This thread is dedicated to the geometry for CAT 2014
This thread is dedicated to the geometry for CAT 2014
Any one guide me in this question , i tried solving , but i feel my reasoning is absurd .
Quant LOD II from Arun sharma Geometry :
If a circle is provided with a measure of 19 degree on centre , is it possible to divide the circle into 360 equal parts ?
My reasoning :
The area of a sector is ( theta / 360 ) * pi*r^2
theta = 19 here .
[ ( 19/360 )*(22/7)*r^2 ] * 360 = (pi*r^2) : The question implies this
This gives rise to the fact that
r = ( 7/19*22) ^ 1/2.
This must be definitely very much less than 1 , such a small circle is not possible 😃 atleast according to me .:D
The options given in arun sharma :
a) never
b) Possible when one more measure of 20 is given.
c) always
d) Possible if one more measure 21 is given
e) none of these .
The answer given was c) - > always .
Can someone explain this to me .?Was my reasoning wrong .?
Any one guide me in this question , i tried solving , but i feel my reasoning is absurd .Quant LOD II from Arun sharma Geometry :If a circle is provided with a measure of 19 degree on centre , is it possible to divide the circle into 360 equal parts ? My reasoning : The area of a sector is ( theta / 360 ) * pi*r^2 theta = 19 here .[ ( 19/360 )*(22/7)*r^2 ] * 360 = (pi*r^2) : The question implies this This gives rise to the fact that r = ( 7/19*22) ^ 1/2.This must be definitely very much less than 1 , such a small circle is not possible atleast according to me .:DThe options given in arun sharma :a) never b) Possible when one more measure of 20 is given.c) always d) Possible if one more measure 21 is givene) none of these .The answer given was c) - > always . Can someone explain this to me .?Was my reasoning wrong .?
how did u get that equation and are these pieces in the form of slices or any shape??
Any one guide me in this question , i tried solving , but i feel my reasoning is absurd .Quant LOD II from Arun sharma Geometry :If a circle is provided with a measure of 19 degree on centre , is it possible to divide the circle into 360 equal parts ? My reasoning : The area of a sector is ( theta / 360 ) * pi*r^2 theta = 19 here .[ ( 19/360 )*(22/7)*r^2 ] * 360 = (pi*r^2) : The question implies this This gives rise to the fact that r = ( 7/19*22) ^ 1/2.This must be definitely very much less than 1 , such a small circle is not possible atleast according to me .:DThe options given in arun sharma :a) never b) Possible when one more measure of 20 is given.c) always d) Possible if one more measure 21 is givene) none of these .The answer given was c) - > always . Can someone explain this t
And I think a circle can always be divided in to 360 equal parts because angle to the centre is 360 degree so we can always divide it.
how did u get that equation and are these pieces in the form of slices or any shape??
That is because they have mentioned that circle is provided with 19 degree at the centre , meaning there is a sector with 19 degree right . I interpreted it as they have asked about whether a circle can be divided into 360 equal parts when each part subtends 19 degree ...
ABC is a triangle and 0 is the point of intersection of its medians, then
a) 3 (AB2 + BC2 +CA2) = 4 (OA2+OB2+OC2)
b) 4 (AB2 + BC2 + CA2) = 3 (OA2 +OB2+OC2)
c) (AB2 + BC2 + CA2 ) ^ ½ = 3 ( OA2 + OB2 + OC2 ) ^ ½
d) AB2 + BC2 + CA2 = 3 ( OA2 + OB2 + OC2 )
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In the figure given below, quadrilateral ABCD is divided into six smaller triangles. The area of each of the smaller triangles is mentioned inside it. If DE : EC = 4 : 5, then find the value of x.
http://www.careerlauncher.com/LSTQuestionImg/772095/300838/5q.jpg
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