CGL 2012 Tier 2 Preparations and Results

Staff Selection Commission (SSC) SSC - CGL
1911
@sscjindabad said:
20
logic dena yar!!
1912
@Brooklyn said:
logic dena yar!! solve for x
bhai
(100*16)/1/6=x*80/6/7
1913
@ssc-cgle said:
Much/many 1. How ______ people are you expecting?
2. How ______ money do you want for this?
3. I don't see ______ point in continuing. We're all very tired.
4. Thank you so ______ for your help.
5. We don't stock these. We don't get ______ demand for them. 6. We need some paper.How ______ do we need? 7. How ______ fruit do you eat in an average week?
bhai last ka answer batao...
1914
There are three circles touching each other externally with equal radii. There are two circles C1 and C2 drawn with C1 passing thru the centre of these circles and C2 passing thru the point of contact. What is the ratio of the area of circles C1 and C2?
1915
@sscjindabad said:
bhai
(100*16)/1/6=x*80/6/7
ye ky a kiya /?? didnt get u at all !!
1916
@sscjindabad said:
bhai last ka answer batao...
last ka 'much' lag rha hai
1917
@JS-M said:
1. many
2. Much
3. Much
4. Much
5. Much
6. Much
7. Much............
all correct
1918
@JS-M said: There are three circles touching each other externally with equal radii. There are two circles C1 and C2 drawn with C1 passing thru the centre of these circles and C2 passing thru the point of contact. What is the ratio of the area of circles C1 and C2?
4:1
1919
@mickym said:
4:1
logic?
1920
@Brooklyn said:
logic?
yr ratio of sqrs of circumradius & inradius of the equilateral triangle formed after joining the centres of 3 circles
1921
@sscjindabad said:
20
explain dis too
1922
@mickym said:
20
isko bhi plz explain ...
1923
In a parallelogram ABCD, the bisector of angle ABC intersects AD at a point M. IF MD = 5 cm, BM = 6 cm and CM = 6 cm, then the length of AB(in cm) is
(a) 4 (b) 4.5 (c) 6 (d) 7.5
1924
@JS-M said: In a parallelogram ABCD, the bisector of angle ABC intersects AD at a point M. IF MD = 5 cm, BM = 6 cm and CM = 6 cm, then the length of AB(in cm) is(a) 4 (b) 4.5 (c) 6 (d) 7.5
4
1925
@Brooklyn said:
isko bhi plz explain ...
Bro kindly post the ques.......sirf Ans se yaad rakhna mushkil hai
1926
@mickym : dis one

A contractor engaged 100 labourers for a construction work to be completed in 96 days. But only 1/7 of the work was done in 1/6th of the schedule time. the additional number of labourers that will be required to complete the work in time, is??
1927
@Brooklyn said:
@mickym : dis one
A contractor engaged 100 labourers for a construction work to be completed in 96 days. But only 1/7 of the work was done in 1/6th of the schedule time. the additional number of labourers that will be required to complete the work in time, is??
bro
1/7 work done by 100 labrs in 16 days
6/7 work left , days left = 80

so extra labrs = (100 *16 * 6/7 * 7 )/80= 120
extra 20 labrs
1928
@mickym said:
4
.......share approach pls
1929
@mickym said:
bro
1/7 work done by 100 labrs in 16 days
6/7 work left , days left = 80
so extra labrs = (100 *16 * 6/7 * 7 )/80= 120
extra 20 labrs
thnx got my error!!
1930
@JS-M said:
.......share approach pls
bro fig banane ke baad
apply similar traingle concept in ABM & BMC
u will get the ans