2(because this list will also contain the lowest numbers in the range). Then, 35% of the numbers are 4 and above meaning the last 35% of the numbers are 4 or above(this would cntain the highest numbers in the range).
The middle 25%-65% would consist of numbers greater than 2 and less than 4 = 3
Hence, 3 would be the median
Hi chintamani.kurs, i guess something wrong with your explanation. Question gives data different than u interpreted.
(1) 25 percent of the projects in the company have 4 or more employees assigned to each project. (2) 35 percent of the projects at company have 2 or less employees assigned to each project.
In this situation, remaining 40% could be in between 2 and 4 or higher than 4 or exactly 1. If 40% projects have more than 5 persons then median could be 4. Answer should be E. Please correct me if i am wrong in my line of reasoning.
(1) 25 percent of the projects in the company have 4 or more employees assigned to each project. (2) 35 percent of the projects at company have 2 or less employees assigned to each project.
I had some difficulty in understanding the below problem .It is from OG 12 from the diagnostic test Problem 11
Of the 3 digit integers greater than 700 how many have 2 digits that are equal to each other and the remaning digit different from the other two
a 90 b 82 c 80 d 45 e 36
The answer is option C, the best way to solve such problems (if you did not understand the logic in the answer) is to go ahead manually. Starting from 707,711,717 onwards you can identify how many such occurences occur tiill 769, then add 770,771,772 etc (without 777) till 799, and then simply multiply by 3 (turns out to be 26*3=7 (multiplied by 3 because we have to find for 800-999) and then add 2 more, viz. 800 and 900. So you get 80 as the answer in the end.
A bus from city M is traveling to city N at a constant speed while another bus is making the same journey in the opposite direction at the same constant speed. They meet in point P after driving for 2 hours. The following day the buses do the same trip again at the same constant speed. One bus is delayed 24 minutes and the other leaves 36 minutes earlier. If they meet 24 miles from point P, what is the distance between the two cities? A. 48 B. 72 C. 96 D. 120 E. 192
A bus from city M is traveling to city N at a constant speed while another bus is making the same journey in the opposite direction at the same constant speed. They meet in point P after driving for 2 hours. The following day the buses do the same trip again at the same constant speed. One bus is delayed 24 minutes and the other leaves 36 minutes earlier. If they meet 24 miles from point P, what is the distance between the two cities? A. 48 B. 72 C. 96 D. 120 E. 192
A bus from city M is traveling to city N at a constant speed while another bus is making the same journey in the opposite direction at the same constant speed. They meet in point P after driving for 2 hours. The following day the buses do the same trip again at the same constant speed. One bus is delayed 24 minutes and the other leaves 36 minutes earlier. If they meet 24 miles from point P, what is the distance between the two cities? A. 48 B. 72 C. 96 D. 120 E. 192
Since they are travelling at same speed, and they meet after two hours, they take four hours to reach their destincation.
One leaves 24 minutes late, and the other 36 minutes early. One of the bus has travelled for one hour before the other starts. That means, the distance between them is only 3/4 the distance. Hence, the distance from one of the cities = 1/2*3/4=3/8. 1/2-3/8 = 1/8 th of the total distance = 24 miles Hence total distance = 192 miles. (E)
Since they are travelling at same speed, and they meet after two hours, they take four hours to reach their destincation.
One leaves 24 minutes late, and the other 36 minutes early. One of the bus has travelled for one hour before the other starts. That means, the distance between them is only 3/4 the distance. Hence, the distance from one of the cities = 1/2*3/4=3/8. 1/2-3/8 = 1/8 th of the total distance = 24 miles Hence total distance = 192 miles. (E)
How can you estimate for sure that by getting a head start of 1 hour the distance is 3/4th of the actual distance ?? won't that depend on the speed of the buses ?? For eg. if a bus is going at 32mph it will have covered only 1/6th of the distance in that 1 hour .. please correct me if i am wrong.
Sorry for posting it 3 times.. the page was not getting saved :P
answer is E. It happens in quant, so i started working for quant regularly now... here is another good one: A cook went to a market to buy some eggs and paid $12. But since the eggs were quite small, he talked the seller into adding two more eggs, free of charge. As the two eggs were added, the price per dozen went down by a dollar. How many eggs did the cook bring home from the market? A. 8 B. 12 C. 15 D. 16 E. 18
answer is E. It happens in quant, so i started working for quant regularly now... here is another good one: A cook went to a market to buy some eggs and paid $12. But since the eggs were quite small, he talked the seller into adding two more eggs, free of charge. As the two eggs were added, the price per dozen went down by a dollar. How many eggs did the cook bring home from the market? A. 8 B. 12 C. 15 D. 16 E. 18
Since they are travelling at same speed, and they meet after two hours, they take four hours to reach their destincation.
One leaves 24 minutes late, and the other 36 minutes early. One of the bus has travelled for one hour before the other starts. That means, the distance between them is only 3/4 the distance. Hence, the distance from one of the cities = 1/2*3/4=3/8. 1/2-3/8 = 1/8 th of the total distance = 24 miles Hence total distance = 192 miles. (E)
How can you estimate for sure that by getting a head start of 1 hour the distance is 3/4th of the actual distance ?? won't that depend on the speed of the buses ?? For eg. if a bus is going at 32mph it will have covered only 1/6th of the distance in that 1 hour .. please correct me if i am wrong.
Because it is mentioned in the question that they are moving at same speeds
However, i plugged in the answers choices to get the answer. Is there another way?
Option E
The cook brought back 18 eggs. Therefore, he/she paid Rs.12 for 16 eggs.
Rate of a dozen eggs: I. (12*12)/18 = 8 II. (12*12)/16 = 9
There is a way, the price decreased by 1 for a dozen. So the price decrease per egg = $(1/12)
Also, since he paid 12 for x eggs, and got x+2 eggs, the equation would be => 12/x-12/(x+2)=1/12 =>24/(x(x+2)) = 1/12 => x(x+2) = 12 * 24 => x(x+2) = 288 Straight forward quadratic equation, x= 16 So he brought home 18 eggs
At a blind taste competition a contestant is offered 3 cups of each of the 3 samples of tea in a random arrangement of 9 marked cups. If each contestant tastes 4 different cups of tea, what is the probability that a contestant does not taste all of the samples?
At a blind taste competition a contestant is offered 3 cups of each of the 3 samples of tea in a random arrangement of 9 marked cups. If each contestant tastes 4 different cups of tea, what is the probability that a contestant does not taste all of the samples?
A.
B.
C.
D.
E.
B. 5/14 This would be my answer, details will post later.
At a blind taste competition a contestant is offered 3 cups of each of the 3 samples of tea in a random arrangement of 9 marked cups. If each contestant tastes 4 different cups of tea, what is the probability that a contestant does not taste all of the samples?
A.
B.
C.
D.
E.
My answer would also be 5/14.. Here is the approach I used. Total Possiblities = 9C4 = 126 No. of Possiblities applicable = 3C2(3C3*3C1*2 +3C2*3C2) = 45 Probability = 45/126 = 5/14.. What is the OA?
(multiplied by 3 because we have to find for 800-999) and then add 2 more, viz. 800 and 900. So you get 80 as the answer in the end.